máy tính dâu sao ko lấy ra

Ta có A:B=1.5.6:1:3:5=2

=1 nha bn

bạn giải cách làm ra nha mk cần gấp lắm nhanh lên ......

A=1+(1/6+1/12+1/20+...+1/90):2

A=1+(1/2-1/3+1/3-1/4+1/4-1/5+...+1/9-1/10):2

A=1+(1/2-1/10):2

A=1+2/5:2

A=1+1/5

A=6/5

Vậy A=6/5 nha bạn 

Đúng 100%

k mk nha

Mk nhanh nhất

thừa 1 số 1/45 nha !!

\(A=1+\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+..+\frac{1}{90}\right):2\)

\(A=1+\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right):2\)

\(A=1+\left(\frac{1}{2}-\frac{1}{10}\right):2\)

\(A=1+\frac{2}{5}:2=1+\frac{1}{5}=\frac{6}{5}\)

vậy...

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\frac{1}{45}\)

\(=\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+...+\frac{2}{90}\)

\(=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}+...+\frac{2}{9.10}\)

\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+..+\frac{1}{9}-\frac{1}{10}\right)\)

\(=2.\left(\frac{1}{2}-\frac{1}{10}\right)\)

\(=2.\frac{2}{5}=\frac{4}{5}\)

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\frac{1}{45}\)

\(=\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+...+\frac{2}{90}\)

\(=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}+...+\frac{2}{9.10}\)

\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=2.\left(\frac{1}{2}-\frac{1}{10}\right)\)

\(=\frac{4}{5}\)

\(\frac{1}{3}\)+\(\frac{1}{6}\)+\(\frac{1}{10}\)+\(\frac{1}{15}\)+........+\(\frac{1}{45}\)

=\(\frac{2}{6}\)+\(\frac{2}{12}\)+\(\frac{2}{20}\)+\(\frac{2}{30}\)+..........+\(\frac{2}{90}\)

=\(\frac{2}{2.3}\)+\(\frac{2}{3.4}\)+\(\frac{2}{4.5}\)+\(\frac{2}{5.6}\)+...........+\(\frac{2}{9.10}\)

=2.(\(\frac{1}{2.3}\)+\(\frac{1}{3.4}\)+\(\frac{1}{4.5}\)+\(\frac{1}{5.6}\)+.........+\(\frac{1}{9.10}\))

=2.(\(\frac{1}{2}\)-\(\frac{1}{3}\)+\(\frac{1}{3}\)-\(\frac{1}{4}\)+\(\frac{1}{4}\)-\(\frac{1}{5}\)+\(\frac{1}{5}\)-\(\frac{1}{6}\)+.......+\(\frac{1}{9}\)-\(\frac{1}{10}\))

=2.(\(\frac{1}{2}\)-\(\frac{1}{10}\))

=2.\(\frac{2}{5}\)

=\(\frac{4}{5}\)

Còn cái nịt

a) 1/3 + 1/6 + 1/10 + 1/15 + ... + 1/45

= 2 x (1/6 + 1/12+ 1/20 + ... + 1/90)

= 2 x (1/2x3 + 1/3x4 + 1/4x5 + ... + 1/9x10)

= 2 x (1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + ... +1/9 - 1/10)

= 2 x (1/2 - 1/10)

= 2 x 2/5

= 4/5

\(a,\frac{1}{2}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\frac{1}{45}\)

\(=2.\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)

\(=2.\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)

\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=2.\left(\frac{1}{2}-\frac{1}{10}\right)\)

\(=2.\frac{2}{5}\)

\(=\frac{4}{5}\)

b, Từ 1,3 đến 43,1 có :(43,1-1,3):1,9+1=23 số 

Từ 1,3 đến 42,1 có 22 số 

Mà (1,3-3,2)+(5,1-7)+(8,9-10,8)+........

Ta có 

22:2=11 ( cặp)

Mà giá trị của 1 cặp là -1,9

 => Tổng của 11 cặp là 

-1,9.11=-20,9

Vậy tổng dãy số trên là 

43,1-20,9=22,2