Tim so nguyen x biet
x + (x + 1) + (x + 2) + ... + (x + 30) = 1240
tim x thuoc z ,biet x+(x+1)+(x+2) +...+(x+30)=1240
có x+(x+1)+(x+2)+....+(x+30) = 1240
x+x+1+x+2+......+x+30 = 1240
(x+x+x+...+x) + ( 1+ 2+....+30) = 1240
31 số x
31.x + ( 30 +1) . 30 : 2 = 1240
31.x + 465 = 1240
31.x = 1240 - 465
31.x = 775
x = 775 :31
x= 25
Vậy x=25
Tim x,bietx/1×2+x/2×3+x/3×4+...+x/2006×2007=2006/2007
\(x-\frac{x}{2}+\frac{x}{2}-\frac{x}{3}+...+\frac{x}{2006}-\frac{x}{2007}=\frac{2006}{2007}\)
\(x-\frac{x}{2007}=\frac{2006}{2007}\)
\(\frac{2007x-x}{2007}=\frac{2006}{2007}\)
\(\frac{2006x}{2007}=\frac{2006}{2007}\Rightarrow2006x=2006\)
=>x=1
Tim x thuoc stn
a, x + ( x +1) + ( x + 2 )+........+ (x +30)+1240
b,1+2+3 + ........ + x+210
a,x+(x+1)+(x+2)+...+(x+30)=1240
<=>31x+(30+1).30:2=1240
<=>31x+465=1240
<=>31x=775
<=>x=25
b,1+2+3+....+x=210
=>x(x+1):2=210
<=>x(x+1)=420=20.21
=>x=20
Nếu thấy mình làm đúng thì tick nha bạn,cảm ơn.
tim x thuoc N biet
x+(x+1)+(x+2)+(x+3)+.......+(x+30)=1240
1+2+3+.....+x=210
x+(x+1)+(x+2)+(x+3)+.......+(x+30)=1240
\(\Leftrightarrow\left(x+x+x.+...x\right)+\left(1+2+3...+30\right)=1240\)
\(\Rightarrow30x+465=1240\)
\(\Rightarrow30x=1240-465=775\)
\(\Rightarrow30x=775\)
\(V\text{ậy}x=\frac{155}{6}\)
1+2+3+.....+x=210
\(\left(1+x\right).x=210\)
\(\Rightarrow x=14\)
x+(x+1)+(x+2)+...+(x+30)=1240
=>x+x+1+x+2+...+x+30=1240
=>(x+x+x+...+x)+(1+2+...+30)=1240
=>31x+[(30-1):1+1] . (30+1) :2=1240
=>31x+30.31:2=1240
=>31x+15.31=1240
=>31(x+15)=1240
=>x+15=1240:31=40
=>x=40-15=25
1+2+3+...+x=210
=>[(x-1):1+1]. (x+1) : 2= 210
=>x.(x+1):2=210
=>x(x+1)=210.2=420
=>x(x+1)=20.21
=>x=20
Cho ham so y=y (x)=2x-0,3
Tinh f(1) f(-0;2)
Tim 2 so xy bietx/3=y/7va x+y=120 do
tim X thuon N ,biet :
a,x+(x+1)+(x+2)+........+(x+30)=1240
b, 1+2+3+4+........+ x =210
a) x + (x + 1) + (x + 2) + ..... + (x + 30) = 1240
31x + 30.31:2 = 1240
31x + 465 = 1240
31x = 775
x = 25
b) 1 + 2 +3 +..... + x = 210
1 + 2 + 3 + ....+x = x.(x+1)/2 = 210
x(x + 1) = 420 = 20.21
Vậy x = 20
+Tim x thuoc N, biet :
a/ x+(x+1)+(x+2)+....+(x+30)=1240
b/1+2+3+........+x=210
a) x + ( x+1 ) + ( x+2 ) + ... + ( x+30 ) = 1240
x + x + 1 + x + 2 + ... + x + 30 = 1240
( x + x + x + ... + x ) + ( 1 + 2 + ... + 30 ) = 1240
x.[( 30 - 0 ) : 1 + 1] + { [ ( 30 - 1 ) : 1 + 1] : 2}.( 30+1 ) = 1240
*Giải thích một chút: "x.[( 30 - 0 ) : 1 + 1]" là tính số lượng x. Ở đây có một ố x để nguyên thfi bạn hãy hiểu rằng nó ơợc công 0 vào nhé; "{ [ ( 30 - 1 ) : 1 + 1] : 2}.( 30+1 )" là tính tổng trong ngoặc, bạn nên tính tách ra thì tốt hơn, t lười!
x . 31 + 465 = 1240
x . 31 = 1240 - 465
x . 31 = 775
x = 775 : 31
x = 25
Vậy x 25
Chúc bạn học tốt!
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