tim cac so nguyen x sao cho (x-3)la uoc cua 13
1.Tim cac so nguyen x,sao cho:
A.11 la boi cua 2.x-1
B.x-13 la boi cua 2x-1
C.2x-1la uoc cua 21
D. X+1 ls uoc cua 4x+11
tim x dua vao quan he uoc boi:
tim so tu nhien x sao cho x-1 la uoc cua 12
tim so tu nhien x sao cho 2x+1 la uoc cua 28
tim so tu nhien x sao cho x+15 la boi cua x+3
tim cac so nguyen x,y sao cho (x+1)(y-2)=3
tim so nguyen x sao cho(x+2).(y-1)=2
tim so nguyen to x vua la uoc cua 275 vua la uoc cua 180
tim so nguyen to x,y biet x+y=12 va UCLL (x:y)=5
tim so tu nhien x,y biet x+y=32 va UCLL (x:y)=8
tim so tu nhien x biet x chia het cho10; xchia het cho12; x chia het cho15 va 100<x<150
tim so x nho nhat khac 0b biet x chia het cho 24 va 30
40 chia het cho x . 56 chia het cho x va x>6
tim cac so nguyen x sao cho
a/ x-11la boi cua x-2
b/x+1 la uoc cua 3x+14
tim cac so nguyen x , biet
x+1 la uoc cua x+32
\(\Rightarrow\)x+32 là bội của x+1
\(\Rightarrow\)(x+1)+31 là bội của x+1
\(\Rightarrow\)31 chia hết cho x+1
\(\Rightarrow\)x+1 là Ư(31)={-1;-13;1;31}
Ta có bảng giá trị
x+1 | -1 | -31 | 1 | 31 |
x | -2 | -30 | 0 | 30 |
Vậy x={-2;-`30;0;30}
tim cac so nguyen sao cho n-1 la uoc cua 15
Ư (15) = {\(\pm\)1;\(\pm\)3;\(\pm5\);\(\pm\)15}
n-1 = 1 => n = 2
n-1 = -1 => n = 0
n-1 = 3 => n = 4
n-1 = -3 => n = -2
n-1 = 5 => n = 6
n-1 = -5 => n = -4
n-1 = 15 => n = 16
n-1 = -15 => n = -14
Vậy n-1 thuộc {1;-1;3;-3;5;-5;15;-15}
n thuộc {2;0;4;-2;6;-4;16;-14}
a) tim gia tri nho nhat cua bieu thuc : A = | 1-x | + 8
b) tim cac so nguyen x biet 13 la boi cua x - 4
c) tim so nguyen x sao cho ( x + 5 ) chia het cho ( x + 3 )
giup minh voi! minh can gap gap gap.....
Tim cac so nguyen n sao cho:
a, n-1 la uoc cua 15
b, 2n-1 chia het cho n-3
a)
Ta có:
(n-1)∈Ư(15)={±1;±3;±5;±15}
=>n∈{2;0;4;-2;6;-4;16;-14}
Vậy: n∈{2;0;4;-2;6;-4;16;-14}
b)
Ta có:
2n-1 chia hết cho n-3
=>2(n-3)+5 chia hết cho n-3
=> 5 chia hết cho n-3
=> (n-3)∈Ư(5)={±1;±5}
=>n∈{4;2;8;-2}
Vậy: n∈{4;2;8;-2}
a, n-1 \(\in\)Ư(15)
\(\Rightarrow\)n - 1 \(\in\){ 1; -1 ; 3 ; -3 ; 5 ; -5 ; 15 ; -15}
\(\Rightarrow\)n \(\in\){ 2 ; 0 ; 4 ;-2 ; 6 ; -4 ; 16 ; -14 }
Vậy n \(\in\){ 2 ; 0 ; 4 ;-2 ; 6 ; -4 ; 16 ; -14 }
b, 2n-1 \(⋮\)n - 3
( n -3 ) + ( n -3 ) + 5 \(⋮\)n - 3
Vì n - 3 \(⋮\)n - 3
nên 5 \(⋮\)n - 3
\(\Rightarrow\)n - 3 \(\in\){ 1; -1 ; 5 ; -5 }
\(\Rightarrow\)n \(\in\){ 4 ; 2 ; 8 ; -2 }
Vậy n \(\in\){ 4 ; 2 ; 8 ; -2 }
~ HOK TỐT ~
cho cac so nguen : a = 10 , b = -18
a) viet tap hop cac uoc cua a , cac uoc cua b
b) viet tap hop cac so nguyen vua la uoc cua a vua la uoc cua b
c) viet tap hop cac so nguyen vua la boi cua a vua la boi cua b
tim so nguyen x sao cho
a) 3x + 4 chia het cho x - 3
b) x + 1 la uoc so cua x2 + 7
a) Ta có : \(3x+4⋮x-3\)
\(\Rightarrow3x-9+13⋮x-3\)
\(\Rightarrow13⋮x-3\)
=> x - 3 \(\in\left\{1;-1;13;-13\right\}\)
=> x \(\in\left\{4;2;16;-10\right\}\)
b) x + 1 là ước của x2 + 7
<=> \(x^2+7⋮x+1\)
<=> x2 + 2x + 1 - 2x - 2 + 8 \(⋮x+1\)
<=> (x+1)2 -2.(x+1) + 8 \(⋮x+1\)
Mà( x + 1 )2 \(⋮\)x + 1 ; (x + 1 ) \(⋮\)x + 1
=> 8 \(⋮\)x + 1
=> x + 1 ={ -1 ; 1 ; -2 ; 2 ;-4 ; 4 ; 8 ; -8}
=> x = { -2 ; 0 ; -3 ; 1 ; -5 ; 3 ; -9 ; 7}