\(\frac{2}{x-3}+\frac{x-5}{x-1}=1\)

\(ĐKXĐ:x\ne1;x\ne3\)

\(pt\Leftrightarrow\frac{2x-2}{x^2-4x+3}+\frac{x^2-8x+15}{x^2-4x+3}=1\)

\(\Leftrightarrow\frac{x^2-6x+13}{x^2-4x+3}=1\)

\(\Leftrightarrow x^2-6x+13=x^2-4x+3\)

\(\Leftrightarrow-2x+10=0\Leftrightarrow x=-5\left(t/mđkxđ\right)\)

Vậy pt có 1 nghiệm là -5

2/x - 3 + x - 5/x - 1 = 1

2(x - 1) + (x - 5)(x - 3) = (x - 3)(x - 1)

-6x + 13 + x^2 = x^2 - 4x + 3

-6x + 13 = -4x + 3

13 = -4x + 3 + 6x

13 = 2x + 3

13 - 3 = 3x

10 = 2x

5 = x

=> x = 5

Xem lại dòng 6 đi ๖²⁴ʱℳąɾąкąเ ༉ :))

\(8\frac{1}{6}:2\frac{1}{2}=\frac{49}{6}:\frac{5}{2}=\frac{98}{30}=\frac{49}{15}\)

\(1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{104}{470}=\frac{52}{235}\)

Bn như thần ý nhỉ :)

trả lời:

8x1/6:2x1/2

=4/3:1

=4/3

1x3/10:5x7/8

=3/10:35/8

=12/175

chúc học tốt

\(8\frac{1}{6}:2\frac{1}{2}\)             \(1\frac{3}{10}:5\frac{7}{8}\)

\(=\frac{49}{6}:\frac{5}{2}\)          \(=\frac{13}{10}:\frac{47}{8}\)

\(=\frac{49}{15}\)               \(=\frac{52}{235}\)

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)

\(=1-\frac{1}{100}\)

\(=\frac{99}{100}\)

nhanh lên nha mấy bn ai trả lời dcd thì kb với mình nha

thank you

\(\frac{51}{92}\)

Tích nha

51/92

51/92

-13/6 nha bạn

TL

-13/6

HT nha bn

\(A=\left(3+\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}-\frac{4}{5}\right)\)

\(A=\left(3-5-6\right)+\left(\frac{1}{4}+\frac{7}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\left(\frac{6}{5}+\frac{4}{5}\right)\)

\(A=-8+2+1+3\)

\(A=-3\)

a) \(\frac{5}{1.4}+\frac{5}{4.7}+\frac{5}{7.10}+.....+\frac{5}{27.30}\)

\(=\frac{5}{3}\left(\frac{1}{1.4}+\frac{1}{4.7}+........+\frac{1}{27.30}\right)\)

\(=\frac{5}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+.....+\frac{1}{27}-\frac{1}{30}\right)\)

\(=\frac{5}{3}\left(1-\frac{1}{30}\right)\)

\(=\frac{5}{3}.\frac{29}{30}=\frac{29}{36}\)

Đặt \(A=\frac{12}{3\cdot5}+\frac{12}{5\cdot7}+\frac{12}{7\cdot9}+....+\frac{12}{97\cdot99}\)

\(2A=\frac{12}{3}-\frac{12}{5}+\frac{12}{5}-\frac{12}{7}+...+\frac{12}{97}-\frac{12}{99}\)

\(2A=\frac{12}{3}-\frac{12}{99}\)

\(A=\frac{128}{33}\cdot\frac{1}{2}=\frac{64}{33}\)

1.5/1-5/4+5/4-5/7+5/7-5/9 +....+5/27-5/30

=5/1-5/30

=145/30=29/6.

tầm là sai ế mình làm bài này nhưng ko ra kq 

\(\frac{x+9}{x+5}=\frac{2}{7}\)

=>7(x+9)=2(x+5)

=>7x+63=2x+10

=>63-10=2x-7x

=>53=-5x

=>x=-53/5

dễ hỏi lm j

:)) Để kiếm k đó bạn ^^ Nhật Linh Nguyễn

a) = \(\frac{6}{7}\)+\(\frac{2}{11}\)-\(\frac{6}{7}\)

= \(\frac{2}{11}\)+(\(\frac{6}{7}\)-\(\frac{6}{7}\))

= \(\frac{2}{11}\)

b) = \(\frac{15}{34}\)+\(\frac{1}{3}\)+\(\frac{9}{34}\)-\(\frac{32}{17}\)+\(\frac{2}{3}\)

= ( \(\frac{15}{34}\)+ \(\frac{9}{34}\)) + ( \(\frac{1}{3}\)+ \(\frac{2}{3}\)) - \(\frac{32}{17}\)

= \(\frac{12}{17}\)+ 1 - \(\frac{32}{17}\)

= \(\frac{12}{17}\)+ \(\frac{17}{17}\)- \(\frac{32}{17}\)

= \(\frac{12+17-32}{17}\)

=\(\frac{-3}{17}\)

c) = \(\frac{3}{7}\)x ( \(\frac{2}{9}\)+ \(\frac{7}{9}\))

= \(\frac{3}{7}\)x 1

=\(\frac{3}{7}\)