Tìm x:
[(6x-39)÷3]÷28=5628
Bài 1.Tìm x
6x-39=5628:28
6x - 39 = 201
6x = 201 + 39
6x = 240
x = 240 : 6
x = 40
Vậy x = 40
Chúc bạn học tốt !
1) Tìm x:
a) 20 - [7.(x - 3) + 4 ]=2
b) [ (6x - 39 ) : 3 ] . 28=5628
[(6x-39):3] . 28 = 5628
(6x - 39) : 3 = 201
6x - 39 = 603
6x = 642
x = 107
a) 7.(x - 3) + 4 = 18
7. (x - 3) = 14
x - 3 = 2
x = 5
b) 2x - 13 = 201
2x = 214
x = 107
a) [(6x-39):3].28=5628 b)4x3+12=120
c)1500:[(30x+40):x]=30
a: Ta có: \(\left[\left(6x-39\right):3\right]\cdot28=5628\)
\(\Leftrightarrow\left(6x-39\right):3=201\)
\(\Leftrightarrow6x-39=603\)
\(\Leftrightarrow6x=642\)
hay x=107
b: Ta có: \(4x^3+12=120\)
\(\Leftrightarrow4x^3=108\)
\(\Leftrightarrow x^3=27\)
hay x=3
c: Ta có: \(1500:\left[\left(30x+40\right):x\right]=30\)
\(\Leftrightarrow\left(30x+40\right):x=50\)
\(\Leftrightarrow30x+40=50x\)
hay x=-2
[ ( 6x - 39 ) ;3 ] . 28 = 5628
[ ( 6x - 39) : 3 ] . 28 = 5628
[ ( 6x - 39) : 3 ] = 5628 :28
( 6x - 39) : 3 = 201
( 6x - 39) = 201 .3
6x - 39 = 603
6x = 603 + 39
6x = 642
x = 642 :6
x = 107
Đúng cho tớ với nhé, cảm ơn cậu nhiều !
[ ( 6x - 39) : 3 ] . 28 = 5628
[ ( 6x - 39) : 3 ] = 5628 :28
( 6x - 39) = 201 .3
6x = 603 + 39
x = 642 :6
x = 107
a/x=2^8:2^4+3^2.3^3
b/6x-39=5628:28
a) x = 2^8 : 2^4 + 3^2 . 3^3
x = 2^4 + 3^5
x = 16 + 243
x = 259
b) 6x - 39 = 5628 : 28
6x - 39 = 201
6x = 240
x = 40
(111:x+25):14=2
[(6x-39):3] .28=5628
400-[545-(45+x)]=0
(111:x+25):14=2
=> 111:x+25=2.14
=> 111:x+25=28
=> 111:x=28-25
=> 111:x=3
=> x=111:3
=> x=37
[(6x-39):3].28=5628
=> (6x-39):3=5628:28
=> (6x-39):3=201
=> 6x-39=201.3
=> 6x-39=603
=> 6x=603+39
=> 6x=642
=> x=642:6
=> x=107
400-[545-(45+x)]=0
=> 545-(45+x)=400-0
=> 545-45-x=400
=> 500-x=400
=> x=500-400
=> x=100
(111:x+25):14=2
111 : x + 25 = 2 . 14 = 28
111 : x = 28 - 25 = 3
x = 111 : 3
x = 37
[(6x-39):3] .28=5628
( 6x - 39 ) : 3 = 5628 : 28 = 201
6x - 39 = 201 . 3 = 603
6x = 603 + 39 = 642
x = 642 : 6
x = 107
400-[545-(45+x)]=0
545 - ( 45 + x )=400
45 + x = 545 - 400 = 145
x = 145 - 45
x = 100
[ ( 6x - 39 ) : 3 ] . 28 = 5628
\(\left[\left(6x-39\right):3\right]\cdot28=5628\)
\(\left(6x-39\right):3=5628:28=201\)
\(6x-39=201\cdot3=603\)
\(6x=603+39=642\)
\(x=642:3=214\)
Vậy \(x=214\)
\(\left[\left(6x-39\right):3\right]\cdot28=5628\)
\(\Rightarrow\left(6x-36\right):3=5628:28=201\)
\(\Rightarrow\left(6x-36\right)=21\cdot3\)
\(\Rightarrow6x-36=63\)
\(\Rightarrow6x=63+36\)
\(\Rightarrow6x=99\)
\(\Rightarrow x=16,5\)
mk giải luôn ạ
(6x-39):3=5628:28
(6x-39):3=201
6x-39=201.3
6x-39=603
6x=603+39
6x=642
=>x=107
vậy x=107
Tìm x
a) 81 - ( 7x - 11 )³ = 3
b) 20 - [ 7 . ( x - 3 ) + 4 ] = 2
c) [ ( 6x - 39 ) : 3 ] . 28 = 5628
Giúp mình với ! >_<
x-7=-5
|x|=3
|X|+=8
8-x=12
6x-39=5628:28
x - 7 = -5
x = -5 + 7
x = 2
|x| = 3
=> x = 3 hoặc x = -3
bạn coi lại đề nha
8 - x = 12
x = 8 - 12
x = -4
6x - 39 = 5628 : 28
6x - 39 = 201
6x = 201 + 39
6x = 240
x = 240 : 6
x = 40
1) x-7=-5
x= -5 +7
x=2
3) /x/=3
=>x= -3 hoặc x=3
câu 3 sai đề
4) 8-x=12
x=8-12
x= -4
5) 6x-39=5628:28
6x-39=201
6x=201+39=240
x=240:6
x=40