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Bạn đổi \(\left(\frac{2}{5}\right)^7.5^7=\frac{2^7}{5^7}.5^7=2^7=128\)

\(\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3=\frac{9^3}{4^3}.\frac{16^3}{3^3}=\frac{3^3.3^3}{4^3}.\frac{4^3.4^3}{3^3}=3^3.4^3=17.64=1088\)

CỘNG 2 CÁI ĐÓ LẠI RỒI LÀM Ở TỬ SỐ LÀ RA.

BẤM ĐÚNG NẾU THẤY ĐÚNG

\(=\frac{\left(\frac{2}{5}.5\right)^7+\left(\frac{9}{4}:\frac{3}{16}\right)^3}{2^7.5^2+512}=\frac{2^7+12^3}{2^7.5^2+512}=\frac{128+1728}{3200+512}=\frac{1856}{3712}=\frac{1}{2}\)

\(C=\frac{\left(\frac{2}{5}\right)^7\times5^7+\left(\frac{9}{4}\right)^3\div\left(\frac{3}{16}\right)^3}{2^7\times5^2+512}\)

\(=\frac{\left(\frac{2}{5}\times5\right)^7+\left(\frac{9}{4}\div\frac{3}{16}\right)^3}{2^7\times5^2+2^9}\)

\(=\frac{2^7+12^3}{2^7\times\left(25+2^2\right)}\)

\(=\frac{2^7+\left(2^2\times3\right)^3}{2^7\times\left(25+4\right)}\)

\(=\frac{2^7+2^6\times3^3}{2^7\times29}\)

\(=\frac{2^6\times\left(2+27\right)}{2^7\times29}\)

\(=\frac{29}{2\times29}\)

\(=\frac{1}{2}\)

\(F=\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^9\div\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\)

\(F=\frac{\left(\frac{2.5}{5}\right)^7+\left(\frac{9.16}{4.3}\right)^3}{2^7.5^2+2^9}=\frac{2^7+12^3}{2^7.5^2+2^9}=\frac{2^7+2^6.3^3}{2^7.5^2+2^9}=\frac{2^6.\left(2+3^3\right)}{2^7.\left(5^2+2^2\right)}=\frac{2^6.29}{2^7.29}\)

\(F=\frac{1}{2}\)

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