Tính hợp lý
\(\frac{69}{157}-\left(2+\left(3+\left(4+5^{-1}\right)^{-1}\right)^{-1}\right)^{-1}\)
\(\frac{69}{157}-\left(2+\left(3+\left(4+5^{-1}\right)^{-1}\right)^{-1}\right)^{-1}\)
69/157 - (2 + (3 + (4 + 5-1)-1)-1)-1
= 69/157 - (2 + 21/68)-1
= 69/157 - (157/68)-1
= 69/157 - 68/157
= 1/157
\(\frac{69}{157}-\left(2+\left(3+4+5^{-1}\right)^{-1}\left(^{-1}\right)\right)^{-1}\)
69/157-1/[(2+(7+1/5)]=69/157-1/(46/5)=69/157-1/5/46=69/157-46/5=-6877/785
Tính hợp lý
\(\left(\frac{-1}{2}\right)-\left(\frac{-3}{5}\right)+\left(\frac{-1}{9}\right)+\frac{1}{127}-\left(+\frac{7}{18}\right)+\frac{4}{35}-\left(\frac{-2}{7}\right)\)
\(=\left(-\frac{1}{2}-\frac{1}{9}-\frac{7}{18}\right)+\left(\frac{3}{5}+\frac{2}{7}+\frac{4}{35}\right)+\frac{1}{127}\)
\(=\left(-\frac{9}{18}-\frac{2}{18}-\frac{7}{18}\right)+\left(\frac{21}{35}+\frac{10}{35}+\frac{4}{35}\right)+\frac{1}{127}\)
\(=\left(-\frac{18}{18}\right)+\frac{35}{35}+\frac{1}{127}\)
\(=-1+1+\frac{1}{127}\)
\(=\frac{1}{127}\)
Giải chi tiết giúp mk bài này với: Tính hợp lý :
\(A=\left(-\frac{2}{9}\right)-\left(-\frac{1}{121}\right)+\left(-\frac{3}{5}\right)+\left(-\frac{1}{2}\right)-\left(-1\frac{13}{18}\right)-\frac{1}{7}-\frac{9}{35}\)
\(B=0,75+\frac{3}{5}+\left(\frac{2}{9}-1\frac{3}{5}+1\frac{1}{4}\right)\)
\(C=1-2+3-4+...+79-80\)
c) C = ( 1 - 2 ) + ( 3 - 4 ) + ... + ( 79 - 80 )
C = ( -1 ) + ( -1 ) + ... + ( -1 )
C = ( -1 ) x ( 80 - 1 + 1 ) : 2
C = ( -1 ) x 80 : 2
C = ( -40 )
C=1-2+3-4+...+79-80
=(1-2)+(3-4)+...+(79-80)
=-1+(-1)+...+(-1) (có 80 số hạng bàng -1)
=-1*80
=-80
Tính hợp lý ( nếu có thể):
\(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{49}\right)\)
Tính hợp lý:
\(\left(-\frac{1}{2}\right)+\left(-\frac{3}{5}\right)+\left(-\frac{1}{9}\right)+\frac{1}{127}-\frac{7}{18}+\frac{4}{35}-\left(-\frac{2}{7}\right)\)
Tính hợp lý nếu có thể:
a) \(2\frac{1}{7}:\left(\frac{1}{15}-1\frac{2}{5}\right)-2\frac{1}{7}:\left(\frac{17}{15}+2\frac{1}{5}\right)\)
b) \(\left(\frac{-2}{3}\right)^{-4}.\left(-4\right)^2-\left[\left(\frac{7}{3}\right)^0\right]^{2016}-10\frac{1}{3}\)
a) A = \(\frac{15}{7}:\left(\frac{1}{15}-\frac{7}{5}\right)-\frac{15}{7}:\left(\frac{17}{15}+\frac{11}{5}\right)=\frac{15}{7}:\frac{-20}{15}-\frac{15}{7}:\frac{50}{15}\)
A = \(\frac{15}{7}.\frac{15}{-20}-\frac{15}{7}.\frac{15}{50}=\frac{15}{7}.\left(\frac{-15}{20}-\frac{15}{50}\right)=\frac{15}{7}.\frac{-105}{100}=-\frac{9}{4}\)
b) B = \(\frac{1}{\left(-\frac{2}{3}\right)^4}.\left(-4\right)^2-1^{2016}-10\frac{1}{3}=\frac{1}{\frac{16}{81}}.16-1-10\frac{1}{3}=\frac{81}{16}.16-1-10\frac{1}{3}\)
B = \(81-1-10-\frac{1}{3}=70-\frac{1}{3}=\frac{209}{3}\)
thực hiện phép tính 1 cách hợp lý
\(B=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+...+\frac{1}{20}\left(1+2+3+...+20\right)\)
tính hợp lý:
a) \(\left(\frac{9}{10}-\frac{15}{16}\right)\left(\frac{5}{12}-\frac{11}{15}-\frac{7}{20}\right)\)
b) \(\left(\frac{1}{2}-1\right)\left(\frac{1}{3-1}\right)\left(\frac{1}{4}-1\right).......\left(\frac{1}{100}-1\right)\)
b)\(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\left(\frac{1}{4}-1\right)...\left(\frac{1}{100}-1\right)=\frac{-1}{2}.\frac{-2}{3}.\frac{-3}{4}....\frac{-99}{100}=\frac{-1.\left(-2\right).\left(-3\right)...\left(-99\right)}{2.3.4...100}=-\frac{1}{100}\)