cmr
A=1^3+2^3+3^3...+2016^3 la so chinh phuong
Giup minh voi LAM ON NHANH LEN NHA
Mn oi giup minh bai nay voi, toi minh di hoc roi
a, Tinh A = 1/3 + 1/3^2 + 1/3^3 + ..... +1/3^n
b, Tị so tu nhien co 2 chu so biet so do nhan voi 75 duoc tich la mot so chinh phuong
c, CMR: 1/3 + 2/3^2 +3/3^3 + ... + 101/3^101
a) \(A=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^n}\)
\(3A=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{n-1}}\)
\(3A-A=\left(1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{n-1}}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^n}\right)\)
\(2A=1-\frac{1}{3^n}\)
\(A=\frac{1-\frac{1}{3^n}}{2}\)
b) Gọi số cần tìm là ab (a khác 0; a,b là các chữ số)
Ta có: ab.75 = x2 \(\left(x\ne0\right)\)
=> ab.3.52 = x2
Để ab.75 là 1 số chính phương thì ab = 3.k2 \(\left(k\ne0\right)\)
Lại có: 9 < ab < 100 => 9 < 3.k2 < 100
=> 3 < k2 < 34
Mà k2 là số chính phương nên \(k^2\in\left\{4;9;16;25\right\}\)
\(\Rightarrow ab\in\left\{12;27;48;75\right\}\)
Vậy số cần tim là 12; 27; 48; 75
c) Đặt \(B=\frac{1}{3}+\frac{2}{3^2}+\frac{3}{3^3}+...+\frac{101}{3^{101}}\)
\(3B=1+\frac{2}{3}+\frac{3}{3^2}+...+\frac{101}{3^{100}}\)
\(3B-B=\left(1+\frac{2}{3}+\frac{3}{3^2}+...+\frac{101}{3^{100}}\right)-\left(\frac{1}{3}+\frac{2}{3^2}+\frac{3}{3^3}+...+\frac{101}{3^{101}}\right)\)
\(2B=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{100}}-\frac{101}{3^{101}}\)
\(6B=3+1+\frac{1}{3}+...+\frac{1}{3^{99}}-\frac{101}{3^{100}}\)
\(6B-2B=\left(3+1+\frac{1}{3}+...+\frac{1}{3^{99}}-\frac{101}{3^{100}}\right)-\left(1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{100}}-\frac{101}{3^{101}}\right)\)
\(4B=3-\frac{101}{3^{100}}-\frac{1}{3^{100}}+\frac{101}{3^{101}}\)
\(4B=3-\frac{303}{3^{101}}-\frac{3}{3^{101}}+\frac{101}{3^{101}}\)
\(4B=3-\frac{205}{3^{101}}< 3\)
\(\Rightarrow B< \frac{3}{4}\)
Minh bo sung cau c la tong do be hon 3/4
Cho A=5+5^2+5^3+...+5^2016
a, A la hop so hay so nguyen to
b,A co phai la so chinh phuong khong ?
giup minh giai voi nha cac ban \(\)
cac bn giup minh tra loi cau nay voi
mn giup minh voi
cam on nhung ban nao da giup minh giai bai toan nay
Cho B=2+2^2+.....+2^2019
a, Tim x eN sao cho A+2=2^x+100
b, A+2 co phai la mot so chinh phuong khong
c, A =3+3^2+....+3^300
chung to A chia 13
d, 2A + 3 co phai la so chinh phuong ko
a) \(A=2+2^2+....+2^{2019}\)
\(\Rightarrow2A=2^2+2^3+....+2^{2020}\)
\(\Rightarrow2A-A=2^{2020}-2\)
\(\Rightarrow A=2^{2020}-2\)
b) \(A+2=2^{2020}-2+2=2^{2020}=\left(2^{1010}\right)^2\)là SCP
làm nốt lười
So chinh phuong la so bang binh phuong cua mot so tu nhien ( vi du : 0,1,4,9,16,..) moi tong sau co la mot so chinh phuong khong?
a) 13 + 23
b) 13 + 23 33
C) 13 + 23 + 33 + 43
NHO GHI KET QUA GIUP MINH NHA CAM ON
a ) \(1^3 + 2^3=1+8=9=3^2\)
b) \(1^3+2^3+3^3=1+8+27=36=6^2\)
c ) \(1^3+2^3+3^3+4^3=1+8+27+64=100=10^2\)
moi tong tren deu la so chinh phuong
tinh nhanh
( 1 + 3 + 5 + 7 + .... + 2003 + 2005) x ( 1212 x 27 - 2727 x 12)giup minh voi minh dang can gap lam
nhanh len nha
cam on truoc
( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 1212 x 27 - 2727 x 12 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 32724 -32724 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x 0
= 0
vu cao minh sai roi
de keu la tinh nhanh ma
Thì thế gọi là tính nhanh còn gì
mn giup minh voi
A=5+5^2+5^3+....+5^100
a,CS chi a chia 6
b, cs chi a chia 16
c, tim x cn 4A+5=5^x+2
d, 4A +5 co phai la so chinh phuong khong
can gap nha, cam on ban nao da giup minh
CMR voi moi so tu nhien n thi n(n+1)(n+2)(n+3)+1 la so chinh phuong
Tim chu so a de a.(a+1).(a+2).(a+3) la so chinh phuong
giup minh nhe
Chung to rang tong sau khong la so chinh phuong :
A=abc+bca+cab
Cac ban lam on nhanh gium minh voi