\(\dfrac{1}{4}-\dfrac{1}{3}+\dfrac{5}{12}\\ =\dfrac{3}{12}-\dfrac{4}{12}+\dfrac{5}{12}\\ =\dfrac{3-4+5}{12}\\ =\dfrac{4}{12}\\ =\dfrac{1}{3}\)

      \(\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times\left(\frac{1}{2}-\frac{1}{3}+-\frac{1}{6}\right)\)

\(=\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(=\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)

\(=\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times0\)

\(=0\)

a) 248: {[( 368+232): 120-3]+122}+2011

=248:{[600:120-3]+122}+2011

=> 248:{ 2+122}+2011

=> 248: 124+2011

=> 2+2011

=> 2013

a)  (11+159).37+(185-31):14

  =170.37+154:14

  =6290+11

  =6301

câu b bạn viết khó hiểu quá bạn viết lại đầu bài đi mik giải cho

b) 3280-(3^2.7^3.2^3.49)

a) 21.(-35)-3.(-25).7=21.(-35)-(21.(-25)=21(-35+25)=21.(-10)=-210

b)77-11(30+7)=77-11.7+11.30=77-77-330=-330

c)85(35-27)-35(85-27)=85.35-85.27-35.85+35.27=(85.35-35.85)+(35.27-85.27)=35.27-85.27=27(35-85)=27.(-50)=-1350

d)(-25).68+(-34).(-250)=-25.68+34.2.125=-25.68+68.125=68(125-25)=68.100=6800

e)125.(-61).(-2^3).(-1)^2n+1=125.(-61).(-8).(-1)=(-8.125).61=-1000.61=-61000

h) đặt S=2¹⁰⁰-2⁹⁹-2⁹⁸-...-2²-2-1=2^100-(2^99+2^98+2^97+...+2+1)=2^100-A

ta có: A=2^99+2^98+2^97+...+2+1

2A=2^100+2^99+2^98+...+2^2+2

=>2A-A=(2^100+2^99+2^98+...+2^2+2)-(2^99+2^98+2^98+...+2+1)

=>A=2^100-1

=>S=2^100-(2^100-1)=2^100-2^100+1=1

A=2^100

a là bằng -210

ý b bằng -330

ý c bằng -1350

ý d bằng 6800

ý f bằng 225

tớ làm được 5 ý , tich nha bạn

a, 21.(-35)-3.(-25).7

=21.(-35)-(3.7).(-25)

=21.(-35)-21.(-25)

=21.[(-35)-(-25)]

=21.(-10)

=-210

30-[50-(9-4)²]+2015⁰

=30-[50-5²]+2015⁰

=30-[50-25]+2015⁰

=30-25+2015⁰

=30-25+1

=5+1

=6

45-|-15|:3

=45-15 :3

=45-5

=40

45 - | -15 | : 3

= 45 - 15 : 3

= 45 - 5 

= 40

\(45-|-15|\div3\)

\(=45-15\div3\)

\(=45-5\)

\(=40\)