\(\frac{x}{x^2+9x+a}=\frac{x^2+10x+a}{x^2+8x+a}\) ( với a=const )
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Giải pt sau :
\(\frac{x}{x^2+8x+a}=\frac{x^2+9x+a}{x^2+7x+a}\)
bài 1 giải phương trình
a) (2x+3)^2-3(x-4)(x+4)left(x-2right)^2+1
b)(3x-2) (9x^2+6x+4)-(3x-1) (9x^2+3x+1)x-4
c)x (x-1) -(x-3) (x+4)5x
d) (2x+1)(2x-1)4x(x-7)-3x
bài 2 giải phương trình
a)frac{x}{10}-left(frac{x}{30}+frac{2x}{45}right)frac{4}{5}
b)frac{10x-5}{18}+frac{x+3}{12}frac{7x+3}{6}+frac{12-x}{9}
c)frac{10x+3}{8}frac{7-8x}{12}
d)frac{x+4}{5}-x-5frac{x+3}{3}-frac{x-2}{2}
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bài 1 giải phương trình
a) (2x+3)\(^2\)-3(x-4)(x+4)=\(\left(x-2\right)^2\)+1
b)(3x-2) (9x\(^2\)+6x+4)-(3x-1) (9x\(^2\)+3x+1)=x-4
c)x (x-1) -(x-3) (x+4)=5x
d) (2x+1)(2x-1)=4x(x-7)-3x
bài 2 giải phương trình
a)\(\frac{x}{10}-\left(\frac{x}{30}+\frac{2x}{45}\right)=\frac{4}{5}\)
b)\(\frac{10x-5}{18}+\frac{x+3}{12}=\frac{7x+3}{6}+\frac{12-x}{9}\)
c)\(\frac{10x+3}{8}=\frac{7-8x}{12}\)
d)\(\frac{x+4}{5}-x-5=\frac{x+3}{3}-\frac{x-2}{2}\)
Giải phương trình
a)\(\frac{x+5}{x^2-5x}-\frac{x-5}{2x^2+10x}=\frac{x+25}{2x^2-50}\)
b) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x\left(x-2\right)}+\frac{1}{8x-16}\)
Bạn nào cho mk 1 ik, mk cho bn ý 3 ik luôn. Mk hứa nếu nói dối bạn có thể Báo cáo sai phạm mk.
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Giải PT
3. a. \(x^2-10x-39=0\)
c. \(\frac{x^2}{x^3-9}=\frac{1}{x+3}\)
d. \(\frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}\)
\(a,x^2-10x-39=0\)
\(\Leftrightarrow x^2-10x-39+64=64\)
\(\Leftrightarrow x^2-10x+25=64\)
\(\Leftrightarrow\left(x-5\right)^2=64\)
làm nốt
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\(x^2-10x-39=0\Leftrightarrow x^2-13x+3x-39=0\Leftrightarrow x\left(x-13\right)+3\left(x-13\right)=0\)
\(\Leftrightarrow\left(x-13\right)\left(x+3\right)=0\Leftrightarrow\orbr{\begin{cases}x=13\\x=-3\end{cases}}\)
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\(b,\frac{x^2}{x^3-9}=\frac{1}{x+3}\)
\(\Leftrightarrow x^2\left(x+3\right)=x^3-9\)
\(\Leftrightarrow x^3+3x^2=x^3-9\)
\(\Leftrightarrow3x^2=-9\left(VL\right)\)
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Xem thêm câu trả lời
Giai phuong trinh: \(\frac{x}{x^2+9x+2015}\)\(=\)\(\frac{x^2+10x+2015}{x^2+8x+2015}\)
a ) \(\frac{x+5}{x^2-5x}\)- \(\frac{x-5}{2x^2+10x}\)= \(\frac{x+25}{2x^2-50}\)
b ) \(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)
c ) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}-\frac{x-1}{2x\left(x-2\right)}+\frac{1}{8x-16}\)
Giải phương trìnha) frac{4}{20-6x-2x^2}+ frac{x^2+4x}{x^2+5x}-frac{x+3}{2-x}+30b)frac{x+5}{x^2-5x}-frac{x-5}{2x^2-10x}+10frac{x+25}{2x^2-50}c) frac{7}{8x}+frac{5-x}{4x^2-8x}frac{x-1}{2x.left(x-2right)}+frac{1}{8x-16}c) frac{7}{8x}+frac{5-x}{4x^2-8x}frac{x-1}{2x.left(x-2right)}+frac{1}{8x-16}
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Giải phương trình
a) \(\frac{4}{20-6x-2x^2}\)+ \(\frac{x^2+4x}{x^2+5x}-\frac{x+3}{2-x}+3=0\)
b)\(\frac{x+5}{x^2-5x}-\frac{x-5}{2x^2-10x}+10=\frac{x+25}{2x^2-50}\)
c) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x.\left(x-2\right)}+\frac{1}{8x-16}\)
c) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x.\left(x-2\right)}+\frac{1}{8x-16}\)
A(x)=\(3x^4-\frac{3}{4}x^3+2x^2-3\)
B(x)=\(8x^4+\frac{1}{5}x^3-9x+\frac{2}{5}\)
Tính A(x)+B(x) ; A(x)-B(x) ; B(x)-A(x)
\(A\left(x\right)+B\left(x\right)=3x^4-\frac{3}{4}x^3+2x^2-3+8x^4+\frac{1}{5}x^3-9x+\frac{2}{5}\)
\(=11x^4-\frac{11}{20}x^3+2x^2-\frac{13}{5}-9x\)
\(A\left(x\right)-B\left(x\right)=3x^4-\frac{3}{4}x^3+2x^2-3-8x^4-\frac{1}{5}x^3+9x-\frac{2}{5}\)
\(=-5x^4-\frac{19}{20}x^3+2x^2-\frac{17}{5}+9x\)
Bn làm nót nhé, tương tự thôi
\(A\left(x\right)+B\left(x\right)\)
\(=\left(3x^4-\frac{3}{4}x^3+2x^2-3\right)+\left(8x^4+\frac{1}{5}x^3-9x+\frac{2}{5}\right)\)
\(=11x^4-\frac{11}{20}x^3+2x^2-9x-\frac{13}{5}\)
\(A\left(x\right)-B\left(x\right)\)
\(=3x^4-\frac{3}{4}x^3+2x^2-3-8x^4-\frac{1}{5}x^3+9x-\frac{2}{5}\)
\(=-5x^4-\frac{19}{20}x^3+2x^2+9x-\frac{17}{5}\)
\(B\left(x\right)-A\left(x\right)\)
\(=8x^4+\frac{1}{5}x^3-9x+\frac{2}{5}-3x^4+\frac{3}{4}x^3+2x^2-3\)
\(=5x^4+\frac{19}{20}x^3+2x^2-9x-\frac{13}{5}\)
GIẢI PHƯƠNG TRÌNHa) (3x - 2) (9x2 + 6x + 4) - (3x - 1) (9x2 - 3x + 1) x - 4b) frac{x}{10}-left(frac{x}{30}+frac{2x}{45}right)frac{4}{5}c)frac{10x-5}{18}+frac{x+3}{12}frac{7x+3}{6}-frac{12-x}{9}d) frac{10x+3}{8}frac{7-8x}{12}e) frac{x+4}{5}-x-5frac{x+3}{2}-frac{x-2}{2}Mng giúp Bơ nhaeeeHứa đáp pưn đầy đủ ạaa
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GIẢI PHƯƠNG TRÌNH
a) (3x - 2) (9x2 + 6x + 4) - (3x - 1) (9x2 - 3x + 1) = x - 4
b) \(\frac{x}{10}-\left(\frac{x}{30}+\frac{2x}{45}\right)=\frac{4}{5}\)
c)\(\frac{10x-5}{18}+\frac{x+3}{12}=\frac{7x+3}{6}-\frac{12-x}{9}\)
d) \(\frac{10x+3}{8}=\frac{7-8x}{12}\)
e) \(\frac{x+4}{5}-x-5=\frac{x+3}{2}-\frac{x-2}{2}\)
Mng giúp Bơ nhaeee
Hứa đáp pưn đầy đủ ạaa
\(d,\frac{10x+3}{8}=\frac{7-8x}{12}\)
\(\left(10x+3\right):8=\left(7-8x\right):12\)
\(\left(10x+3\right).\frac{1}{8}=\left(7-8x\right).\frac{1}{12}\)
\(\frac{5}{4}x+\frac{3}{8}=\frac{7}{12}-\frac{8}{12}x\)
\(\frac{5}{4}x+\frac{8}{12}x=\frac{7}{12}-\frac{3}{8}\)
\(\frac{23}{12}x=\frac{5}{24}\)
\(x=\frac{5}{46}\)
E mới lớp 6 nên giải sai thì thông cảm ạ UwU
\(b,\frac{x}{10}-\left(\frac{x}{30}+\frac{2x}{45}\right)=\frac{4}{5}\)
\(< =>\frac{9x}{90}-\frac{7x}{90}=\frac{4}{5}\)
\(< =>\frac{x}{45}=\frac{32}{45}\)
\(< =>x=32\)
\(d,\frac{10x+3}{8}=\frac{7-8x}{12}\)
\(< =>\left(10x+3\right).12=\left(7-8x\right).8\)
\(< =>120x+36=56-64x\)
\(< =>184x=56-36=20\)
\(< =>x=\frac{20}{184}=\frac{5}{46}\)