Tìm x, biết: 2x^2-4x=0
Tìm x biết :
x^4-4x^3+4x^2-(2x-4)(x^2-2x)+(2-x)^2=0
Tìm x, biết :
a. 3x(x-2)-x+2=0
b. 4x(x-3)-2x+6=0
c. 2x(x-4)+x-4=0
d. 2x³+4x=0
e. 3x³-6x=0
a. 3x(x-2)-x+2=0
3x(x-2)-(x-2)=0
(3x-1)(x-2)=0
=>\(\hept{\begin{cases}3x-1=0\\x-2=0\end{cases}}\)
=> \(\hept{\begin{cases}3x=1\\x=2\end{cases}}\)
=>\(\hept{\begin{cases}x=\frac{1}{3}\\x=2\end{cases}}\)
vậy x thuộc (1/3;2)
b. 4x(x-3)-2x+6=0
4x(x-3) -2(x-3)=0
(4x-2)(x-3)
=>*4x-2=0
4x=2
x=1/2
*x-3=0
x=3
vậy x thuộc (1/2;3)
a. 3x(x-2)-x+2=0
=>(x-2)(3x-1)=0
=>x-2=0 hoặc 3x-1=0
*x-2=0=>x=2
*3x-1=0=>x=\(\frac{1}{3}\)
Vậy x=2;x=\(\frac{1}{3}\)
b. 4x(x-3)-2x+6=0
=>(x-3)(4x-2)=0
=>(x-3)=0 hoặc 4x-2=0
*x-3=0=>x=3
*4x-2=0=>\(\frac{1}{2}\)
Vậy x=3; x=\(\frac{1}{2}\)
câu c, d,e thì chút nx mk gửi cho nha
Tìm x biết
a. \(4x^2+2x+4x+2=0\)
b. \(15x^2-25x-10=0\)
c. \(3x^2-27=0\)
Tìm x biết
a) 25x^2 -1-(5x-1)(x+2) = 0
b) (2x-3)-(3-2x)(x-1) = 0
c) 9 -4x^2-(6+4x)(x-5) = 0
b) ( 2x - 3 ) - ( 3 - 2x )( x - 1 ) = 0
<=> ( 2x - 3 ) + ( 2x - 3 )( x - 1 ) = 0
<=> ( 2x - 3 )( 1 + x - 1 ) = 0
<=> x( 2x - 3 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}x=0\\2x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{3}{2}\end{cases}}}\)
Vậy .....
a, 25x^2 - 1 - (5x -1)(x+2)=0
=> (5x)^2 - 1 + (5x-1)(x+2) = 0
=> (5x-1)(5x+1) + (5x-1)(x+2) = 0
=> (5x-1)(5x+1+x+2) = 0
=> (5x-1)(6x+3) = 0
=> \(\orbr{\begin{cases}5x-1=0\\6x+3=0\end{cases}}\)
a) 25x2 - 1 - ( 5x - 1 )( x + 2 ) = 0
<=> ( 5x - 1 )( 5x + 1 ) - ( 5x - 1 )( x + 2 ) = 0
<=> ( 5x - 1 )( 5x + 1 - x - 2) = 0
<=> ( 5x - 1 )( 4x - 1 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}5x-1=0\\4x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{4}\end{cases}}}\)
Vậy .......
Tìm x biết
(6-3x)^2-2(3x-6)=0(2x+5)^3-(2x+5)=0(6-4x)^3-(6-4x)=0(5-4x)^2-(4x+5)=0Tìm x biết
a) (2x-3)2 - (x+5)2=0
b) 4x2-1-x(2x+1)=0
c)x(2x-7)-(4x-14)=0
Tìm x biết: (x^2+2x-3)^3+(x^2-4x-1)^3-(2x^2-2x-4)^3=0
Tìm x biết:
(4x-1)^2-x^2-2x-1=0
(4x-1)2-(x2+2x+1)=0
(4x-1)2-(x+1)2=0
(4x-1-x-1)(4x-1+x+1)=0
(3x-2)5x=0
x=0 hoặc 3x-2=0=>x=2/3
\(\left(4x-1\right)^2-x^2-2x-1=0\)
\(\Rightarrow\left(4x-1\right)^2-\left(x^2+2x+1\right)=0\)
\(\Rightarrow\left(4x-1\right)^2-\left(x+1\right)^2=0\)
\(\Rightarrow\left(4x-1-x-1\right)\left(4x-1+x+1\right)=0\)
\(\Rightarrow\left(3x-2\right).5x=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{2}{3}\end{matrix}\right.\)
Tìm x, biết:
a) 2 x + 1 x 2 − 4 x + 4 − 2 x + 5 x 2 − 4 = 0 với x ≠ ± 2 ;
b) 3 x − 2 − 4 x 4 − x 2 + x x + 2 = 0 với x ≠ ± 2 ;
Tìm x biết: (x^3-2x^2-4x+8)/(x-2)=0