1/3mũ50 . -9mũ25 -2/3 :4
\(A=\)\(-\frac{1}{3}+\frac{1}{3^2}-\frac{1}{3^3}+\frac{1}{3^4}-...+\frac{1}{3^{50}}-\frac{1}{3^{51}}\)
\(3A=-1+\frac{1}{3}-\frac{1}{3^2}+...+\frac{1}{3^{49}}-\frac{1}{3^{50}}\)
\(4A=-1-\frac{1}{3^{51}}\)
\(A=\frac{-1-\frac{1}{3^{51}}}{4}\)
k cho mik nha
Tính:
4 - 1 = 4 - 2 = 3 + 1 = 1 + 2 =
3 - 1 = 3 - 2 = 4 - 3 = 3 - 1 =
2 - 1 = 4 - 3 = 4 - 1 = 3 - 2 =
Thực hiện phép trừ rồi điền kết quả vào chỗ trống.
4 - 1 = 3 4 - 2 = 2 3 + 1 = 4 1 + 2 = 3
3 - 1 = 2 3 - 2 = 1 4 - 3 = 1 3 - 1 = 2
2 - 1 = 1 4 - 3 = 1 4 - 1 = 3 3 - 2 = 1
>, <, = ?
4 – 1 … 2 | 4 – 3 … 4 – 2 |
4 – 2 … 2 | 4 – 1 … 3 + 1 |
3 – 1 … 2 | 3 – 1 … 3 – 2 |
Lời giải chi tiết:
4 – 1 > 2 | 4 – 3 < 4 – 2 |
4 – 2 = 2 | 4 – 1 < 3 + 1 |
3 – 1 = 2 | 3 – 1 > 3 – 2 |
4-1 > 2
4-2 = 2
4-3 < 4-2
4-1 < 3+1
4 – 1 > 2 | 4 – 3 < 4 – 2 |
4 – 2 = 2 | 4 – 1 < 3 + 1 |
3 – 1 = 2 | 3 – 1 > 3 – 2 |
>, <, = ?
4 – 1 … 2 | 4 – 3 … 4 – 2 |
4 – 2 … 2 | 4 – 1 … 3 + 1 |
3 – 1 … 2 | 3 – 1 … 3 – 2 |
Lời giải chi tiết:
4 – 1 > 2 | 4 – 3 < 4 – 2 |
4 – 2 = 2 | 4 – 1 < 3 + 1 |
3 – 1 = 2 | 3 – 1 > 3 – 2 |
a,1/3 .(x-2/5)=3/4 b, 7/3:(x-2/3)=4/5 c,1/3.(x-2/5)=4/5 d, 2/3.(x-1/2)-1/4.(x-2/5)=7/3 e,3/7 .(x-2/3)+1/2=5/4.(x-2) f,1/2.(x-3)+1/3.(x-4)+1/4.(x-5)=1/5 g,[2/3.(x-1/2)-4/5]:(x-1/3)=21/5 h, {x-[1/2.(x-3)+11/5]}:(x-1/2)=3/5 i,x.(x-2/5)-(x+2).x+11/4=4/3
a: =>x-2/5=3/4:1/3=3/4*3=9/4
=>x=9/4+2/5=45/20+8/20=53/20
b: =>x-2/3=7/3:4/5=7/3*5/4=35/12
=>x=35/12+2/3=43/12
c: 1/3(x-2/5)=4/5
=>x-2/5=4/5*3=12/5
=>x=12/5+2/5=14/5
d: =>2/3x-1/3-1/4x+1/10=7/3
=>5/12x-7/30=7/3
=>5/12x=7/3+7/30=77/30
=>x=77/30:5/12=154/25
e: \(\Leftrightarrow x\cdot\dfrac{3}{7}-\dfrac{2}{7}+\dfrac{1}{2}-\dfrac{5}{4}x+\dfrac{5}{2}=0\)
=>\(x\cdot\dfrac{-23}{28}=\dfrac{2}{7}-3=\dfrac{-19}{7}\)
=>x=19/7:23/28=76/23
f: =>1/2x-3/2+1/3x-4/3+1/4x-5/4=1/5
=>13/12x=1/5+3/2+4/3+5/4=257/60
=>x=257/65
i: =>x^2-2/5x-x^2-2x+11/4=4/3
=>-12/5x=4/3-11/4=-17/12
=>x=17/12:12/5=85/144
1+1+1+1+1+1+1=?
2+2+2+2+2+2+2=?
3+3+3+3+3+3+3=?
4+4+4+4+4+4+4=?
5+5+5+5+5+5=?
1+1+1+1+1+1+2+2+2+2+2+2+3+3+3+4+4+4+4+4+4+4+4+1234567890 có chia hết cho 3 không?
>, <, =?
2 … 4 – 1 | 3 – 2 … 3 – 1 |
3 … 4 – 1 | 4 – 1 …4 – 2 |
4 … 4 – 1 | 4 – 1 … 3 + 0 |
Lời giải chi tiết:
2 < 4 – 1 | 3 – 2 < 3 – 1 |
3 = 4 – 1 | 4 – 1 > 4 – 2 |
4 > 4 – 1 | 4 – 1 = 3 + 0 |
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