24:(6-x)=8

6-x=24:8

6-x=3

x=6-3

x=3

#Châu's ngốc

a) \(24:\left(6-x\right)=8\)

\(6-x=24:8=3\)

\(x=6-3=3\)

Vậy x = 3

b) \(25\cdot5^{x+2}=5^6\)

\(5^2\cdot5^{x+2}=5^6\)

\(5^{x+2}=5^6:5^2=5^{6-2}=5^4\)

\(\Leftrightarrow x+2=4\)

\(x=4-2=2\)

Vậy x = 2

Bài làm

a) 24 : ( 6 -x ) = 8

        6 - x    = 3

             x    = 6 - 3

             x    = 3

Vậy x = 3

b) 25 . 5^{x + 2} = 5⁶ 

=> 5² . 5^{x + 2} = 5⁶ 

=> 2 + x + 2 = 6

=> x + 4       = 6

=> x             = 2

Vậy x = 2 

# Học tốt #

x-4=o hoặc 6-x=0 =>x=4 hoặc x=6

+ ) \(\left(x-4\right)\left(6-x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-4=0\\6-x=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=4\\x=6\end{cases}}\)

+ ) \(\left(2x-1\right)^2=25\)

       \(\left(2x-1\right)^2=5^2\)Hoặc \(\left(2x-1\right)^2=\left(-5\right)^2\)

 \(\Rightarrow\orbr{\begin{cases}2x-1=5\\2x-1=-5\end{cases}\Rightarrow\orbr{\begin{cases}2x=6\\2x=-4\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=-2\end{cases}}}\)

+ ) \(\left(x\div6\right)^5=243\)

     \(\left(x\div6\right)^5=3^5\)

\(\Rightarrow x\div6=3\)

\(\Leftrightarrow x=18\)

\(\left(x-4\right)\left(6-x\right)=0\)

Th1:\(x-4=0\Rightarrow x=4\)

Th2: \(6-x=0\Rightarrow x=6\)

\(\Rightarrow S=\left\{4;6\right\}\)

\(\left(2x-1\right)^2=25\)

\(\left(2x-1\right)^2=5^2\)

\(2x-1=5\)

\(2x=6\)

\(x=3\)

\(\Rightarrow S=\left\{3\right\}\)

\(\left(\frac{x}{6}\right)^5=243\)

\(\left(\frac{x}{6}\right)^5=3^5\)

\(\frac{x}{6}=3\)

\(x=3\cdot6=18\)

\(\Rightarrow S=\left\{18\right\}\)

\(\left(2x-5\right)^3=8\)

\(\left(2x-5\right)^3=2^3\)

\(2x-5=2\)

\(2x=7\)

\(x=\frac{7}{2}\)

\(b,6⋮x-1\)

\(\Rightarrow x-1\inƯ6\left(\pm1,\pm2,\pm3\right)\)

+ x-1 =1 => x=2

+ x-1 =-1 =>x=0

+ x-1=2 =>x=3

+ x-1=-2 => x= -1

+ x-1 =3 =>x=4

+ x-1=-3 => x=-2

#Giải :

( 2x - 5 )³ = 8

( 2x - 5 )³ = 2³

=> 2x - 5 = 2

     2x = 7

       x = 7/2

6 chia hết cho ( x - 1 )

=> (x - 1) € Ư (6)

Ư (6) = { 1 ; 2 ; 3 ; 6 }

Nếu x - 1 = 1 => x = 2

Nếu x - 1 = 2 => x = 3

Nếu x - 1 = 3 => x = 4

Nếu x - 1 = 6 => x = 7

   [ P/S : € - thuộc ]

       #By_Ami 

a) (2x-5)³=8

    (2x-5)³=2³

     2x-5   =2

     2x       =2+5

     2x       =7

       x       =7/2

b) \(6⋮\left(x-1\right)\)

\(\Rightarrow x-1\inƯ\left(6\right)\)

\(\Rightarrow x-1\in\left\{-1;-2;-3;-6;1;2;3;6\right\}\)

\(\Rightarrow x\in\left\{0;-1;-2;-5;2;3;4;7\right\}\)

     Hok tốt nha!!!

=> x . 3,6=27 . -2

=>x . 3,6=-54

=>x=-15

=>x.36=27.-2

=> x.3.6=-54

=> x=-15

x^=27

a)\(-2\left(x+6\right)+6\left(x-10\right)=8.\)

\(\Leftrightarrow-2x-12+6x-60=8\)

\(\Leftrightarrow4x=80\)

\(\Rightarrow x=20\)

b/ \(-4\left(2x+9\right)-\left(-8x+3\right)-\left(x+13\right)=0\)

\(\Leftrightarrow-8x-36+8x-3-x-13=0\)

\(\Leftrightarrow-x=52\)

\(\Rightarrow x=-52\)

c/\(7x\left(2+x\right)-7x\left(x+3\right)=14\)

\(\Leftrightarrow14x+7x^2-7x^2-21x=14\)

\(\Leftrightarrow-7x=14\)

\(\Rightarrow x=-2\)

minh cma on nha

3x+17=2⁸.2³

3x+17=2¹¹

3x+17=2048

3x=2048-17

3x=2031

x=2031:3

x=677

Vậy x=677

3x + 17 = 2⁸.2³
3x + 17 = 2⁸⁺³
3x + 17 = 2¹¹
3x + 17 = 2048
3x         = 2048 - 17
3x         = 2031
  x         = 2031 : 3
  x         = 677
Vậy x = 677

3x + 17 = 2⁸ × 2³

<=>  3x+17= 2⁸⁺³=2¹¹ =2048

<=> 3x=2048-17=2031

<=>x=2031:3=677

Vậy x = 677

♡♡♡♡♡♡♡

\(F=\left|x\right|+\left|x+2\right|=\left|-x\right|+\left|x+2\right|\ge\left|-x+x+2\right|=2\)(Áp dụng bất đẳng thức \(\left|a\right|+\left|b\right|\ge\left|a+b\right|\))Dấu "=" xảy ra \(\Leftrightarrow-x\left(x+2\right)\ge0\)
\(\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}-x\ge0\\x+2\ge0\end{cases}}\\\hept{\begin{cases}-x\le0\\x+2\le0\end{cases}}\end{cases}}\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}x\le0\\x\ge-2\end{cases}\Rightarrow x=0;-1;-2}\\\hept{\begin{cases}x\ge0\\x\le-2\end{cases}\Rightarrow x\in\varnothing}\end{cases}}\)

Vậy x = 0;-1;-2

cái chỗ giải -x(x+2) >=0 bạn tự giải làm 2 trường hợp: (-x>=0 và x+2>=0) hoặc (-x<=0 và x+2<=0)

3^x+2-5.3^x=36

3^x(3^2-5)=36

3^x.4=36

3^x=9

x=2

\(3^{x+2}-5\cdot3^x=36\)

\(3^x\cdot3^2-5\cdot3^x=36\)

\(3^x\left(3^2-5\right)=36\)

\(3^x\left(9-5\right)=36\)

\(3^x\cdot4=36\)

\(3^x=36:4\)

\(3^x=9\)có \(3^2=9\)

\(\Rightarrow x=2\)

\(\Rightarrow x\in\left\{2\right\}\)