dell giúp thì sao

A=2000²⁰¹⁶+2000²⁰¹⁷=2000²⁰¹⁶(1+2000)=2000²⁰¹⁶x2001<2001²⁰¹⁶x2001=2001²⁰¹⁷=B

Vây A < B

Ta có : A = 2000²⁰¹⁶ + 2000²⁰¹⁷

      = 2000²⁰¹⁶.(1 + 2000)

      = 2000²⁰¹⁶.2001

      < 2001²⁰¹⁶.2001

      = 2001²⁰¹⁷ = B

=> A < B

Vậy A < B

B=2000²⁰¹⁷+2017               ,A=2000²⁰¹⁶+2000²⁰¹⁷

Mà 2000²⁰¹⁶>2017

=>A>B

                                                         Bài giải

Ta có :

\(A=2000^{2016}\cdot2000^{2017}=2000^{2016}\left(1+2000\right)=2000^{2016}\cdot2001< 2001^{2016}\cdot2001=2001^{2017}=B\)

\(\Rightarrow\text{ }A< B\)

Ta có:\(Q=\frac{2015+2016+2017}{2016+2017+2018}=\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)

Vì \(\hept{\begin{cases}\frac{2015}{2016}>\frac{2015}{2016+2017+2018}\\\frac{2016}{2017}>\frac{2016}{2016+2017+2018}\\\frac{2017}{2018}>\frac{2017}{2016+2017+2018}\end{cases}}\)

\(\Rightarrow\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}>\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)

\(\Rightarrow P>Q\)

Vậy P > Q

tớ chịu thôi SORRY CẬU RẤT NHIỀU

A=2015/2016+2016/2017+2017/2018>2015/2018+2016/2018+2017/2018

=6048/2018>1

B=2015+2016+2017/2016+2017+2018=6048/6051<1

=>A>B

Có: B = 2015 + 2016 + 2017/2016 + 2017 + 2018

       B= 2015 / (2015 + 2016+2017)  + 2016/(2016+2017+2018) + 2017/(2016 + 2017 + 2018)

vì     2015/2016 > 2015/(2016 + 2017+2018)  ; 2016/2017>2016/(2016+2017+2018) ; 2017/2018 > 2017/(2016+2017+2018)

=> A>B

có ai là ARMY ko nếu là ARMY thì mọi người cày view chưa