Các bạn làm nhanh hộ mình, mình đang cần gấp😊

Thôi để t làm nốt cho 

c )  

Ta có : 

\(x+5⋮2x-1\)

\(\Leftrightarrow2\left(x+5\right)⋮2x-1\)

\(\Leftrightarrow2x+10⋮2x-1\)

\(\Leftrightarrow2x-1+11⋮2x-1\)

\(\Leftrightarrow11⋮2x-1\)

\(\Leftrightarrow2x-1\inƯ\left(11\right)\)

\(\Leftrightarrow2x-1\in\left\{1;-1;11;-11\right\}\)

\(\Leftrightarrow2x\in\left\{2;0;12;-10\right\}\)

\(\Leftrightarrow x\in\left\{1;0;6;-5\right\}\)

a )    \(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)

\(\Rightarrow\left(19x+2.25\right):14=5^2-16\)

\(\Rightarrow\left(19x+50\right):14=25-16\)

\(\Rightarrow\left(19x+50\right):14=9\)

\(\Rightarrow19x+50=9.14\)

\(\Rightarrow19x+50=126\)

\(\Rightarrow19x=126-50\)

\(\Rightarrow19x=76\)

\(\Rightarrow x=76:19\)

\(\Rightarrow x=4\)

Vậy \(x=4\)

b )   Số lượng số dãy số trên là : 

( x - 1 ) : 1 + 1 = x ( số ) 

Tổng dãy số trên là : 

( x + 1 ) . x : 2 = 378

=> ( x + 1 ) . x = 378 . 2 

=> ( x + 1 ) . x = 756

=> x = 27 hoặc x = -28 

Vậy x = 27 hoặc x = -28

c )  Tự làm nhé 

a)\(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)

\(\left(19x+2\cdot25\right)\div14=\left(13-8\right)^2-16\)

\(\left(19x+2\cdot25\right)\div14=5^2-16\)

\(\left(19x+2\cdot25\right)\div14=25-16\)

\(\left(19x+2\cdot25\right)\div14=9\)

\(\left(19x+2\cdot25\right)=9\times14\)

\(\left(19x+2\cdot25\right)=126\)

\(\left(19x+50\right)=126\)

\(19x=126-50\)

\(x=76\div19\)

\(\Rightarrow x=4\)

b) \(1+2+3+4+...+x=378\)

\(\left(1+x\right)\cdot x\div2=378\)

\(\left(1+x\right)\cdot x=378\times2\)

\(\left(1+x\right)\cdot x=756\)

\(\left(1+x\right)\cdot x=28\cdot27\)

\(\Rightarrow x=27\)

c) \(x+5⋮2x-1\)

\(\Rightarrow x\in\left\{\varnothing\right\}\)

vì ko số nào chia hết

a) \(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)

\(\left(19x+2\cdot25\right)\div14=5^2-16\)

\(\left(19x+50\right)\div14=25-16=9\)

\(19x+50=9\cdot14=126\)

\(19x=126-50=76\)

\(x=76\div19=4\)

b) \(2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)

\(2\cdot3^x=\left(10+8\right)\cdot3^{12}\)

\(2\cdot3^x=18\cdot3^{12}\)

\(\Rightarrow2\cdot3^x=2\cdot3^2\cdot3^{12}\Rightarrow2\cdot3^x=2\cdot3^{15}\Rightarrow x=15\)

a, \left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2(19.x+2.52)÷14=(13−8)2−42
\left(19.x+2.25\right)\div14=5^2-4^2(19.x+2.25)÷14=52−42
\left(19.x+2.25\right)\div14=25-16(19.x+2.25)÷14=25−16
\left(19.x+50\right)\div14=9(19.x+50)÷14=9
\left(19.x+50\right)=9.14(19.x+50)=9.14
19.x+50=12619.x+50=126
19.x=126-5019.x=126−50
19.x=7619.x=76
\Rightarrow x=76\div19⇒x=76÷19
\Rightarrow x=4⇒x=4
Vậy x = 4
b, 2.3^x=10.3^{12}+8.27^42.3x=10.312+8.274
2.3^x=10.3^{12}+8.\left(3^3\right)^42.3x=10.312+8.(33)4
2.3^x=10.3^{12}+8.3^{12}2.3x=10.312+8.312
2.3^x=\left(10+8\right).3^{12}2.3x=(10+8).312
2.3^x=18.3^{12}2.3x=18.312
2.3^x=2.3^3.3^{12}2.3x=2.33.312
2.3^x=2.3^{15}2.3x=2.315
\Rightarrow x=15⇒x=15
Vậy x = 15

Cau a sai de

ừ mình nhầm

a,(19x+2*5^2)/14=(13-8)^2-4^2

Giúp mik vs nha