I don't now

or no I don't

..................

sorry

\(\left(2x-3\right)^2-\left(2x-3\right)=0\)

\(\Rightarrow\left(2x-3\right)\left(2x-3-1\right)=0\)

\(\Rightarrow\left(2x-3\right)\left(2x-4\right)=0\)

\(\Rightarrow\hept{\begin{cases}2x-3=0\\2x-4=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=\frac{3}{2}\\x=2\end{cases}}\)

a: 3^x=243

=>3^x=3^5

=>x=5

b: 4^x=4096

=>4^x=4^5

=>x=5

c: 5^3-x=25

=>3-x=2

=>x=1

d: =>2x-3=3

=>2x=6

=>x=3

j: =>2^x*8+2^x*2=80

=>2^x=8

=>x=3

\(\left(x-3\right)\left(2x+6\right)=0\)

<=> \(\hept{\begin{cases}x-3=0\\2x+6=0\end{cases}}\)

<=> \(\hept{\begin{cases}x=3\\x=-3\end{cases}}\)

học tốt

a. (x - 3) . (2x + 6) = 0

<=> \(\orbr{\begin{cases}x-3=0\\2x+6=0\end{cases}}\)

<=> \(\orbr{\begin{cases}x=3\\2x=-6\end{cases}}\)

<=> \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)

Vậy x = + 3

(x-3)(2x+6)=0

x(2+6-3)=0

x.5=0

x=0:5=0

câu a

2 mũ x = 512 chia 8

2 mũ x =64

2 mũ x = 2 mũ 6

suy ra x =6

2^x.8=512

2^x=512:8

2^x=64

2^x=2⁶

=>x=6

(2x+1)³=729

(2x+1)³=9³

2x+1=9

2x=9-1

2x=8

x=8:2

x=4

a) 2^x . 8 = 512

2^x = 512 : 8

2^x = 64

2^x = 2⁶ 

x = 6

b) ( 2x + 1 )³ = 729

( 2x + 1)³ = 9³

2x + 1 = 9

2x = 9 - 1 

2x = 8

x = 8 : 2

x = 4

A= 2^2019-2^2018-...-2^2-2^1-1 

??????

ÁP dụng tc dãy tỉ số bằng nhau ta có:

\(\frac{x}{3}=\frac{y}{5}=\frac{z}{7}=\frac{2x}{6}=\frac{3y}{15}=\frac{z}{7}=\frac{2x+3y-z}{6+15-7}=\frac{-14}{14}=-1\)

\(\Rightarrow x=-3;y=-5;z=-7\)

Đặt \(\frac{x}{3}=\frac{y}{5}=\frac{z}{7}=k\)

\(\Rightarrow x=3k;y=5k;z=7k\)

\(2x+3y-z=-14\)

\(\Leftrightarrow6k+15k-7k=-14\)

\(\Leftrightarrow14k=-14\)

\(\Leftrightarrow k=-1\)

\(\Rightarrow x=-3;y=-5;z=-7\)

Từ đề bài ta có:

4/3x - 1/3 = (2x-1) : 3/5 

=> 4/3x -1/3 = (2x-1) * 5/3

=> 4/3x -1/3= 10/3x - 5/3

Chuyển vế đổi dấu

Ta được:

=> -2x = -4/3

=> x= 2/3

Vậy x= 2/3

\(1\frac{1}{3}x=\left(2x-1\right):\left(1-\frac{2}{5}\right)\)

\(\frac{4}{3}x=\left(2x-1\right):\left(\frac{3}{5}\right)\)

\(\frac{4}{3}x.\frac{3}{5}=\left(2x-1\right)\)

\(\frac{4}{5}x=\left(2x-1\right)\)

\(x=\left(2x-1\right):\frac{4}{5}\)

\(x=\left(2x-1\right).\frac{5}{4}\)

\(x=2x.\frac{5}{4}-1.\frac{5}{4}\)

\(x=\)\(2x.\frac{5}{4}-\frac{5}{4}\)

\(x=2.\frac{5}{4}.x-\frac{5}{4}\)

\(x=\left(\frac{5}{2}.x\right)-\frac{5}{4}\)

\(x=\frac{5}{2}-\frac{5}{4}.x-\frac{5}{4}\)

\(x=\frac{5}{4}.x-\frac{5}{4}\)

\(x=x\left(\frac{5}{4}-\frac{5}{4}\right)\)

\(x=x.0\)

\(=>x=0\)