Ta có:

=35x12-15x28+23/49-23/49+2010

=420-420+0+2010

=0+2010

=2010

chúc bạn học tốt

Câu này dễ mà 

\(=35.12-15.28+\frac{23}{49}-\frac{23}{49}+2010\)

\(=\left(420-420\right)+\left(\frac{23}{49}-\frac{23}{49}\right)+2010\)

\(=0+0+2010\)

\(=2010\)

  35 x 12 - 15 x 28 + \(\frac{2323}{4949}-\frac{23}{49}\)+ 2010 

=  (420 - 420 )+ \(\left(\frac{23}{49}-\frac{23}{49}\right)\)+ 2010

= 0 + 0 + 2010 = 2010 .

35 x 12 -15 x28+2323/4949-23/49+2010

=35x12-15x28+23/49-23/49+2010

=420-420+0+2010

=0+0+2010

=2010

35.12-15.28+ 23.101/49.101-23/49+2010=

=7.5.4.3 - 3.4.4.7+23/49-23/49+2010=

=2010

35 x 12 - 15 x 28 + \(\frac{23}{49}\)- \(\frac{23}{49}\)+ 2017

= 35 x 12 - 15 x 28 + 0 + 2017

= 35 x 12 - 15 x 28 + 2017

= 420 - 420 + 2017

= 0 + 2017

= 2017

ra 2017 pn nha

mình còn ko bt cơ mà mai nộp r

mik chỉ lm đc 1 câu thôi mong bn like cho
(13911:3849−5211:3849):(4938.511)={(13+911).4938−(5+211).4938}:(4938.511)=4938.(13−5+911−211):(4938.511)=4938.(8+711):(4938.511)=(8+711):511=19

a)\(\frac{23.5^2.7^2.3^7}{49.5^3.3^2.11}=\frac{23.5^2.7^2.3^7}{7^2.5^3.3^2.11}=\frac{23.3^5}{5.11}=\frac{23.243}{5.11}=\)\(\frac{5589}{55}\)

b) \(\frac{9^{14}.25^5.8^7}{18^{12}.6^{25}.3^{243}}=\frac{3^{28}.5^{10}.2^{21}}{\left(3^2.2\right)^{12}.\left(2.3\right)^{25}.3^{243}}=\frac{3^{28}.5^{10}.2^{21}}{3^{24}.2^{12}.2^{25}.3^{25}.3^{243}}=\frac{3^{28}.5^{10}.2^{21}}{3^{292}.2^{37}}=\frac{5^{10}}{3^{264}.2^{16}}\)

mik làm xong kết bn với mik nhé

thì cứ làm đi

\(\frac{25^4\cdot7^2+5^8\cdot49}{5^8\cdot2^3-25^4}=\frac{5^8\cdot7^2+5^8\cdot7^2}{5^8\cdot2^3-5^8}=\frac{5^8\cdot7^2\cdot\left(1+1\right)}{5^8\cdot\left(2^3-1\right)}=\frac{2\cdot5^8\cdot7^2}{5^8\cdot7}=2\cdot7=14\)