\(F=\frac{1996^3-1}{1996^2+1997}=\frac{\left(1996-1\right)\left(1996^2+1996+1\right)}{1996^2+1997}=\frac{1995.\left(1996^2+1997\right)}{1996^2+1997}=1995\)

E = \(\frac{1995^3}{1995^2-1994}=\frac{1995^3+1-1}{1995^2-1994}=\frac{\left(1995+1\right)\left(1995^2-1995+1\right)-1}{1995^2-1994}\)

  =\(\frac{1996\left(1995^2-1994\right)-1}{1995^2-1994}=1996-\frac{1}{1995^2-1994}\)

Vì \(1995^2-1994>0\) => \(\frac{1}{1995^2-1994}-1\) =>  \(1996-\frac{1}{1995^2-1994}>1996-1\)

HAy E > F

chuẩn luôn

a)37/53x23/48x535353/373737x242424/232323

=37/53x23/48x53/37x24/23

=851/2544x1272/851

=1/2

\(\frac{2}{7}\)+ \(\frac{5}{14}\)+\(\frac{1}{7}\)+ \(\frac{3}{14}\)=\(\frac{4}{14}\)+\(\frac{5}{14}\)+\(\frac{2}{14}\)+\(\frac{3}{14}\)=\(\frac{14}{14}\)=1

469x281+489x719=469x281+(469+20)x719=469x281+469x719+20x719=469x(281+719)+1438=469x1000+1438=469000+1438=470438

a\(\frac{2}{5}\)+\(\frac{5}{14}\)+\(\frac{1}{7}\)+\(\frac{3}{14}\)=\(\frac{53}{70}\)+\(\frac{1}{7}\)=\(\frac{9}{10}\)+\(\frac{3}{14}\)=\(\frac{39}{35}\)

b\(\frac{1995.1997-1}{1996.1995+1994}\)=3984008001

c    469x281+489x719

=(489-469)x(281+719)

=20x1000

=20000

minh rut gon roi nha

\(\dfrac{1995x1997-1}{1996x1995+1994}=\dfrac{1995x\left(1996+1\right)-1}{1996x1995+1994}\)

\(=\dfrac{1995x1996+1995-1}{1996x1995+1994}=\dfrac{1995x1996+1994}{1996x1995+1994}=1\)

1

\(\frac{1}{1997}\)

Chỗ cuối là 1997 ạ

Tính diện tích miếng bìa màu xanh như hình bên 20cm 25cm

\(\frac{1995.1997-1}{1996.1995+1994}\)

\(=\frac{1995.1996+1995-1}{1996.1995+1994}\)

\(=\frac{1995.1996+1994}{1996.1995+1994}=1\)

#

-\(\frac{1995\cdot1997-1}{1995\cdot1996+1994}\)

=\(\frac{1995\cdot\left(1996+1\right)-1}{1995\cdot1996+1994}\)

=\(\frac{1995\cdot1996+1995\cdot1-1}{1995\cdot1996+1994}\)

=\(\frac{1995\cdot1996+1994}{1995\cdot1996+1994}\)

=1