TÌM X
a,1/1 nhan 3 + 1/3 nhan 5+1/5 nhan 7+...+1/x nhan (x+2)=20/41
tim x nha mn
l,[12 nhan 15 - x] nhan 1/4= 120 nhan 1/4
i, [x nhan 0,25 cong 2012 ] nhan 2013 =[50 cong 2012] nhan 2013
k,[ x - 1/2] nhan 5/3 = 7/4 - 1/2
\(\left[12\cdot15-x\right]\cdot\frac{1}{4}=120\cdot\frac{1}{4}\)
\(\Leftrightarrow\left[180-x\right]\cdot\frac{1}{4}=30\)
\(\Leftrightarrow180-x=30:\frac{1}{4}\)
\(\Leftrightarrow180-x=120\)
\(\Leftrightarrow x=60\)
\(\left[x\cdot0,25+2012\right]\cdot2013=\left[50+2012\right]\cdot2013\)
\(\Leftrightarrow x\cdot0,25\cdot2013+2012\cdot2013=2062\cdot2013\)
\(\Leftrightarrow x\cdot\frac{2013}{4}+4050156=4150806\)
\(\Leftrightarrow x\cdot\frac{2013}{4}=100650\)
\(\Leftrightarrow x=100650:\frac{2013}{4}=100650\cdot\frac{4}{2013}=200\)
35 nhan x + 1/2 : 5/3 - 5/4 = 1/2 x 1/3
3/5 nhan x + 1/2 : 5/3 - 5/4 = 1/2 x 1/3
ban ko tra loi ho minh cau nay a
neu the minh ket ban kieu gi
2/5: 3/7 nhan 3/7 : 2/5 + 1999
{1- 1/2} nhan { 1 - 1/3} nhan { 1 - 1/4 } nhan { 1 - 1/5}
\(\frac{2}{5}:\frac{3}{7}x\frac{3}{7}:\frac{2}{5}+1999=\)\(\frac{2}{5}x\frac{7}{3}x\frac{3}{7}x\frac{5}{2}+1999=\)\(\left(\frac{2x7x3x5}{5x3x7x2}\right)+1999=\)\(1+1999=2000\)
\(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{5}\right)\)\(=\left(\frac{2}{2}-\frac{1}{2}\right)\)\(x\left(\frac{3}{3}-\frac{1}{3}\right)\)\(x\left(\frac{4}{4}-\frac{1}{4}\right)\)\(x\left(\frac{5}{5}-\frac{1}{5}\right)\)\(=\frac{1}{2}x\frac{2}{3}x\frac{3}{4}x\frac{4}{5}=\)\(\frac{1x2x3x4}{2x3x4x5}=\frac{1x\left(2x3x4\right)}{\left(2x3x4\right)x5}=\frac{1}{5}\)\(.\)
2/5:3/7 nhân 3/7:2/5+1999
=2/5 nhân 7/3 nhân 3/7nhân 5/2+1999
=14/15 nhân 15/14+1999
=1+1999
=2000
(1-1/2) nhân (1-1/3) nhân (1-1/4) nhân (1-1/5)
=1/2 nhân 2/3 nhân 3/4 nhân 4/5
=24/120
=1/5
Rút gọn biểu thức
(a-b+c-d)-(a+b+c+d)
(-a+b-c)+(a-b)-(a-b+c)
-(a-b-c)+(b-c+d)-(a+b+d)
Tìm số nguyên x,biết
x+x+x+82=-2-x
5 nhan (-40) nhan x=-100
(-1) nhan (-3) nhan (-6) nhan x=36
gia tri tuyet doi cua
1-4x=7
x nhan(x-2)=0
x nhan(x-2) lon hon 0
(a-b+c-d)-9a+b+c+d)=a-b+c-d-a-b-c-d
=(a-a)-(b+b)+(c-c)-(d-d)
=0-2b+0-2d
=-2b-2d
(-a+b-c)+(a-b)-(a-b+c)
=-a+b-c+a-b-a+b-c
=(-a+a-a)+(b-b+b)-(c+c)
=-a+b-2c
-(a-b-c)+(b-c+d)-(a+b+d)
=-a+b+c+c-c+d-a-b-d
=(-a-a)+(b-b)+(c+c-c)+(d-d)
=-2a+0+c+0
=-2a+c
x+x+x+82=-2-x
3x+82=-2-x
3x+x=-2-82
4x=-84
x=-84:4=-21
5.(-40).x=-100
-200.x=-100
x=-100:(-200)
x=0,5
-1.(-3).(-6).x=36
-18.x=36
x=36:(-18)
x=-2
|1-4x|=7
Xảy ra hai trường hợp:1-4x=7=>4x=1-7=-6=>x=-6:4=-1,5
1-4x=-7=>4x=1+7=8=>x=8:4=2
Vì x là số nguyên nên ta chỉ có một đáp án đó là:2
x.(x-2)=0+> x=0 hoặc x=2
x.(x-2)>0=>x=-1;-2;-3;-4;...
giup em voi moi nguoi oi
tim so tu nhien x
1+2+3...+99+100+x=6050
3 nhan x tru 18 =x+20
x phan 4 = 14 phan x+1
2000-5 nhan[x-18]= 125 nhan 8
em cam on a
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+3)=101 phan 1540
1 phan 5 nhan 8 cong 1 phan 8 nhan 11 cong 1 phan 11 nhan 14 +..........+1 phan x nhan (x+3)=101 phan 1540
\(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}\)
\(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{x.\left(x+3\right)}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{x+3}=\frac{1}{308}\)
\(\Rightarrow x+3=308\)
\(x=305\)
tim x thuoc n biet : b,(149 nhan 35 : x + 5) nhan 17 =13 va d/(3 nhan x tru 3 ) binh phuong 3 =2 nhan 32 e/5 x+1-5x=500
Bai 1 Tim x
A) x nhan 4 phan 5 = 1 phan 2 nhan 1 phan 3
B ) x : 2 phan 5 = 2phan 3 + 1 phan 2