TÌM X HỘ MIK NHA MÌNH CẢM ƠN\(\left(X+\frac{1}{1\cdot3}\right)+\left(X+\frac{1}{3\cdot5}\right)+...+\left(X+\frac{1}{23\cdot25}\right)=11\cdot X+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{242}\right)\)
Những câu hỏi liên quan
Tìm \(x\)sao cho:
\(\left(x+\frac{1}{1\cdot3}\right)+\left(x+\frac{1}{3\cdot5}\right)+\left(x+\frac{1}{5\cdot7}\right)+...+\left(x+\frac{1}{23\cdot25}\right)=11\cdot x+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\right)\)
Chỉ biết \(x\) = \(\frac{109}{6075}\) thôi
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Tìm x biết:
\(\left(1+\frac{1}{1\cdot3}\right)\cdot\left(1+\frac{1}{2\cdot4}\right)\cdot\left(1+\frac{1}{3\cdot5}\right)\cdot...\cdot\left(1+\frac{1}{2014\cdot2016}\right)\)=\(\frac{x}{1008}\)
Ta có :
\(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right)....\left(1+\frac{1}{2014.2016}\right)\)
\(=\frac{4}{1.3}.\frac{9}{2.4}.\frac{16}{3.5}.....\frac{4060225}{2014.2016}\)
\(=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}....\frac{2015.2015}{2014.2016}\)
\(=\frac{2.3.4....2015}{1.2.3....2014}.\frac{2.3.4....2015}{3.4.5....2016}\)
\(=\frac{2015}{1}.\frac{2}{2016}\)
\(=2015.\frac{1}{1008}=\frac{2015}{1008}\)
\(\Rightarrow\frac{2015}{1008}=\frac{x}{1008}\Rightarrow x=2015\)
Vậy \(x=2015\)
Ủng hộ mk nha !!! ^_^
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Xem thêm câu trả lời
Tĩm x:
1,\(\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+5\right)}=\frac{1}{x+5}\)
2,\(\left(x+\frac{1}{1.3}\right)+\left(x+\frac{1}{3.5}+......+x+\frac{1}{23.25}\right)=11.x+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\right)\)
Giải chi tiết hộ mình nha mình tik cho
Giải phương trình:
\(\left(1+\frac{1}{1\cdot3}\right)\left(1+\frac{1}{2\cdot4}\right)\left(1+\frac{1}{3\cdot5}\right)...\left(1+\frac{1}{x\left(x+2\right)}\right)=\frac{1989}{995}\) 1989/995 nhé!!!
Cảm ơn mọi người
để ý 1+1/x(x+2)=(x2+2x+1)/x(x+2)=(x+1)2/x(x+2)
+ 1+1/1.3=22/1.3 ;......
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\(\frac{1}{2\cdot3}+\frac{1}{3\cdot\text{4}}+\frac{1}{4\cdot5}+....+\frac{1}{x\cdot\left(x+1\right)}=\frac{99}{100}\)
- Tìm x giải hộ giùm Luka nga~
\(\Leftrightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{99}{100}\)
\(\Leftrightarrow1-\frac{1}{x+1}=\frac{99}{100}\)
\(\frac{100}{100}-\frac{1}{x+1}=\frac{99}{100}\)
\(\frac{1}{x+1}=\frac{1}{100}\)
\(\Rightarrow x+1=100\)
\(x=99\)
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Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
Tìm x biết : \(\left(\frac{1}{3}\right)^x\left(\frac{1}{9}\right)^x\left(\frac{1}{27}\right)^x\left(\frac{1}{81}\right)^x\left(\frac{1}{243}\right)^x=\left(-\frac{1}{3}\right)^{30}\)
\(\left(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}\right)\cdot\left(x-\frac{1}{2}\right)=\frac{3}{4}\)
frac{4}{9}:frac{-1}{7}+6frac{5}{9}.frac{2}{3}left(frac{-1}{3}right)^4.frac{4}{11}+frac{7}{11}.left(frac{-1}{3}right)^2left(frac{-1}{7}right)^0-2frac{4}{9}:left(frac{2}{3}right)^2left(frac{1}{3}-frac{5}{6}right)^2+frac{5}{6}:2Tìm xleft(frac{3}{5}-frac{1}{2}xright)^2+812frac{7}{12}-left|frac{1}{3}-frac{1}{2}xright|frac{1}{3}frac{13}{12}-frac{1}{3}.left|frac{1}{5}-frac{1}{3}xright|frac{1}{2}Nhanh hộ mình nhaCảm ơn mn
Đọc tiếp
\(\frac{4}{9}:\frac{-1}{7}+6\frac{5}{9}.\frac{2}{3}\)
\(\left(\frac{-1}{3}\right)^4.\frac{4}{11}+\frac{7}{11}.\left(\frac{-1}{3}\right)^2\)
\(\left(\frac{-1}{7}\right)^0-2\frac{4}{9}:\left(\frac{2}{3}\right)^2\)
\(\left(\frac{1}{3}-\frac{5}{6}\right)^2+\frac{5}{6}:2\)
Tìm x
\(\left(\frac{3}{5}-\frac{1}{2}x\right)^2+8=12\)
\(\frac{7}{12}-\left|\frac{1}{3}-\frac{1}{2}x\right|=\frac{1}{3}\)
\(\frac{13}{12}-\frac{1}{3}.\left|\frac{1}{5}-\frac{1}{3}x\right|=\frac{1}{2}\)
Nhanh hộ mình nha
Cảm ơn mn