Lời giải:

PT $\Leftrightarrow \frac{x+25}{75}+1+\frac{x+30}{70}+1=\frac{x+35}{65}+1+\frac{x+40}{60}+1$

$\Leftrightarrow \frac{x+100}{75}+\frac{x+100}{70}=\frac{x+100}{65}+\frac{x+100}{60}$
$\Leftrightarrow (x+100)(\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60})=0$

Dễ thấy $\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60}<0$

$\Rightarrow x+100=0$

$\Leftrightarrow x=-100$ (tm)

b) 3.25.8+ 4.37.6+2.38.12

= 24.25+24.37+24.38

=24.(25+ 37+38)

=24.100

=2400

c) (563+745)-(463+545)

= (563-463)+(745+545)

=    100     +     100

=             200

bạn ơi cái phần c 745+545 = 1290 mà

a=10320

b=2400  

c=300

a) 35 x 34 + 35 x 38 + 65 x 75 + 65 x 45

  = 35 x (34+38)  + 65 x (75 + 45)

  = 35 x 72   +    65 x 120

  =  2520 + 7800 = 10320

b)  3 x 25 x 8 + 4 x 37 x 6 + 2 x 38 x 12

 = 3 x ( 25 x 8) + 4 x (37 x 6) + 2 x (38 x 12)

 = 3 x 200 + 4 x 222 + 2 x 456

= 600 + 888 + 912 = 2400

tk nha

35 x 34 + 35 x 38 + 65 x 75 + 65 x 45 

= 35 x ( 34 + 38 ) + 65 x ( 45 + 75 )

= 35 x 72 + 65 x 120

Vì quy tắc thực hiện tính toán phải làm nhân chia trước nên :

= (35 x 34)+(35 x 38)+(65 x 75)+(65 x 45)

= (1190 + 1330) + (4875 + 2925)

= 2520 + 7800

=10320

b) (3 x 25 x 8) +( 4 x 37 x  6) + (2 x 38 x 12)

= 600 + 888 + 912

= 2400

25 x 34 + 65 x 75 - 35 x 86 + 65 x 45

= 5 x 17 x 10 + 65 x (75 + 45) - 7 x 43 x 10

= 85 x 10 + 780 x 10 - 301 x 10

= 10 x (85 + 780 - 301)

= 10 x 564

= 5640

12000 nha bẹn iu

lộn bài

Cho \(x=\frac{1}{4}\Rightarrow2.f\left(\frac{1}{\frac{1}{4}}\right)=\left(\frac{1}{4}\right)^2\)

\(\Rightarrow2f\left(4\right)=\frac{1}{16}\Rightarrow f\left(4\right)=\frac{1}{32}\)

\(a,-\frac{9}{12}=-\frac{9:3}{12:3}=-\frac{3}{4}\)

\(\frac{-18}{-24}=\frac{\left(-18\right):\left(-6\right)}{\left(-24\right):\left(-6\right)}=\frac{3}{4}\)

\(-\frac{35}{70}=-\frac{35:35}{70:35}=\frac{1}{2}\)

\(-\frac{9}{27}=-\frac{9:9}{27:9}=-\frac{1}{3}\)

\(b,\frac{1313}{4242}=\frac{1313:101}{4242:101}=\frac{13}{42}\)

\(\frac{-353535}{-424242}=\frac{\left(-353535\right):\left(-70707\right)}{\left(-424242\right):\left(-70707\right)}=\frac{5}{6}\)

\(c,\frac{2^3\times4^3\times5^4}{8^2\times25^3\times7}=\frac{2^3\times4^3\times25^2}{8\times8^2\times25^2\times25\times7}\)         ( 4^3 = 8^2 ; 5^4 = 25^2 )

\(=\frac{1}{25\times7}=\frac{1}{175}\)

\(a.\frac{-9}{-12}=\frac{-9:3}{-12:3}=\frac{-3}{-4}.\)

\(\frac{-18}{-24}=\frac{-18:6}{-24:6}=\frac{-3}{-4}\)

\(\frac{-35}{-70}=\frac{-35:35}{-70:35}=\frac{-1}{-2}\)

\(\frac{-9}{-27}=\frac{-9:9}{-27:9}=\frac{-1}{-3}\)

a) \(\frac{-9}{12}=\frac{-9\div3}{12\div3}=\frac{-3}{4}\)

\(\frac{-18}{-24}=\frac{-18\div\left(-6\right)}{-24\div\left(-6\right)}=\frac{3}{4}\)

\(\frac{-35}{70}=\frac{-35\div35}{70\div35}=\frac{-1}{2}\)

\(\frac{-9}{27}=\frac{-9\div9}{27\div9}=\frac{-1}{3}\)

b) \(\frac{1313}{4242}=\frac{1313\div101}{4242\div101}=\frac{13}{42}\)

\(\frac{-353535}{-424242}=\frac{-353535\div\left(-70707\right)}{-424242\div\left(-70707\right)}=\frac{5}{6}\)

c)\(\frac{2^3\times4^3\times5^4}{8^2\times25^3\times7}\)= \(\frac{2^3\times4^3\times5^4}{\left(2^3\right)^2\times\left(5^2\right)^3\times7}\)= \(\frac{2^3\times4^3\times5^4}{2^6\times5^6\times7}\)= \(\frac{2^3\times4^3\times5^4}{2^3\times2^3\times5^2\times5^4\times7}\)= \(\frac{2^3\times2^3}{2^3\times5^2\times7}\)= \(\frac{8}{25\times7}\)= \(\frac{8}{175}\)

\(\left(x+5\right)\sqrt{2x^2+1}=x^2+x-5\left(đk:x\ge0\right)\)

\(< =>x\sqrt{2x^2+1}-0+5\sqrt{2x^2+1}-5=x\left(x+1\right)\)

\(< =>\frac{x^2\left(2x^2+1\right)}{x\sqrt{2x^2+1}}+\frac{25\left(2x^2+1\right)-25}{5\sqrt{2x^2+1}+5}=x\left(x+1\right)\)

\(< =>\frac{x\left(2x^2+1\right)}{\sqrt{2x^2+1}}+\frac{25.2x^2}{5\left(\sqrt{2x^2+1}+1\right)}-x\left(x+1\right)=0\)

\(< =>x\left[\frac{2x^2+1}{\sqrt{2x^2+1}}+\frac{10x}{\sqrt{2x^2+1}+1}-x-1\right]=0< =>x=0\)

đánh giá cái ngoặc to to bằng đk là được , hoặc có nghiệm nữa thì giải luôn

25 x 35 + 25 x 65

= 25 x (35 + 65)

= 25 x 100

= 2500

25 x 35 + 25 x 65

=25 x (35 + 65 )

=25 x 100

=2500

kb nha

2500 k và kết bạn nha