\(B=\frac{18\times123+9\times4567\times2+3\times5310\times6}{1+4+7+10+...+55+58-410}.\)

\(B=\frac{18\times123+9\times2\times4567+3\times6\times5310}{\left(1+4+7+10+....+55+58\right)-410}\)

\(B=\frac{18\times123+18\times4567+18\times5310}{\left(1+4+7+10+......+55+58\right)-410}\)

\(B=\frac{18\times\left(123+4567+5310\right)}{\left(1+4+7+10+....+55+58\right)-410}\)

\(B=\frac{18\times10000}{\left(1+4+7+10+....+55+58\right)-410}\)

Ta xét : 1 + 4 + 7 + 10 + .... + 55 + 58

Ta có : 4 - 1 = 3

            7 - 4 = 3

            10 - 4 = 3

           ................

            58 - 55 = 3

Vậy khoảng cách giữa 2 số liền nhau trong dãy số trên hơn kém nhau 3 đơn vị

Dãy số trên có tất cả số số hạng là :

( 58 - 1 ) : 3 + 1 = 20 ( số )

tổng của dãy số trên là :

( 58 + 1 ) x 20 : 2 = 590

Thay vào ta có :

\(B=\frac{18\times10000}{590-410}\)

\(B=\frac{180000}{180}\)

\(B=1000\)

Mình nhầm nhé : ( Mình quên chưa chia 2 )

1 + 4 + 7 + 10 + ... + 58 - 410

= ( 58 + 1 ) x [ ( 50 - 1 ) : 3 + 1 ]  : 2 - 410 

= 59 x 20 : 2 - 410

= 590 - 410 = 180

=> B = 18 000 : 180 = 100

\(A=\frac{0,8\times0,4\times1,25\times25+0,6524+0,3476}{10\times125\times4\times25\times8}\)

\(A=\frac{0,8\times1,25\times0,4\times25+0,6524+0,3476}{10\times4\times25\times8\times125}\)

\(A=\frac{1\times10+1}{10\times100\times1000}\)

\(A=\frac{11}{1000000}\)

Giúp mk với , thanks nhiều ạ

2x3x4x8x50x25x125

=(2x50)x(4x25)x(8x125)x3

=100x100x1000x3

=10000000x3=30000000

30000000 nha minh ban k cho mik mik se tra lai

a) \(\dfrac{30\times25\times7\times8}{75\times8\times12\times14}=\dfrac{3\times2\times5\times25\times7\times8}{25\times3\times8\times3\times4\times2\times7}=\dfrac{5}{3\times4}=\dfrac{5}{12}\)

b) \(\dfrac{8\times3\times4}{16\times3}=\dfrac{8\times3\times2\times2}{8\times2\times3}=2\)

c) \(\dfrac{4\times5\times6}{3\times10\times8}=\dfrac{4\times5\times3\times2}{3\times5\times2\times4\times2}=\dfrac{1}{2}\)

giúp mik với ạ, mình sẽ tick ạ! Thanks.

a) \(T=\frac{9^{14}\times25^6\times8^7}{18^{12}\times625^3\times24^3}\)

       \(=\frac{\left(3^2\right)^{14}\times25^6\times\left(2^3\right)^7}{\left(2\times3^2\right)^{12}\times\left(25^2\right)^3\times\left(3\times2^3\right)^3}\)

       \(=\frac{3^{28}\times25^6\times2^{21}}{2^{12}\times3^{24}\times25^6\times3^3\times2^9}\)

       \(=\frac{3^{28}\times25^6\times2^{21}}{\left(2^{12}\times2^9\right)\times\left(3^{24}\times3^3\right)\times25^6}\)

       \(=\frac{3^{28}\times25^6\times2^{21}}{2^{21}\times3^{27}\times25^6}=3\)

b)  \(A=\frac{5\times4^{15}\times9^9-4\times3^{20}\times8^9}{5\times2^9\times6^{19}-7\times2^{29}\times27^6}\)

        \(=\frac{5\times\left(2^2\right)^{15}\times\left(3^2\right)^9-2^2\times3^{20}\times\left(2^3\right)^9}{5\times2^9\times\left(2\times3\right)^{19}-7\times2^{29}\times\left(3^3\right)^6}\)

        \(=\frac{5\times2^{30}\times3^{18}-2^2\times3^{20}\times2^{27}}{5\times2^9\times2^{19}\times3^{19}-7\times2^{29}\times3^{18}}\)

        \(=\frac{5\times2^{30}\times3^{18}-2^{29}\times3^{20}}{5\times2^{28}\times3^{19}-7\times2^{29}\times3^{18}}\)

        \(=\frac{2^{29}\times3^{18}\times\left(5\times2-3^2\right)}{2^{28}\times3^{18}\times\left(5\times3-7\times2\right)}\)

        \(=\frac{2\times\left(10-9\right)}{15-14}=\frac{2\times1}{1}=2\)

bn nguyễn văn kiệt lm đug r

\(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}\)

\(=\frac{\left(3^2\right)^{14}.\left(5^2\right)^5.\left(2^3\right)^7}{2^{12}.\left(3^2\right)^{12}.\left(5^4\right)^3.3^3.\left(2^3\right)^3}\)

\(=\frac{3^{28}.5^{10}.2^{21}}{2^{12}.3^{24}.5^{12}.3^3.2^9}\)

\(=\frac{3^{28}.5^{10}.2^{21}}{2^{21}.3^{27}.5^{12}}\)

\(=\frac{3}{5^2}\)

\(=\frac{3}{25}\)

Ta có: \(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}=\frac{\left(3^2\right)^{14}.\left(5^2\right)^5.\left(2^3\right)^7}{\left(2.3^2\right)^{12}.\left(5^4\right)^3.\left(2^3.3\right)^3}\)\(=\frac{3^{28}.5^{10}.2^{21}}{2^{21}.3^{27}.5^{12}}=\frac{3}{5^2}=\frac{3}{25}\)