Find the value of x such that\(\frac{3}{x-2}=\frac{2}{x-3}\)
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Find the value of x such that \(\frac{3}{x-2}=\frac{2}{x-3}\)
Answer x = ......
<=>3(x-3)=2(x-2)
<=>3x-9=2x-4
<=>3x-2x=-4+9
<=>x=5
tick nha
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Find the value of x such that\(\frac{x^3}{3}=\frac{3^2}{2^3}\) .
Answer x=: .
(write your answer by decimal in simplest form)
Find the value of x such that .\(\frac{x+3}{7}=\frac{2-x}{3}\)
Answer: .x=.....
(write your answer by decimal in simplest form)
=>3(x+3)=7.(2-x)
=>3x+9=14-2x
=>3x+2x=14-9
=>5x=5=>x=1
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Find the value of x such that: \(\frac{5}{7-2x}=\frac{3}{x-3}\)
Find the value of x such that: \(\frac{3\left(x+2\right)}{2x+3}=\frac{7}{8},\left(x\ne-\frac{3}{2}\right)\) . Answer: x = ...
( write your answer by decimal in simplest form )
find the value of x such that \(\frac{x+3}{7}=\frac{2-x}{3}\)
x=?
lamf ddusng tick cho
\(\frac{x+3}{7}=\frac{2-x}{3}=>\left(x+3\right).3=\left(2-x\right).7=>3x+9=14-7x=>3x+7x=14-9=>10x=5=>x=\frac{5}{10}=\frac{1}{2}=0,5\)
vậy x=1/2=0,5
tick tớ nhé
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Find the value of x such that:\(\frac{3}{2x+7}=\frac{5}{3x+9}\)
\(x\ne-\frac{7}{2};x\ne-3\)
\(\Rightarrow3\left(3x+9\right)=5\left(2x+7\right)\)
\(\Rightarrow9x+27=10x+35\)
\(\Rightarrow10x-9x=27-35\)
\(\Rightarrow x=-8\)
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Find the value of x such that A=\(\frac{5x^2-8x+8}{2x^2}\) reaches the minimun value.
find the value of x such that x/2=x+2/3
Tìm giá trị của x sao cho x/2=x+x/3
\(x\cdot\frac{1}{2}-x=\frac{2}{3}\)
\(x=\frac{\frac{2}{3}}{-\frac{1}{2}}\)
\(x=\frac{-4}{3}\)
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