( x -1 ) ^2 / 3 = 9 / x -1
nhanh nhe mik tik
/ co nghia la a/b phan so do
Những câu hỏi liên quan
1, GIAI CAC PHUONG TRINH SAU
a, (1-x)(5x+3)= (3x-8)(1-x)
b, (x-3)(x+4)-2(3x-2)=(x-4)^2
c,x^2+ x^3+x+1=0
d, (x-3)tren x+3 -2 tren x-3 = 3x+1 tren 9-x^2
(tren co nghia la phan so nha moi nguoi)
(GIIUP EM VOI MN)
a, (1-x)(5x+3)= (3x-8)(1-x)
<=> (1-x) (5x+3) - (3x-8)(1-x) =0 <=> (1-x) (2x+11) = 0
\(\Leftrightarrow\left[{}\begin{matrix}1-x=0\\2x+11=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{11}{2}\end{matrix}\right.\)
Vậy.........
b, (x-3)(x+4)-2(3x-2)=(x-4)^2
<=> 3x = 24<=> x=8
Vậy .......
c,x^2+ x^3+x+1=0
<=> x^2 (x+1) +(x+1) =0 <=> (x^2 +1)(x+1) =0
<=> x+1 =0 => x=-1
Vậy.......
d, \(\dfrac{x-3}{x+3}-\dfrac{2}{x-3}=\dfrac{3x+1}{9-x^2}\)
\(\Leftrightarrow x^2-6x+9-2x-6=-3x-1\)
\(\Leftrightarrow x^2-5x+4=0\Leftrightarrow\left(x+4\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+4=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=1\end{matrix}\right.\)
Vậy...........
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Tim x , biet : 5 < x < 6 va
a] x la so tu nhien
b] x la so thap phan co 1 chu so o phan thap phan
Cac ban oi , giai nhanh bai nay cho minh voi , mai minh da hoc roi . Ban nao giai nhanh va dung se duoc minh bam like nhieu . Cam on cac ban nhieu nhe
a) không tồn tại số tự nhiên x
b) x= 5,1; 5,2; 5,3; 5,4; 5,5; 5,6; 5,7; 5,8; 5,9
trong cùng em học toán hả
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Tim x nguyen de moi phan so sau co gia tri la so tu nhien
a)x+6/x+1
b)x-2/x+3
Cac ban giup minh nhe !
\(a,\frac{x+6}{x+1}\)
\(\left\{\left(x+6\right)-\left(x+1\right)\right\}⋮x+1\)
\(5⋮x+1\)
\(x+1\inƯ_{\left(5\right)}=\left\{-5;5;1;-1\right\}\)
\(=>x\inƯ_{\left(5\right)}=\left\{-6;4;0;-2\right\}\)
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\(b,\frac{x-2}{x+3}\)
\(\left\{\left(x+3\right)-\left(x-2\right)\right\}⋮x+3\)
\(5⋮x+3\)\(=>x+3\inƯ_{\left(5\right)}=\left\{-5;5;-1;1\right\}\)
\(=>x\in\left\{-8;2;-4;-2\right\}\)
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Bai 1 A; 85+76+59-2B;3-56-49+3224Bai 2; Trong mot thu vien co 12 so sach la truyen thieu nhi 25 so sach la sach giao khoa con lai la cac loai sach khac tim phan so chi so sach khacBai3 ;viet phan so 78 thanh tong cua ba phan so so toi gian co mau so khac nhau Bai4; A;x :54 95+12 B;[x +34]* 57 109Bai 5 mot manh giay hinh chu nhat co chu vi la 223 dm chieu dai hon chieu rong 12 dm tinh dien tich cua manh giay do
Đọc tiếp
Bai 1
A; 8\5+7\6+5\9-2
B;3-5\6-4\9+32\24
Bai 2; Trong mot thu vien co 1\2 so sach la truyen thieu nhi 2\5 so sach la sach giao khoa con lai la cac loai sach khac tim phan so chi so sach khac
Bai3 ;viet phan so 7\8 thanh tong cua ba phan so so toi gian co mau so khac nhau
Bai4; A;x :5\4 =9\5+1\2 B;[x +3\4]* 5\7 =10\9
Bai 5 mot manh giay hinh chu nhat co chu vi la 22\3 dm chieu dai hon chieu rong 1\2 dm tinh dien tich cua manh giay do
cau 1:tinh gia tri bieu thuc
3/4 +1/1/4 *2/2/3-(-1/2)^2:6/5
cho ma co 2 dau/la hon so,con 1 dau la phan so,con ^2 la mu 2
cau 2:tim x biet
( x-1)^5= -32
cho ^5 co nghia la mu 5
a)3/4+1/1/4*2/2/3-(-1/2)^2:6/5
=3/4+5/4*8/3-1/4:6/5
=3/4+10/3-5/24=18/24+80/24-5/24=93/24=31/8
b)(x-1)^5=32=2^5
=>x-1=2
x=2+1
x=3
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bai 1.A,sap xep cac phan so sau day theo thu tu tu lon den be ;5/6,13/8,8/9 ,1/3 ,3/2 ;B,tim tat ca cac phan so sau cho mau so la so co 2 chu so . Cac ban giup to nhe .
Tim x nguyen de phan so sau co gia tri nguyen
a)\(\frac{x^2-6x-3}{x-4}\) b) \(\frac{x^2-x+1}{x+2}\)
ai nhanh mik tik!!!
a,(x-1)*(y+3)=7
b,(x+5)*(y+2)=9
c,x+y-xy=3
d,xy+3x-7x=21
e,xy-2y+3x=11
Luu y * co nghia la nhan
ai lam nhanh chinh xac mik tick cho cac ban!
Giup mik giai bai toan nay,mik tick cho^_^
a,6/7+5/8:5-3/16(-2)2;b,2/3+1/3*(-2/3+5/6):2/3;c,1/1/2x-1/2=3/4;d,-3/5+(-2/5-99)
b,Tim x
a,(2/11+1/3)*x=(1/7-1/8)*56
*luu y:dau gach / la phan so,con so ma co hai dau nhu the nay:vd:7/1/7 la hon so nhe)
\(a,\frac{6}{7}+\frac{5}{8}:5-\frac{3}{16}\cdot(-2)^2\)
\(=\frac{6}{7}+\frac{5}{8}:\frac{5}{1}-\frac{3}{16}\cdot4\)
\(=\frac{6}{7}+\frac{5}{8}\cdot\frac{1}{5}-\frac{3}{16}\cdot4\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3\cdot4}{16}\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3\cdot1}{4}\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3}{4}=\frac{48+7-42}{56}=\frac{13}{56}\)
\(b,\frac{2}{3}+\frac{1}{3}\cdot\left[\frac{-2}{3}+\frac{5}{6}\right]:\frac{2}{3}\)
\(=\frac{2}{3}+\frac{1}{3}\cdot\left[\frac{-4+5}{6}\right]:\frac{2}{3}\)
\(=\frac{2}{3}+\frac{1}{3}\cdot\frac{1}{6}:\frac{2}{3}=\frac{2}{3}+\frac{1}{3}\cdot\frac{1}{6}\cdot\frac{3}{2}=\frac{2}{3}+\frac{1}{12}=\frac{8}{12}+\frac{1}{12}=\frac{9}{12}=\frac{3}{4}\)
c, Xem lại đề
d, \(\frac{-3}{5}+\left[\frac{-2}{5}-99\right]\)
\(=\frac{-3}{5}+\frac{-497}{5}=\frac{-500}{5}=-100\)
b, Tìm x
\(\left[\frac{2}{11}+\frac{1}{3}\right]\cdot x=\left[\frac{1}{7}-\frac{1}{8}\right]\cdot56\)
\(\Rightarrow\left[\frac{2}{11}+\frac{1}{3}\right]\cdot x=\left[\frac{8}{56}-\frac{7}{56}\right]\cdot56\)
\(\Rightarrow\left[\frac{6}{33}+\frac{11}{33}\right]\cdot x=1\)
\(\Rightarrow\frac{17}{33}\cdot x=1\)
\(\Rightarrow x=1:\frac{17}{33}=1\cdot\frac{33}{17}=\frac{33}{17}\)
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