1 + 1 + 1 + 1 = 4 

Chúc bạn năm mới mạnh khỏe , học giỏi 

1 + 1 + 1 + 1 = 4

k mình nha !

Tổng 3 số là:

1 + 1 + 1 = 3

Đáp số: 3

1+1+1=3

1+1+1

=1x3

=3

\(B\)\(=\) \(\frac{1}{2015}\) + \(\frac{2}{2014}\)\(+\) ... \(+\) \(\frac{2014}{2}\) + \(\frac{2015}{1}\)

\(=\)  \(\left(1+\frac{1}{2015}\right)+\left(1+\frac{2}{2014}\right)+...+\left(1+\frac{2014}{2}\right)+\left(\frac{2015}{1}-2014\right)\)

\(=\) \(\frac{2015}{2016}+\frac{2016}{2014}+...+\frac{2016}{2}+\frac{2016}{2016}\)

\(=\)\(2016.\left(\frac{1}{2016}+\frac{1}{2015}+\frac{1}{2014}+...+\frac{1}{3}+\frac{1}{2}\right)\)

\(=\)2016

\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+...+\dfrac{1}{x}=\dfrac{127}{256}\)

Đặt VT là A

\(\Rightarrow2A=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\)

\(2A-A=\left(1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{x}\right)=\dfrac{127}{256}\)

\(\Leftrightarrow A=1-\dfrac{1}{x}=\dfrac{127}{256}\)

\(\Leftrightarrow\dfrac{1}{x}=\dfrac{129}{256}\)

\(\Rightarrow x=\dfrac{256}{129}\)

Lời giải:
$2\times A=\frac{2}{1\times 3}+\frac{2}{3\times 5}+\frac{2}{5\times 7}+...+\frac{2}{19\times 21}$
$2\times A=\frac{3-1}{1\times 3}+\frac{5-3}{3\times 5}+\frac{7-5}{5\times 7}+...+\frac{21-19}{19\times 21}$

$=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+....+\frac{1}{19}-\frac{1}{21}$

$=1-\frac{1}{21}=\frac{20}{21}$

$\Rightarrow A=\frac{20}{21}: 2= \frac{10}{21}$

= 10

tk mk nha,năn nỉ

10 nha bạn

=10

dể ợt

bn nào thấy vậy thì tk nhé

 1 + 1 + 1 + 1 + 1 + 1 = 6

mk đầu tiên nha bạn

1+1+1+1+1+1=6

tíc nha

\(1+1+1+1+1+1=6\)k tớ nha,đảm bảo sẽ k lại