\(C-D=\dfrac{\left(98^{99}+1\right)\left(98^{88}+1\right)-\left(98^{89}+1\right)\left(98^{98}+1\right)}{\left(98^{89}+1\right)\left(98^{88}+1\right)}\)

\(=\dfrac{98^{187}+98^{99}+98^{88}+1-98^{197}-98^{89}-98^{98}-1}{\left(98^{89}+1\right)\left(98^{88}+1\right)}\)

\(=\dfrac{98^{99}-98^{98}+98^{88}-98^{89}}{\left(98^{89}+1\right)\left(98^{88}+1\right)}=\dfrac{98^{98}\left(98-1\right)-98^{88}\left(98-1\right)}{\left(98^{89}+1\right)\left(98^{88}+1\right)}\)

\(=\dfrac{97.98^{98}-97.98^{88}}{\left(98^{89}+1\right)\left(98^{88}+1\right)}=\dfrac{97.98^{88}\left(98^{10}-1\right)}{\left(98^{89}+1\right)\left(98^{88}+1\right)}>0\)

\(\Rightarrow C>D\)

1+1=2

98+99=197

69+69=138

mk nha 

1+1=2

98+99=197

69+69=138

1+1=2

98+99=197

69+69=138

Giúp tớ với ngày kia tớ kiểm tra rồi

Ai đúng mk cho t**k nha! Thanks

#Bạn gì ơi,bài này có giáo viên làm rồi nhé,link đây: https://olm.vn/hoi-dap/detail/36594660334.html

#C > D

\(8624/4928+5544/4928=14168/4928=23/8\) nhé =)

\(A=\frac{98^{99}+1}{98^{89}+1}>\frac{98^{99}+1+97}{98^{89}+1+97}=\frac{98^{99}+98}{98^{89}+98}=\frac{98\left(98^{98}+1\right)}{98\left(98^{88}+1\right)}=B\)

Vậy A>B

C < D

Chắc chắn

\(C=\frac{98^{99}+1}{98^{89}+1}\)

\(D=\frac{98^{98}+1}{98^{88}+1}\)

\(C< \frac{98^{99}+1+97}{98^{89}+1+97}=\frac{98^{99}+98}{98^{89}+98}=\frac{98^{98}\left(98+1\right)}{98^{88}\left(98+1\right)}\)

\(C< \frac{98^{98}}{98^{88}}=D\)