98+69-99-88
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So sánh :
C= \(\dfrac{98^{99}+1}{98^{89}+1}\) và D = \(\dfrac{98^{98}+1}{98^{88}+1}\)
\(C-D=\dfrac{\left(98^{99}+1\right)\left(98^{88}+1\right)-\left(98^{89}+1\right)\left(98^{98}+1\right)}{\left(98^{89}+1\right)\left(98^{88}+1\right)}\)
\(=\dfrac{98^{187}+98^{99}+98^{88}+1-98^{197}-98^{89}-98^{98}-1}{\left(98^{89}+1\right)\left(98^{88}+1\right)}\)
\(=\dfrac{98^{99}-98^{98}+98^{88}-98^{89}}{\left(98^{89}+1\right)\left(98^{88}+1\right)}=\dfrac{98^{98}\left(98-1\right)-98^{88}\left(98-1\right)}{\left(98^{89}+1\right)\left(98^{88}+1\right)}\)
\(=\dfrac{97.98^{98}-97.98^{88}}{\left(98^{89}+1\right)\left(98^{88}+1\right)}=\dfrac{97.98^{88}\left(98^{10}-1\right)}{\left(98^{89}+1\right)\left(98^{88}+1\right)}>0\)
\(\Rightarrow C>D\)
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1+ 1=....
98+99=
69+69=
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De bai: So sánh.C=98^99+1/98^89+1; D=98^98+1/98^88+1.
C=98^99+1/98^89+1 va D=98^98+1/98^88+1. So sanh C va D
C=98^99+1/98^89+1 va D=98^98+1/98^88+1. So sanh C va D
Giúp tớ với ngày kia tớ kiểm tra rồi
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#Bạn gì ơi,bài này có giáo viên làm rồi nhé,link đây: https://olm.vn/hoi-dap/detail/36594660334.html
#C > D
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\(\dfrac{98}{56}\) + \(\dfrac{99}{88}\)
\(8624/4928+5544/4928=14168/4928=23/8\) nhé =)
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So sánh các phân số sau:
9899+1/9889+1 và 9899+1/9888+1
\(A=\frac{98^{99}+1}{98^{89}+1}>\frac{98^{99}+1+97}{98^{89}+1+97}=\frac{98^{99}+98}{98^{89}+98}=\frac{98\left(98^{98}+1\right)}{98\left(98^{88}+1\right)}=B\)
Vậy A>B
So sánh : C = 9899+1/9889+1
D = 9898+1/9888+1
so sánh : C=98^99+1/98^89+1
D=98^98+1/98^88+1
\(C=\frac{98^{99}+1}{98^{89}+1}\)
\(D=\frac{98^{98}+1}{98^{88}+1}\)
\(C< \frac{98^{99}+1+97}{98^{89}+1+97}=\frac{98^{99}+98}{98^{89}+98}=\frac{98^{98}\left(98+1\right)}{98^{88}\left(98+1\right)}\)
\(C< \frac{98^{98}}{98^{88}}=D\)
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