Vì |x-y+3| luôn lớn hơn hoặc bằng 0 với mọi x,y

2015(2y-3)²⁰¹⁶ lớn hơn hoặc bằng 0 với mọi x,y

=> |x-y+3|=0 và 2015(2y-3)²⁰¹⁶=0

<=> x-y+3=0 và 2y-3=0

<=>x-y+3=0 và y=3/2

Thay vào bạn sẽ tìm đc x

Nhớ k mk nha

Ta có \(|x-y+3|\ge0\forall x,y\)

\(2015\left(2y-3\right)^{2016}\ge0\forall y\)

\(\Rightarrow\hept{\begin{cases}|x-y+3|\ge0\\2015.\left(2y-3\right)^{2016}\ge0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x-y+3=0\\\left(2y-3\right)^{2016}=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x-y+3=0\\2y-3=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x-y+3=0\\2y=3\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x-y+3=0\\y=\frac{3}{2}\end{cases}}\)

Bạn thay vào tìm x

Mik cũng hok Toán 2

xc

Ta có:/x-3/^2014>=0;/6+2y/^2015>=0

=>/x-3/^2014+/6+2y/^2015>=0

mà theo đề bài, /x-3/^2014+/6+2y/^2015<=0

=>/x-3/^2014=/6+2y/^2015=0

=>/x-3/=0;       /6+2y/=0

=>x-3=0           =>6+2y=0

=>x=3              =>2y=-6=>y=-3

vậy x=3; y=-3

3 hoặc -3 đúng zồi đó

3;-3 đúng 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%

Ta có:

\(C=2\left(x-y\right)+13x^3y^2\left(x-y\right)-15xy\left(x-y\right)+1\)

=\(0+0+0+1=1\)

\(C=2x-2y+13x^3y^2\left(x-y\right)+15\left(y^2x-x^2y\right)+\left(\dfrac{2015}{2016}\right)^0\)

\(=2\left(x-y\right)+13x^3y^2\left(x-y\right)-15xy\left(x-y\right)\)

\(=0+0+1=1\)

~^~