\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=3\)

giúp tớ nhé 

tớ bị trừ 41 điểm 

cảm ơn trước

cảm ơn huhuh

\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{\left(3^4\right)^{11}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=\frac{3^1}{1}=3\)

\(\frac{81^{12}.3^{17}}{27^{10}.9^{15}}\)

= \(\frac{9^{13}.3^{17}}{3^{13}.9^{15}}\)

=  \(\frac{3^4}{9^2}\)

= \(\frac{81}{81}\)

= 1

cái này toán lớp 6 bn ơi

\(81^{11}.3^{17}=3^{61};27^{10}.9^{15}=3^{60}\Rightarrow bt=3\)

\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=3\)

\(\frac{3^{17}\cdot81^{11}}{27^{10}\cdot9^{15}}\)

\(=\frac{3^{17}\cdot\left(3^4\right)^{11}}{\left(3^3\right)^{10}\cdot\left(3^2\right)^{15}}\)

\(=\frac{3^{17}\cdot3^{44}}{3^{30}\cdot3^{30}}\)

\(=\frac{3^{61}}{3^{60}}\)

\(=3\)

\(\frac{9^2\cdot2^{11}}{16^2\cdot6^3}\)

\(=\frac{\left(3^2\right)^2\cdot2^{11}}{\left(2^4\right)^2\cdot\left(2\cdot3\right)^3}\)

\(=\frac{3^4\cdot2^{11}}{2^8\cdot2^3\cdot3^3}\)

\(=\frac{3^4\cdot2^{11}}{2^{11}\cdot3^3}\)

\(=\frac{3^4}{3^3}\)

\(=3\)

\(\frac{2^{10}\cdot3^{31}+2^{40}\cdot3^6}{2^{11}\cdot3^{31}+2^{41}\cdot3^6}\)

\(=\frac{2^{10}\cdot3^{31}+2^{40}\cdot3^6}{2\cdot\left(2^{10}\cdot3^{31}+2^{40}\cdot3^6\right)}\)

\(=\frac{1}{2}\)

3¹⁷.81¹¹/27¹⁰.9¹⁵

=3¹⁷.(3⁴)¹¹/(3³)¹⁰.(3²)¹⁵

=3¹⁷.3⁴⁴/3³⁰.3³⁰

=3⁶¹/3⁶⁰

=3

\(\frac{3^{17}.81^{11}}{27^{10}.9^{15}}=\frac{3^{17}.\left(3^4\right)^{11}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{17}.3^{41}}{3^{30}.3^{30}}=\frac{3^{17+41}}{3^{30+30}}=\frac{3^{58}}{3^{60}}=\frac{1}{3^2}=\frac{1}{9}\)

nho k day

a)10+5^4*5=10+5^5

b)2^2*9^27*2=2^3*9^27

10+5/4.5=15/20=3/4

2^2.9/27.2 = 2^2.9/ 3.9.2 = 2.1/3.1= 1/3

Sai đề bài rồi! 😋😴