\(\frac{2^5.3^6+6^5.11}{12^5-6^5.2^2}\)

\(=\frac{2^5.3^6+2^5.3^5.11}{2^2.3-2^5.3^5.2^2}\)

\(=\frac{2^5.3^5.\left(3+11\right)}{2^2.3\left(1-2^5.3^4\right)}\)

\(=\frac{2^3.3^4.14}{1-32.81}\)

\(=\frac{2^4.3^4.7}{-2591}\)

\(\frac{2^5\cdot3^6+6^5\cdot11}{12^5-6^5.2^2}\)

\(=\frac{6^5\cdot3+6^5\cdot11}{6^5\cdot2^5-6^5\cdot2^2}\)

\(=\frac{6^5\cdot\left(3+11\right)}{6^5\cdot\left(2^5-2^2\right)}\)

\(=\frac{14}{32-4}\)

\(=\frac{14}{28}=\frac{1}{2}\)

Đáp án là 1/2 nha bạn.

\(=\frac{2^5.3^5.2^2.5^2}{2^5.3^6.5}=\frac{5.2^2}{3}=\frac{20}{3}\)

5.3^x=5.3⁴

<=> 3^x=3⁴( chia cả hai vế cho 5)

<=> x=4

Câu thứ hai viết lại đề

7.3^x=5.3⁷+2.3⁷

<=> 7.3^x=3⁷.(5+2)

<=> 7.3^x=3⁷.7

<=> 3^x=3⁷(chia cả hai vế cho 7)

<=> x=7

x=10^5-10^5*3/10^5*11

x=10^5(1-3)/10^5(11)

=>x=-2/11

   3/5 . 11/7 + 3/5 . (- 4/7) + 2/5
= 3/5 . [11/7 + (- 4/7)]       + 2/5
= 3/5 .        1                     + 2/5
=          3/5                        + 2/5
=                          1

a) 5.3^x = 405

3^x = 81 = 3⁴

=> x = 4

b) 2^x : 8 = 4

2^x = 32 = 2⁵

=> x = 5

c) x⁶⁴ = x

=> x⁶⁴ - x = 0

x.(x⁶³ -1) = 0

=> x = 0

x⁶³ - 1 = 0 => x⁶³ = 1 => x = 1

KL: ...

phần d lm tương tự phần c nha bn

e) (x-2)⁵ = 243 = 3⁵

=> x - 2 = 3

x = 5

g) (x+1)³ = 125 = 5³

=> x + 1 = 5

 x = 4

\(5.3^x=405\)

\(3^x=81\)

\(3^x=3^4\)

\(=>x=4\)

\(\frac{2^5.7+2^5}{2^5+5^2-2^5.3}\)

\(=\frac{2^5.8}{5^2.3}\)

\(=\frac{32.8}{25.3}\)

\(=\frac{256}{75}\)

11/2 mink đoán thế,số thập phân thì là 5,5