\(2-\left(\frac{2}{8}+x-\frac{173}{24}\right)\text{ : }\frac{50}{3}=0\)

\(2-\left(\frac{2}{8}+x-\frac{173}{24}\right)=0\text{ x }\frac{50}{3}\)

\(2-\left(\frac{2}{8}+x-\frac{173}{24}\right)=0\)

\(\frac{2}{8}+x-\frac{173}{24}=2-0\)

\(\frac{2}{8}+x-\frac{173}{24}=2\)

\(\frac{2}{8}+x=2+\frac{173}{24}=\frac{48}{24}+\frac{173}{24}\)

\(\frac{2}{8}+x=\frac{221}{24}\)

\(x=\frac{221}{24}-\frac{2}{8}=\frac{221}{24}-\frac{6}{24}\)

\(x=\frac{215}{24}\)

(x-11/6):50/3=2

x-11/6=100/3

x=211/6

\(2-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(\left(x-\frac{11}{6}\right)\cdot\frac{3}{50}=2\)

\(\Rightarrow x-\frac{11}{6}=\frac{100}{3}\)

\(\Rightarrow x=\frac{211}{6}\)

\(2-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(2-\left(x+\frac{11}{6}\right):\frac{50}{3}=0\)

\(2-\frac{3}{50}x-\frac{11}{100}=0\)

\(\frac{3}{50}x=\frac{189}{100}\)

\(x=\frac{63}{2}\)

\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=2\)

\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{100}{3}\)

\(\Rightarrow x-\frac{11}{6}=\frac{100}{3}\)

\(\Rightarrow x=\frac{211}{6}\)

a,7.x-8=6

x-8=6:7

x-8=6/7

x=6/7+8

x=62/7

Vậy x=62/7

b, 8.(x-5)=0

x-5=0:8

x-5=0

x=0+5

x=5

Vậy x = 5

c, x -6:2-(48-24.2:6-3)=0

x-6:2-(48-48:6-3)=0

x-6:2-(48-8-3)=0

x-6:2-(40-3)=0

x-6:2-37=0

x-6:2=0+37

x-3=37

x=37+3

x=40

Vẫy=40

Tích đi mình trả lời

Ta có :

\(3^{2n}=\left(3^2\right)^n=9^n\)

\(2^{3n}=\left(2^3\right)^n=8^n\)

Vì \(9>8\)\(\Rightarrow9^n>8^n\)

Hay \(3^{2n}>2^{3n}\)

Vậy  \(3^{2n}>2^{3n}\)

_Chúc bạn học tốt_

Đề sai rồi bạn!!!
 

?????

\(=>1-\left(\frac{43}{8}+x-\frac{173}{24}\right)=0\)

\(=>\frac{43}{8}+x-\frac{173}{24}=1\)

\(=>\frac{43}{8}+x=\frac{197}{24}\)

\(=>x=\frac{17}{6}\)

=>  1 - (43/8+x-173/24) = 0

=>  43/8 + x - 173/24 = 1

=>  43/8 + x = 197/24

=>  x = 17/6

k nha

1-(43/8+x-173/24):50/3=0

a) \(\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\Leftrightarrow\frac{11}{15}x=-\frac{2}{5}\Leftrightarrow x=-\frac{6}{11}\)

b) \(\Leftrightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right).-\frac{3}{50}=1\Leftrightarrow\frac{-11}{6}+x=-\frac{50}{3}\Leftrightarrow x=-\frac{37}{2}\)