A=13!-11!

A=1.2.3....12.13-1.2.3....10.11

A=618 710 400

a)A chia hết cho 2 ( vì có số cuối là 0)

b)A chia hết cho 5( vì có số cuối là 0)

C)A chia hết cho 155( vì a>155 và 155=5.31)

a) có

b) có

c) có

a) có

b) có

c) có 

k mình nha

*13! chia hết cho 2

11! chia het cho 2=>13!-11! chia hết cho 2

*13! chia het cho 5

11! chia het cho 5=>3!-11! chia het cho 5

*155=5.31

13! ko chia hết cho 5.31

11! ko chia het cho 5.31=>13!-11! ko chia het cho 155

a)A chia hết cho 2

b)A chia hết cho 5

c)A ko chia het cho 155

**** GIÙM MÌNH NHA

a) 13! = 13.12.11....5.4.3.2.1 => 13! chia hết cho 2 và 5

11! = 11.10.9....5.4.3.2.1 => 11! chia hết cho 2 và 5

=> A = 13! - 11! chia hết cho 2 và 5

c) A = 13! - 11! = 13.12.11! - 11! = (13.12 - 1) .11! = 155.11! chia hết cho 155

Vậy A chia hết cho 155

cảm ơn Trần Thị

 Loan nhé

100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

 \(A=13!-11!\)

\(A=11!\cdot12\cdot13-11!\)

\(A=11!\left(12\cdot13-1\right)\)

\(A=11!\cdot155\)

\(\Rightarrow\)A chia hết cho 2 ( vì trong 11! chứa thừa số 2 )

         A chia hết cho 5

         A chia hết cho 155

a)A có chia hết cho 2

b)A có chia hết cho 5

c)A có chia hết cho 155

a) 13! = 13.12.11.....5.4.3.2.1 => 13! chia hết cho 2 và 5

11! = 11.10.9.....5.4.3.2.1 =>11! chia hết cho 2 và 5

=> A chia hết cho 2 và 5

c) A = 13! - 11! = 13.12.11! - 11! = ( 13.12 - 1 ) .11! = 155. 11! chia hết cho 155

Vậy A chia hết cho 155

Phần b) và a) mk gộp vào rồi nhé. Duyệt nha bạn . Chúc bạn học tốt

Ta có:

 A = 13! -11!

    = 11!(12.13-1)

    = 11! . 155

Mà 11! chia hết cho 2, 5 nên A chia hết cho 2 và 5.

Mà 155 chia hết cho 155 nên A chia hết cho 155

A = 13! - 11! = 1 . 2 . 3 . 4 . ...... . 13 - 1 . 2 . 3 . 4 . .... . 11

                    = 1 . 2 . 3 . 4 . .... . 11 ( 12 . 13 - 1 )

                    = 1 . 2 . 3 . 4 . .... . 11 ( 156 - 1 )

                    = 1 . 2 . 3 . 4 . .... . 11 . 155

    vì tích trên có chứa thừa số 2 ; 5 ; 155

=> A chia hết cho 2 ; cho 5 ; cho 155

chúc bạn học giỏi

70.a,nếu n chẵn thì n+10 chẵn chia hết cho 2,nếu n lẻ thì n+15 chẵn chia hết cho 2(vì bất kì một số nào nhân với số chẵn đều ra số chẵn)

làm tương tự vậy là được thui 

A=13!-11!=11!.(12.13-1)=11!.155=1.2.3.4.5.....11.155

vì trong tích có các thừa soos2,5,155 nên  A chia hết cho 2,5,155

Vì n là số tự nhiên nên sảy ra 2 trường hợp

+ n là số chẵn thì n có dạng 2a 

Thay n = 2a ta có : (n + 10) ( n + 15) = (2a + 10)(n + 15)

                                                          = 2(a + 5)(n + 15) chia hết cho 2 

+ n là số lẻ thì n có dạng 2a + 1 

Thay n = 2a + 1 ta có : (n + 10)(n + 15) = (2a + 11)(2a + 16)

                                                             = 2(2a + 11)(a + 8) chia hết cho 2 

Vậy với mọi số tự nhiên n thì (n + 10)(n + 15) chia hết cho 2 (đpcm)