5-[-|-4|+(-3+x-|-6|)]=15-94+|-8|-9

5-[-4+(-3+x-6)] = 15-94+8-9

5-[-4+(-3)+x-6] = (-79)+8-9

5+4-(-3) - x + 6 = -71 - 9

9-(-3) - x + 6 = -80

12 - x + 6 = -80

12-x = -80 - 6

12-x = -86

x = 12 - (-86)

x = 98

mk ko chắc lắm

5 - [ - l -4 l + ( - 3 + x - l - 6 l ) ] = 15 - 94 + l -8 l - 9

           5 - [ - 4 + ( - 3 + x - 6 ) ] = - 78 + 8 - 9

                  5 - [ - 4 - 3 + x - 6 ]  = - 70 - 9

                   5 + 4 + 3 - x + 6      = - 79

                          9 + 3 - x + 6      = - 79

                              12 - x + 6      = - 79

                           12 + ( - x ) + 6  = - 79

                                 12 + ( - x )  = - 79 - 6

                                   12 + ( - x ) = - 85

                                              - x  = - 85 - 12

                                               - x  = - 97 => x = 97

Vậy x = 97

Xin lỗi mk sai , mk tính nhầm 1 bước

\(\left(x-5\right)^4=\left(x-5\right)^6\)

\(\left(x-5\right)^4-\left(x-5\right)^6=0\)

\(\left(x-5\right)^4-\left(x-5\right)^4\cdot\left(x-5\right)^2=0\)

\(\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0\)

\(\Rightarrow\orbr{\begin{cases}x-5=0\\1-\left(x-5\right)^2=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x-5=\left\{\pm1\right\}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x=\left\{6;4\right\}\end{cases}}\)

Vậy \(x=\left\{4;5;6\right\}\)

\(\left(x-5\right)^4=\left(x-5\right)^6\)

\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

\(\left(x-5\right)^4\left[\left(x-5\right)^2-1\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^2-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\\left(x-6\right)\left(x-4\right)=0\end{cases}}\)

1: \(x-5=0\Leftrightarrow x=5\)

2.\(\left(x-6\right)\left(x-4\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-6=0\\x-4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=4\end{cases}}\)

Vậy ...

Hâm hấp bánh bao cho nóng

l x - 5 l + x - 5 = 0

l x -5 l = 5 -x

=>x-5=5-x => 2x=10 => x=5

=>x-5=-5+x => x=0

Vậy x= 0 hoặc 5

+/  \(x-5\ge0\)<=> \(x\ge5\)  => /x-5/=x-5

=> Phương trình <=> x-5+x-5=0  => 2x=10=> x=5

+/  \(x-5< 0\)<=> \(x< 5\)  => /x-5/=5-x

=> Phương trình <=> -x+5+x-5=0  => 0=0

 => Phương trình thỏa mãn với mọi x<5

Đáp số: \(x\le5\)

\(5\times95+5\times4+5\)

\(=5\times\left(95+4+1\right)\)

\(=5\times100\)

\(=500\)

5 x 95 + 5 x 4 + 5

= 5 x ( 95 + 4 + 1 )

= 5 x 100

= 500

5 x 95 + 5 x 4 + 5

= 5 x ( 95 + 4 + 1 )

= 5 x 100

= 500

Ta có \(\frac{3}{2}-\frac{5}{2}.\left(1,2x-3\right)^2=-0,9\)

\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{3}{2}+0,9\)

\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{21}{2}\)

\(\Rightarrow\left(1,2x-3\right)^2=\frac{21}{5}\)

đề sai hay mình sai ????

a) (3x + 5)² = 289

Vì \(\sqrt{289}\)= 17

=> 3x + 5 = 17

3x = 17 - 5

3x = 12

x = 12 : 3

x = 4

b) x + (x²)³ = x⁵

x + x⁶ = x⁵

x = x⁵ - x⁶

x = x^-1 = \(\frac{1}{x}\).

x=8635-5553

x=3082

k mik đi âm 1098 thật 1000000000000000000000000000000000000000000%

x = 8635 - 5553 

x = 3082

ai tk mk mk tk lại

băng 3082 nhe