Ta có : 2⁹⁸ = 2^2.49 = (2²)⁴⁹ = 4⁴⁹

Vì 4⁴⁹ < 9⁴⁹ => 2⁹⁸ < 9⁴⁹

Ta có : 3⁴⁴ = (3⁴)¹¹ = 81¹¹

            4³³ = (4³)¹¹ = 64¹¹

Vì 81¹¹ > 64¹¹ => 3⁴⁴ > 4³³

9 mũ 49=3⁹⁸>2⁹⁸

3⁴⁴=(3⁴)¹¹=81¹¹;4³³=(4³)¹¹=64¹¹=>3⁴⁴>4³³

Ta có : 2⁹⁸ = 2^2.49 = (2²)⁴⁹ = 4⁴⁹

Vì 4⁴⁹ < 9⁴⁹ => 2⁹⁸ < 9⁴⁹

Ta có : 3⁴⁴ = (3⁴)¹¹ = 81¹¹

            4³³ = (4³)¹¹ = 64¹¹

Vì 81¹¹ > 64¹¹ => 3⁴⁴ > 4³³

Sửa đề: \(C=\dfrac{17^{99}+1}{17^{99}-1}\)

\(C=\dfrac{17^{99}-1+2}{17^{99}-1}=1+\dfrac{2}{17^{99}-1}\)

\(D=\dfrac{17^{98}-1+2}{17^{98}-1}=1+\dfrac{2}{17^{98}-1}\)

17^99>17^98

=>17^99-1>17^98-1

=>C<D

3\(^4\)>\(^{4^3}\)

[100-99]\(^{2000}\)>[100+99]\(^0\)( vì theo dạng tổng quát ta có :a\(0\)=1 nên sẽ có điều như tớ làm nhé@@@@@@@@@)

A)Ta co:3^4=81

         4^3=64

        Vi 64<81

        =>3^4>4^3

B)Ta co:(100-99)^2000=1^2000=1

            (100+99)^0=199^0=1

            Vì:1=1

            =>(100-99)^2000=(100+99)^0

tk jup

b.Ta có :  = (111.3)^111.4 = ( 111⁴ . 3⁴ )¹¹¹= 

            = ( 111 . 4 )^111.3 = ( 111³.4³)111 = 

Vì (111⁴.81)¹¹¹ > ( 111³.64 )¹¹¹ => 333⁴⁴⁴ > 444³³³

a. 10³⁰ = ( 10³ )¹⁰=1000¹⁰

2¹⁰⁰ = ( 2¹⁰ )¹⁰=1024¹⁰

Vì 1000¹⁰<1024¹⁰ nên 10³⁰<2¹⁰⁰

Bạn gì ơi, bạn làm đầy đủ  ra được không ?

a)\(\left(\frac{1}{5}\right)^{10}.5^{20}=\left(\frac{1}{5}\right)^{10}.5^{10.2}=\left(\frac{1}{5}\right)^{10}.25^{10}=\left(\frac{1}{5}.5\right)^{10}=1^{10}=1\)

b)\(5^2.3^5.\left(\frac{3}{5}\right)^2=\left(\frac{3}{5}.5\right)^2.3^5=3^2.3^5=3^7\)

c)\(\left(\frac{1}{16}\right)^3:\left(\frac{1}{8}\right)^2=\left(\frac{1}{8}\right)^{2.3}:\left(\frac{1}{8}\right)^2=\left(\frac{1}{8}\right)^{6+2}=\left(\frac{1}{8}\right)^8\)

\(a.\left(\frac{1}{5}\right)^{10}.5^{20}=\left(\frac{1}{5}\right)^{10}.5^{10.2}=\left(\frac{1}{5}\right)^{10}.\left(5^2\right)^{10}=\left(\frac{1}{5}\right)^{10}.25^{10}=\left(\frac{1}{5}.25\right)^{10}=5^{10}.\)

\(b.5^2.3^5.\left(\frac{3}{5}\right)^2=\left[5^2.\left(\frac{3}{5}\right)^2\right].3^5=\left(5.\frac{3}{5}\right)^2.3^5=3^2.3^5=3^7\)\(c.\left(\frac{1}{16}\right)^3:\left(\frac{1}{8}\right)^2=\left[\left(\frac{1}{4}\right)^2\right]^3:\left[\left(\frac{1}{2}\right)^3\right]^2=\left(\frac{1}{4}\right)^6:\left(\frac{1}{2}\right)^6=\left(\frac{1}{4}:\frac{1}{2}\right)^6=\left(\frac{1}{2}\right)^6\)

333⁴⁴⁴=(111*3)⁴⁴⁴=111⁴⁴⁴*3⁴⁴⁴=111⁴⁴⁴*3^4*111=111⁴⁴⁴*81¹¹¹

444³³³=(111*4)³³³=111³³³*4³³³=111³³³*4^3*111=111³³³*64¹¹¹

Mả 111⁴⁴⁴>111³³³ ; 81¹¹¹>64¹¹¹ suy ra 333⁴⁴⁴>444³³³

333⁴⁴⁴>444³³³

333⁴⁴⁴ =( 333⁴ )¹¹¹

444³³³ = ( 444³ )¹¹¹

Theo mình nghĩ thì 333⁴⁴⁴ > 444³³³ vì 333⁴ > 444³