a) \(2.4.16.32.2^4=2.2^2.2^4.2^5.2^4=2^{16}\)

b) \(\left(4.2^5\right):\left(2^3.\frac{1}{16}\right)=\left(2^2.2^5\right):\left(2^3.\left(\frac{1}{2}\right)^4\right)=2^7:\frac{1}{2}=2^8\)

c) \(9.3^3.\frac{1}{81}.27=3^2.3^3.\left(\frac{1}{3}\right)^4.3^3=3^4\)

d)\(2^2.4.\frac{32}{2^2}.2^5=2^2.2^2.2^3.2^5=2^{12}\)

\(\frac{2^2\cdot4\cdot32}{\left(-2\right)^2\cdot2^5}=\frac{2^2\cdot4\cdot2^5}{4\cdot2^5}=2^2=4\)

\(9\cdot3^2\cdot\frac{1}{81}\cdot27=9\cdot9\cdot\frac{1}{81}\cdot27=81\cdot\frac{1}{81}\cdot27=27\)

đổi thành thùa số nguyên tố là tính được nha bn

giúp mk vs

2^n/32 = 4 => 2^n = 4 . 32 = 128 => n =7

27^n . 9^n = 9^27 . 81 

=> (27.9)^n = 9^27 . 9^2

=> 243^n = 9^54

=> 243^n = 243^1458

vay n=1458

1/9 . 3^4 . 3^n+1 = 9^4

=> 9 . 3^n+1 = 6561

=> 3^n+1 = 6561 /9

=> 3^n+1 = 729

=> n = 5

\(a.\frac{2^n}{32}=4\Rightarrow2^n=32.4=128=2^7\Rightarrow n=7\)

\(b.27^{n^{ }}.9^n=9^{27}:81\Rightarrow3^{3n}.3^{2n}=3^{54}:3^4\)

\(\Rightarrow3^{5n}=3^{50}\Rightarrow n=50:5=10\)

\(c.\frac{1}{9}.3^4.3^{n+1}=9^4\Rightarrow\frac{1}{3^2}.3^4.3^{n+1}=3^8\)

\(\Rightarrow3^2.3^{n+1}=3^8\Rightarrow3^{n+1}=3^6\Rightarrow n=6-1=5\)

a/\(2.4.16.32.2^4=2.2^2.2^4.2^5.2^4=2^{16}\)

b/\(9.3^3.\dfrac{1}{81}=3^2.3^3.3^{-4}=3\)

a) \(2\cdot4\cdot16\cdot32\cdot2^4\)

\(=2^1\cdot2^2\cdot2^4\cdot2^5\cdot2^4\)

\(=2^{16}\)

b) \(9\cdot3^3\cdot\dfrac{1}{81}\cdot27\)

\(=3^2\cdot3^3\cdot3^{-4}\cdot3^3\)

\(=3^4\)

9.3^x+1= 81

3^2.3^x+1= 81

3^x+3=81

3^x+3=3^4

Suy ra x+3=4

               x= 4-3

               x=1

\(9.3^{x+1}=81\)

\(\Rightarrow3^{x+1}=81:9\)

\(\Rightarrow3^{x+1}=9\)

\(\Rightarrow3^{x+1}=3^2\)

\(\Rightarrow x+1=2\)

\(\Rightarrow x=1\)

Đề có phải là thế này ko

9.3^9.\(\frac{1}{81}\)

9.3².1/81.9.3 <=> 9²/81. 3³= 3³

4.32:(2³.1/2⁴) <=> 4.4².2.2 <=> 4.4².4 = 4⁴

3⁴.3⁵:1/27 = 3⁴.3⁵.3³= 3¹²