43 - ( 24 - x ) = 20
43-[24-x]=20
43-[24-x]=20
=>24-x= 43-20 = 23
=>x = 24 - 23 = 1
Vậy....
43-(24-x)=20
=> 24-x =43-20
=> 24-x =13
=> x =24-13
=> x =11
43 - I24-xI = 20
I24-xI = 43 - 20
I24-xI = 23
TH1 : 24 - x = 23
x = 24 - 23
x= 1
TH2 : 24 - x = (-23)
x = 24 -(-23)
x = 24 + 23
x = 77
Vậy X = 1 ; 77
học tốt @
43-(24-x)=20
43-(24-x)=20
=> 24-x = 43-20
=> 24-x = 23
=> x= 24-23
=> x= 14
43 - (24 - x) = 20
24 - x = 43 - 20
24 - x = 23
x = 24 - 23
x = 1
43 - ( 24 - x ) = 20
đề :
24 -x = 43-20
24 -x = 23
x =24 -23
x=1
43 - ( 24 - x ) = 20
=> 43 - 24 + x = 20
=> 19 + x = 20
=> x = 20 - 19
=> x = 1
Vậy x = 1
43 - ( 24 - x ) = 20
24 -x =43-20
24-x =23
x =24-23
x =1
chuk bn hok tốt
43 - × (24 - x) = 20
Tìm x
có 1 dấu nhân ở đây
43-(24-x)=20
43 - ( 24 - x ) = 20
24 - x = 43 - 20
24 - x = 23
x = 24 - 23
x = 1
43-(24-x)=20
43 - ( 24 - x ) = 20
24 - x = 43 - 20
24 - x = 23
x = 24 - 23
x = 1
43-(24-x)=20 24-x=43-20 24-x=23 x=1
43 - ( 24 - x ) = 20
Ai nhanh mình tick
43 - ( 24 - x ) = 20
24 - x = 43 - 20
24 - x = 23
x = 24 - 23
x = 1
43 - ( 24 - x ) = 20
( 24 - x ) = 43 - 20
24 - x = 23
x = 24 - 23
x = 1
Bài 2.Tìm x
d,43-(24-x)=20
e,20-(x+14)=5
f,15:(x-3)=3
Bài 2:
d, 43-(24-x)=20
<=>43-24+x=20
<=>19+x=20
<=>x=20-19=1
Vậy x=1
e, 20-(x+14)=5
<=> 20-x-14=5
<=>6-x=5
<=>x=6-5=1
Vậy x=1
f,15:(x-3)=3
<=> x-3=15:3=5
<=>x=5+3
<=>x=8
Vậy x=8
\(d,43-\left(24-x\right)=20\)
\(24-x=23\)
\(x=1\)
\(e,20-\left(x+14\right)=5\)
\(x+14=15\)
\(x=1\)
\(f,15:\left(x-3\right)=3\)
\(x-3=5\)
\(x=8\)
Các bạn giúp mình với :
Tìm x:
25 + (15 - x) = 30
43 - (24 - x) = 20
24 + 3 (5 - x) = 27
25+(15-x)=30 43-(24-x)=20 24+3(5-x)=27
(15-x)=25+30=55 (24-x)=43-20=23 3(5-x)=27-24=3
x =55-15=40 x =24-23=1 (5-x)=3:3=1
x =5-1=4
Hok tốt!
@Kaito Kid
Mình cần các bạn giúp gấp.
( 1225 + 625 ) - 4x = 1000 - 150
43 - ( 24 - x ) = 20
245 - 5 (16 + x ) = 140
(1225 + 625) - 4x = 1000 - 150
=> 1850 - 4x = 950
=> 4x = 1850 - 950
=> 4x = 900
=> x = 900 : 4
=> x = 225
b) 43 - (24 - x) = 20
=> 24 - x = 43 - 20
=> 24 - x = 23
=> x = 24 - 23
=> x = 1
c) 245 - 5(16 + x) = 140
=> 5(16 + x) = 245 - 140
=> 5(16 + x) = 105
=> 16 + x = 105 : 5
=> 16 + x = 21
=> x = 21 - 16
=> x = 5
\(a,\)\(\left(1225+625\right)-4x=1000-150.\)
\(\Rightarrow1850-4x=850\)\(\Rightarrow4x=1850-850=1000\)
\(b,43-\left(24-x\right)=20\)
\(\Rightarrow43-24+x=20\)\(\Rightarrow19+x=20\Leftrightarrow x=1\)
\(c,245-5\left(16+x\right)=140\)
\(\Rightarrow245-80-5x=140\)
\(\Rightarrow165-5x=140\Leftrightarrow5x=165-140=25\Leftrightarrow x=5\)