100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5

\(140-100:x=120\)

\(\Leftrightarrow100:x=20\)

hay x=5

a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.

b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.

c) x :  7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.

d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.

e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.

g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135

a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.

b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.

c) x :  7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.

d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.

e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.

g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135

           Bài làm :

\(a\text{)}...\Leftrightarrow\orbr{\begin{cases}x\div7-7=0\\x.3-12=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x\div7=7\\x.3=12\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=49\\x=4\end{cases}}\)

\(b\text{)}\Leftrightarrow...\Leftrightarrow x\div2=15\Leftrightarrow x=15.2=30\)

\(c\text{)}...\Leftrightarrow100\div x=20\Leftrightarrow x=100\div20=5\)

\(d\text{)}...\Leftrightarrow x\div5=27\Leftrightarrow x=27.5=135\)

\(180-\left(x-45\right)\div2=120\)

\(\left(x-45\right)\div2=180-120\)

\(\left(x-45\right)\div2=60\)

\(x-45=60\times2\)

\(x-45=120\)

\(x=120+45\)

\(x=165\)

\(\left(2009-x\right)\div29+32=100\)

\(\left(2009-x\right)\div29=100-32\)

\(\left(2009-x\right)\div29=68\)

\(2009-x=68\times29\)

\(2009-x=1972\)

\(x=2009-1972\)

\(x=37\)

\(\left(x-2\right)\times3-270\div45=120\)

\(\left(x-2\right)\times3-6=120\)

\(\left(x-2\right)\times3=120+6\)

\(\left(x-2\right)\times3 =126\)

\(x-2=126\div3\)

\(x-2=42\)

\(x=42+2\)

\(x=44\)

\(\left(x+0,2\right)+\left(x+0,7\right)+\left(x+1,2\right)+...+\left(x+4,2\right)+\left(x+4,7\right)=65,5\)

\(\left(x+x+x+..+x+x\right)+\left(0,2+0,7+1,2+...+4,2+4,7\right)=65,5\)

\(10x+\frac{\left(0,2+4,7\right)\times10}{2}=65,5\)

\(10x+24,5=65,5\)

\(10x=65,5-24,5\)

\(10x=41\)

\(\Rightarrow x=4,1\)

a)50 + x = 180 - 120

 50 + x = 60

 x = 60-50 

 x = 10

b)20-x = 150-140

 20-x = 10

x = 20-10

x = 10

c) 25+x = 100-40

25+x=60

x= 60-25

x=35

d) 100+x =130-25

100+x = 105

x = 105-100

x = 5

e) 143+x = 174-22

143+x = 152

x = 152-143

x = 9 

ỦNG HỘ MK NHÁ

120 + ( 50 + x ) = 180

50 + x = 180 - 120

50 + x = 60

x = 60 - 50

x = 10

140 + ( 20 - x ) = 150

20 - x = 150 - 140

20 - x = 10

x = 20 - 10

x = 10

100 - ( 25 + x ) = 40

25 + x = 100 - 40

25 + x = 60

x = 60 - 25

x = 35

130 - ( 100 + x ) = 25

100 + x = 130 - 25

100 + x = 105

x = 105 - 100

x = 5

174 - ( 143 + x ) = 22

143 + x = 174 - 22

143 + x = 152

x = 152 - 143

x = 9

k mk nha 

Thanks nhìu

\(120+\left(50+x\right)=180\)

\(\Rightarrow50+x=180-120\)

\(\Rightarrow50+x=60\)

\(\Rightarrow x=60-50=10\)

Vậy x = 10

\(140+\left(20-x\right)=150\)

\(\Rightarrow20-x=150-140\)

\(\Rightarrow20-x=10\)

\(\Rightarrow x=20-10=10\)

Vậy x =x10

\(100-\left(25+x\right)=40\)

\(\Rightarrow25+x=100-40\)

\(\Rightarrow25+x=60\)

\(\Rightarrow x=60-25=35\)

Vậy x = 35

\(130-\left(100+x\right)=25\)

\(\Rightarrow100+x=130-25\)

\(\Rightarrow100+x=105\)

\(\Rightarrow x=105-100=5\)

Vậy x = 5

\(174-\left(143+x\right)=22\)

\(\Rightarrow143+x=174-22\)

\(\Rightarrow143+x=152\)

\(\Rightarrow x=152-143=9\)

Vậy x = 9

TL

a)    5x + 20 = 110      

<=> x = 90 : 5 = 18

 b) x + 18 = - 13 

 <=> x = - 31

  c) 120 - x =  50   

   <=> x = 70     

 d) 10 - x = -29  

     <=>  x = 39

e) - x + 31 = 61

<=> x = -30

f) -85 - x = --70

<=> x = 15

Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!

giúp mk nhé

\(A,x-218=297\)

\(\Leftrightarrow x=297+218=515\)

\(B,469+x=1234\)

\(\Leftrightarrow x=1234-469=765\)

\(C,\left(x-25\right).13=0\)

\(\Leftrightarrow x-25=\frac{0}{13}=0\)

\(\Leftrightarrow x=0+25=25\)

\(D,140-\frac{100}{x}=120\)

\(\Leftrightarrow\frac{100}{x}=140-120=20\)

\(\Leftrightarrow20x=100\)

\(\Leftrightarrow x=\frac{100}{20}=5\)