tự lm đi bn ơi, phụ thuộc quá

5 * 5 * 5* 5 * 5 = 3125

5 * 3 * 10 = 150

1 * 2 * 3 * 4 = 24.

5 x 5 x 5 x 5 x 5 = 3125

5 x 3 x 10 = 150

1x 2 x 3 x 4 = 24

Ủng hộ nha !!!!!~~~

5 mũ 56,nha bạn

kết quả là 5 ^ ⁵⁶

Ta có : 5²⁵.5^x+1=5²⁵

=> 5^x+1=5²⁵:5²⁵

=> 5^x+1=1

=> 5^x=\(\frac{1}{5}\)\(=\frac{1}{5^1}\)

=> 5^x=5^-1

=> x=-1

x=-1

= 0 nhé

mik chỉ k cho 2 người thôi nhé

0 vì trong đó có 1 thừa số là 0 nên tích cũng bằng 0

 ket qua bang 0 nhe ban.

5 x 5 x5 x 5 x 5x 5x 5x 5x0 x5x2512000051515145163

Vì trong 1 biếu thức chỉ có phép nhân có chứa thừa số 0

Thì => tích đó bằng 0

 = (62x5)x(4x25)+ (62x5)x(4x25)

= 310x100+310x100

= 100x(310+310)

= 62000

mình nha bạn

a x+\(\frac{1}{2}\)=\(\frac{5}{7}\)

x=\(\frac{5}{7}\)-\(\frac{1}{2}\)

x=\(\frac{3}{14}\)

b \(\frac{25}{7}\)-x=\(\frac{8}{9}\)

x=\(\frac{25}{7}\)-\(\frac{8}{9}\)

x=\(\frac{169}{43}\)

c \(\frac{15}{11}\)*x=\(\frac{5}{3}\)

x=\(\frac{5}{3}\):\(\frac{15}{11}\)

x=\(\frac{11}{9}\)

D x*\(\frac{5}{12}\)=\(\frac{8}{9}\)

x=\(\frac{8}{9}\):\(\frac{5}{12}\)

x=\(\frac{32}{15}\)

a) \(x+\frac{1}{2}=\frac{5}{7}\)

\(x=\frac{5}{7}-\frac{1}{2}\)

\(x=\frac{10}{14}-\frac{7}{14}\)

\(x=\frac{3}{14}\)

b) \(\frac{25}{7}-x=\frac{8}{9}\)

\(x=\frac{25}{7}-\frac{8}{9}\)

\(x=\frac{225}{63}-\frac{56}{63}\)

\(x=\frac{169}{63}\)

c) \(\frac{15}{11}\cdot x=\frac{5}{3}\)

\(x=\frac{5}{3}:\frac{15}{11}\)

\(x=\frac{5}{3}\cdot\frac{11}{15}\)

\(x=\frac{11}{9}\)

d) \(x\cdot\frac{5}{12}=\frac{8}{9}\)

\(x=\frac{8}{9}:\frac{5}{12}\)

\(x=\frac{8}{9}\cdot\frac{12}{5}\)

\(x=\frac{32}{15}\)

a) x + 1/2 = 5/7

  x           = 5/7 - 1/2 

   x          =3 /14

b) 25/7 - x  =  8/9

              x = 25/7 - 8/9

              x = 169/63

c) 15/11 * x   = 5/3

            x       = 5/3 : 15/11

           x        = 11/9

d)  x * 5/12      = 8/9

     x                 = 8/9 : 5/12 

 x                      = 32/15

\(\dfrac{22}{5}\times\dfrac{6}{121}\times\dfrac{11}{4}\times\dfrac{3}{5}\times\dfrac{1}{3}\times\dfrac{5}{4}\)

\(=\left(\dfrac{22}{5}\times\dfrac{5}{4}\right)\times\left(\dfrac{6}{121}\times\dfrac{11}{4}\right)\times\left(\dfrac{3}{5}\times\dfrac{1}{3}\right)\)

\(=\dfrac{11}{2}\times\dfrac{3}{22}\times\dfrac{1}{5}\)

\(=\dfrac{3}{20}\)

\(=\dfrac{22\times6\times11\times3\times1\times5}{5\times121\times4\times5\times3\times4}=\dfrac{11\times2\times6\times11\times1}{11\times11\times4\times5\times4}=\dfrac{2\times6\times1}{4\times5\times4}=\dfrac{18}{100}=\dfrac{9}{50}\)