( 7x - 11)³ = 1000

=> (7x - 11)^3 = 10^3

=> 7x - 11 = 10

7x = 21

x = 3

(7.x  - 11)³ = 2⁵ . 5² + 200

(7.x - 11)³ = 1000

(7.x - 11)³ = 10³

=> 7.x - 11 = 10

=> 7.x = 10 + 11

=> 7.x = 21

=> x = 21 : 7 = 3

(7.x  - 11)³ = 2⁵ . 5² + 200

=>(7.x - 11)³ = 1000

=>(7.x - 11)³ = 10³

=> 7.x - 11 = 10

=> 7.x = 10 + 11=21

=> x = 21 : 7 = 3

vậy x=3

\(10^x+39=5y\)

\(5y-10^x=39\)

Vì \(Ư\left(39\right)\in\left\{1;3;13;39\right\}\)

\(\Rightarrow x=0\)

Thế x = 0, ta có:

\(5y-1=39\)

\(5y=39+1\)

\(5y=40\)

\(y=40:5\)

\(y=8\)

Vậy:\(x=0,y=8\)

x=0;y=8

bn cho mik xin cách làm

=40 yến = 4 tạ

12 yến+28 yến =.4..tạ 

Thank you các bn nha.Mãi iu các bn

\(x.125^3=25^3\)

\(\implies x.(5^3)^3=(5^2)^3 \)

\(\implies x.5^{27}=5^6\)

\(\implies x=5^6:5^{27}\)

\(x.125^3=25^3\)

\(\Rightarrow x.\left(5^3\right)^3=\left(5^2\right)^3\)

\(\Rightarrow x.5^9=5^6\)

\(\Rightarrow x=\frac{5^6}{5^9}=\frac{1}{125}\)

Vậy x = 1/125

x . 125³ = 25³

x = 25³ ÷125³

x = 15625 ÷ 1953125

x = 8×10^-3

3.12:0.25+12.48*3-3.12*6

=3.12*4+3.12*12-3.12*6

=3.12*(4+12-6)

=3.12*10

=31.2

= 3,12 x 4 + 3,12 x 4 x 3 - 3,12 x 6

= 3,12 x 4 +3,12 x 12 - 3,12 x 6

= 3,12 x ( 4 + 12 - 6 )

= 3,12 x 10

= 31,2

    3,12 : 0,25 + 12,48 x 3 - 3,12 x 6

=  3,12 x 4 + 3,12 x ( 4 x 3 ) - 3,12 x 6

= 3,12  x 4 + 3,12 x 12 - 3,12 x 6

= 3,12 x ( 4 + 12 - 6 )

= 3,12 x         10

= 31,2

3,12 : 0,25 + 12,48 x 3 - 3,12 x 6

=3,12 : 1/4 + 3,12 x 4 x 3 - 3,12 x 6

=3,12 x 4 + 3,12 x 12 - 3,12 x 6

=3,12 x (4 + 12 - 6)

=3,12 x 10

=31,2

   3,12 : 0,25 +12,48 x 3 - 3,12 x 6

= 3,12 x 4 + 3,12 x 12 - 3,12 x 6

=3,12 x (4 + 12- 6)

=3,12 x 10

= 31,2

\(\frac{10}{7}\cdot\frac{2}{3}+\frac{5}{6}:\frac{3}{10}-\frac{2}{3}\cdot\frac{3}{7}\)

\(=\left(\frac{10}{7}\cdot\frac{2}{3}-\frac{2}{3}\cdot\frac{3}{7}\right)+\frac{5}{6}\cdot\frac{10}{3}\)

\(=\frac{2}{3}\left(\frac{10}{7}-\frac{3}{7}\right)+\frac{5\cdot10}{6\cdot3}\)

\(=\frac{2}{3}\cdot1+\frac{25}{9}\)

\(=\frac{2}{3}+\frac{25}{9}\)

\(=\frac{31}{9}\)

\(\frac{1}{7}\cdot\frac{2}{3}+\frac{5}{6}:\frac{3}{10}-\frac{2}{3}\cdot\frac{3}{7}\)

\(=\left(\frac{1}{7}\cdot\frac{2}{3}-\frac{2}{3}\cdot\frac{3}{7}\right)+\frac{5}{6}\cdot\frac{10}{3}\)

\(=\frac{2}{3}\cdot\left(-\frac{2}{7}\right)+\frac{5}{3}\cdot\frac{5}{3}\)

\(=-\frac{4}{21}+\frac{25}{6}=\frac{167}{42}\)

Xin lỗi không nhanh được 

Bạn ơi câu này trả lời r mà

\(\frac{x}{-11}=\frac{-11}{x}\)

\(\Rightarrow x^2=\left(-11\right)^2\)

\(\Rightarrow x^2=\left(-11\right)^2=11^2\)

\(\Rightarrow\orbr{\begin{cases}x=11\\x=-11\end{cases}}\)  ( thỏa mãn x nguyên ) 

Vậy \(x\in\left\{11;-11\right\}\)

!!! K chắc

@ Học tốt

Chiyuki Fujito

\(\frac{x}{-11}=\frac{-11}{x}\)

=>x.x=(-11).(-11)

=>x²=(-11)²=11²

=>x=-11  hoặc x=11

Vậy x\(\in\){-11;11}

Chúc bn học tốt

\(\frac{x}{-11}=-\frac{11}{x}\)

\(\Rightarrow x.x=-11.\left(-11\right)\)

\(x^2=121\)

\(x^2=11^2\)

\(\Rightarrow x=\pm11\)

Vậy \(x=\pm11\)