\(\frac{2}{3}\) .\(\frac{3}{4}\)\(\le\)\(\frac{x}{18}\) \(\le\)\(\frac{7}{3}\).\(\frac{1}{3}\)

\(\frac{1}{2}\le\frac{x}{18}\le\frac{7}{9}\)

\(\frac{9}{18}\le\frac{x}{18}\le\frac{14}{18}\)

\(\Rightarrow x\in\){9:10;11;12;13;14}

\(\frac{2}{3}.\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\le\frac{x}{18}\le\frac{7}{3}.\left(\frac{1}{2}-\frac{1}{6}\right)\)

\(\frac{2}{3}.\left(\frac{5}{4}-\frac{1}{3}\right)\le\frac{x}{18}\le\frac{7}{3}.\frac{1}{3}\)

\(\frac{2}{3}.\frac{11}{12}\le\frac{x}{18}\le\frac{7}{9}\)

\(\frac{11}{18}\le\frac{x}{18}\le\frac{7}{9}\)

\(\frac{11}{18}\le\frac{x}{18}\le\frac{14}{18}\)

Vậy \(x\in\left\{11;12;13\right\}\)

\(\frac{2}{3}\cdot\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\le\frac{x}{18}\le\frac{7}{3}\cdot\left(\frac{1}{2}-\frac{1}{6}\right)\)

\(\frac{2}{3}\cdot\left(\frac{2}{4}+\frac{3}{4}-\frac{1}{3}\right)\le\frac{x}{18}\le\frac{7}{3}\cdot\left(\frac{3}{6}-\frac{1}{6}\right)\)

\(\frac{2}{3}\cdot\left(\frac{5}{4}-\frac{1}{3}\right)\le\frac{x}{18}\le\frac{7}{3}\cdot\frac{1}{3}\)

\(\frac{2}{3}\cdot\left(\frac{15}{12}-\frac{4}{12}\right)\le\frac{x}{18}\le\frac{7}{9}\)

\(\frac{2}{3}\cdot\frac{11}{12}\le\frac{x}{18}\le\frac{7}{9}\)

\(\frac{11}{18}\le\frac{x}{18}\le\frac{14}{18}\)

Để \(x\)phải nhỏ hơn hoặc bằng thì x lần lượt bằng \(\left\{11;12;13;14\right\}\)

Câu 2 : 

\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)

\(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{25}{100}\right).\frac{24}{47}-\frac{51}{13}:3\)

\(\frac{28}{15}.\frac{3}{4}-\frac{47}{60}.\frac{24}{47}-\frac{51}{13}:3\)

\(\frac{7}{5}-\frac{2}{5}-\frac{51}{13}.\frac{1}{3}\)

\(\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)

\(-\frac{4}{13}\)

Câu 1:

\(-\frac{13}{9}\le x\le-\frac{1}{2}\)

\(x=-1\)

đố mày làm được mà còn cho bọn tao làm 

Ta có: \(-4\frac{1}{3}\left(\frac{1}{2}-\frac{1}{6}\right)=\frac{-13}{3}.\frac{1}{3}=-\frac{13}{9}=\frac{-26}{18}\)

\(-\frac{2}{3}\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)=\frac{-2}{3}.\frac{-11}{12}=\frac{11}{18}\)

Mà \(\frac{-26}{18}\le x\le\frac{11}{18}\)

\(\Rightarrow x=\left\{\frac{-26}{18};\frac{-25}{18};\frac{-24}{18};.....;\frac{10}{18};\frac{11}{18}\right\}\)

\(a,4\frac{1}{3}\left[\frac{1}{2}-\frac{1}{6}\right]\le x\le-\frac{2}{3}\left[\frac{1}{3}\cdot\frac{1}{2}-\frac{3}{4}\right]\)

=> \(\frac{13}{3}\left[\frac{3}{6}-\frac{1}{6}\right]\le x\le-\frac{2}{3}\left[\frac{1}{6}-\frac{3}{4}\right]\)

=> \(\frac{13}{3}\cdot\frac{1}{3}\le x\le-\frac{2}{3}\cdot\left[\frac{2}{12}-\frac{9}{12}\right]\)

=> \(\frac{13}{9}\le x\le-\frac{2}{3}\cdot\left[-\frac{7}{12}\right]\)

=> \(\frac{13}{9}\le x\le-\frac{1}{3}\cdot\left[-\frac{7}{6}\right]\)

=> \(\frac{13}{9}\le x\le\frac{7}{18}\)

Đến đây tự tìm x 

\(4\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{6}\right)\le x\le\frac{2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{1}{4}\right)\)

\(\Rightarrow\frac{13}{3}.\frac{1}{3}\le x\le\frac{2}{3}.\frac{-5}{12}\)

\(\Rightarrow\frac{13}{9}\le x\le\frac{-5}{18}\)

\(\Rightarrow\frac{26}{18}\le x\le\frac{-5}{18}\)

=> Không tìm được x

nhanh len nha. minh k cho

thiếu dấu ngoặc rồi thánh!

\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le x\le\frac{2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)

       \(\frac{13}{3}.\frac{-1}{3}\)   \(\le x\le\frac{2}{3}.\frac{-11}{12}\)

         \(\frac{-13}{9}\)        \(\le x\le\) \(\frac{-11}{18}\)

         \(\frac{-26}{18}\)     \(\le\frac{18x}{18}\le\frac{-11}{18}\)

Suy ra \(-26\le18x\le-11\)

\(\rightarrow x=-1\)

Vậy x = -1

a) \(-4\frac{3}{5}\cdot2\frac{4}{23}\le x\le-2\frac{3}{15}:1\frac{6}{15}\)

=> \(-\frac{23}{5}\cdot\frac{50}{23}\le x\le\frac{-33}{15}:\frac{21}{15}\)

=> \(-10\le x\le\frac{-11}{7}\)

=> \(x\in\left\{-10;-9,-8,-7,-6,-5,-4,-3,-2,-1\right\}\)

-4/1/3.1/3< x <  -2/3.-11/12

-1/4/9< x < 11/18

-26/18< x < 11/18

Vậy x={-26/18;-25/18;.............;11/18}