2;4;6;8;...;16;18 có : 9 số hạng

Tổng của 9 số hạng đó là :

\(\frac{\left(18+2\right).9}{2}=90\)

\(\Rightarrow A=\frac{-45.58-45.42}{2+4+6+...+16+18}\)

\(A=\frac{-45.\left(58+42\right)}{90}=\frac{-45.100}{90}=-\frac{4500}{90}\)\(=-50\)

\(\frac{-45.58-45.42}{2+4+6+...+16+18}=\frac{-45.\left(42+58\right)}{2+4+6+...+16+18}=\frac{-45.100}{2+4+6+...+16+18}=\frac{-4500}{2+4+6+...+16+18}\)

Ta có:2+4+6+...+18

Dãy số trên có:(18-2):2+1=9(số)

Tổng dãy trên là:(18+2).9:2=90

=>\(\frac{-4500}{2+4+6+...+16+18}=-\frac{4500}{90}=-50\)

\(\frac{-45.58-45.42}{2+4+6+...+18}=\frac{-45\left(58+42\right)}{20.9}=\frac{-45.100}{180}=-\frac{4500}{180}=-25\)

A = 45(-58-42)   /   (2=18).9:2= -5

a) \(A=\dfrac{-45.58-45.42}{2+4+6+...+16+18}\)

\(A=-\dfrac{45\left(58+42\right)}{\dfrac{\left(18-2\right):2+1}{2}.\left(2+18\right)}\)

\(A=\dfrac{-45.100}{\dfrac{5}{2}.20}\)

\(A=-\dfrac{45.100}{50}\)

\(A=-90\)

b) \(1-\left[\left(5\dfrac{3}{8}+x-7\dfrac{5}{24}\right):\left(-16\dfrac{2}{3}\right)\right]=0\)

\(\Rightarrow\left(5\dfrac{3}{8}+x-7\dfrac{5}{24}\right):\left(-16\dfrac{2}{3}\right)=1\)

\(\Rightarrow\left(\dfrac{43}{8}+x-\dfrac{173}{24}\right):\left(-\dfrac{46}{3}\right)=1\)

\(\Rightarrow\left(\dfrac{129}{24}-\dfrac{173}{24}+x\right).\left(-\dfrac{3}{46}\right)=1\)

\(\Rightarrow\left(-\dfrac{44}{24}+x\right).\left(-\dfrac{3}{46}\right)=1\)

\(\Rightarrow\left(-\dfrac{11}{6}+x\right).\left(-\dfrac{3}{46}\right)=1\)

\(\Rightarrow-\dfrac{11}{6}+x=1.\left(-\dfrac{46}{3}\right)\)

\(\Rightarrow-\dfrac{11}{6}+x=-\dfrac{46}{3}\)

\(\Rightarrow x=-\dfrac{46}{3}+\dfrac{11}{6}\)

\(\Rightarrow x=-\dfrac{92}{6}+\dfrac{11}{6}\)

\(\Rightarrow x=-\dfrac{81}{6}\)

\(\Rightarrow x=-\dfrac{27}{2}\)

Chả hiểu cái yêu cầu..

Thôi cứ làm nhé.

Ta tách ra làm 2 phần để tính:

(1) 45.8 - 45.42 = -1530

(2) 2 + 4 + 6 +...+ 16 + 18

Số số hạng là: ( 18 - 2 ) : 2 + 1 = 9 (số)

Tổng là: ( 18 + 2 ) x 9 : 2 = 90 

Ghép lại có: \(-\frac{1530}{90}=-17\)

tính 2+4+6+...+18

daỹ tính trên có ssh là (18+2):2+1=11(ssh)

tổng bằng:(2+18).11:2=110

A=45.8+45.42/110

A=45.(8+42)/110

A=45.50/110

A=225/11

A=20 5/11(HỖN SỐ)

\(A=\frac{45.\left(8+42\right)}{\left(18+2\right).9:2}=\frac{45.50}{90}=25\)

\(\Rightarrow A=\frac{45.\left(8+42\right)}{\left(18+2\right).9:2}\)

\(\Rightarrow A=\frac{45.50}{20.9:2}\)

\(\Rightarrow A=\frac{45.50}{20:2.9}\)

\(\Rightarrow A=\frac{45.50}{10.9}\)

\(\Rightarrow A=5.5=25\)

A=25 k mk ha