a) {132 - [116- (16 - 8)]:2}.5

= [132 - (116 - 8): 2] .5

= (132 - 108 : 2). 54

= (132 - 54).5

= 78.5 = 390

b) 36: {136 : 200 - (12+ 8. 20)]}

= 36: {336 : [200 - ( 12 + 160)]}

= 36 : [336 : ( 200 - 172)

= 36 : ( 336 : 28) = 3

c) 86 - [15. (64 - 39): 75+11] 

= 86 - (15.25 : 75 + 11) 

= 86 - ( 5 + 11) 

= 70

d)  55 - [ 49 - ( 2 3 . 17 - 2 3 . 14 ) ]

= 55 - 49 - 2 3 . 3

= 55- ( 49 - 24)

= 30

Bạn ơi ở chỗ trước số 200 có dấu này [mà

Phần b/

a) {132 – [116 – (16 – 8)]:2}.5

= [132 – (116 – 8): 2] .5

= (132 – 108 : 2). 5

= (132 –54).5

= 78.5 = 390

b) 36: {136 : 200 – (12+ 8. 20)]}

= 36: {336 : [200 – ( 12 + 160)]}

= 36 : [336 : ( 200 – 172)

= 36 : ( 336 : 28)

= 36 : 12 = 3

c) 86 – [15. (64 - 39): 75+11]

= 86 – (15.25 : 75 + 11)

= 86 – ( 5 + 11)

= 70.

d) 55 – [49 – (2³ . 17 – 2³.14)]

= 55 – (49 – 2³ .3)

= 55 – ( 49 – 24)

= 30

b) 7³.9+ 3².7⁴- 45.539

=343.9+9.2401-45.539

=9.(343+2401)-45.539

=9.2744-24355

=24696-24355

=341

a) 132- (116-(132-128²))

=132- ( 116-(132-16384))

=132-(116+16252)

=132-16368

=16236

Giải;

1) \(347.222-222.\left(216+184\right):8\) 

\(=347.222-222.400:8\) 

\(=347.222-222.50\) 

\(=222.\left(347-50\right)\) 

\(=222.297\)

\(=65934\) 

2) \(132-\left[116-\left(132-128\right).22\right]\) 

\(=132-\left[116-4.22\right]\) 

\(=132-\left[116-88\right]\) 

\(=132-28\) 

\(=104\) 

3) \(16:\left\{400:\left[200-\left(37+46.3\right)\right]\right\}\) 

\(=16:\left\{400:\left[200-\left(37+138\right)\right]\right\}\) 

\(=16:\left\{400:\left[200-175\right]\right\}\) 

\(=16:\left\{400:25\right\}\) 

\(=16:16\) 

\(=1\) 

4) \(\left\{184:\left[96-124:31\right]-2\right\}.3651\) 

\(=\left\{184:\left[96-4\right]-2\right\}.3651\) 

\(=\left\{184:92-2\right\}.3651\) 

\(=\left\{2-2\right\}.3651\) 

\(=0.3651\) 

\(=0\) 

5) \(46-\left[\left(16+71.4\right):15\right]-2\) 

\(=46-\left[\left(16+284\right):15\right]-2\) 

\(=46-\left[300:15\right]-2\)

 \(=46-20-2\) 

\(=24\)

6) \(3^3.18+72.4^2-41.18\) 

\(=18.\left(27-41\right)+72.16\) 

\(=18.-14+1152\) 

\(=-252+1152\) 

\(=900\)

Giải: (tiếp)

7) \(\left(56.46-25.23\right):23\) 

\(=\left(2576-575\right):23\) 

\(=2001:23\) 

\(=87\) 

8) \(\left(28.54+56.36\right):21:2\) 

\(=\left(1512+2016\right):21:2\) 

\(=3528:21:2\) 

\(=84\) 

9) \(\left(76.34-19.64\right):\left(38.9\right)\) 

\(=\left(2584-1216\right):342\) 

\(=1368:342\) 

\(=4\) 

10) \(\left(2+4+6+...+100\right).\left(36.333-108.111\right)\) 

\(=\left(2+4+6+...+100\right).\left(11988-11988\right)\) 

\(=\left(2+4+6+...+100\right).0\) 

\(=0\) 

11) \(\left(5.4^{11}-3.16^5\right):4^{10}\) 

\(=5.4^{11}:4^{10}-3.16^5:4^{10}\) 

\(=5.4-3.1\) 

\(=20-3\) 

\(=17\) 

12) \(7256.4375-725:3650+4375.7255\) 

\(=4375.\left(7256+7255\right)-\dfrac{29}{146}\) 

\(=4375.14511-\dfrac{29}{146}\) 

\(=63485624,8\) 

Câu 12 ko chắc!

\(132+[116-\left(132-128\right)^2]\)

\(=132+[116-4^2]\)

\(=132+[116-16]\)

\(=132+100\)

\(=232\)

a) 2,448 : ( 0,6x1,7 ) 

=2,448 : 1,02

= 2,4

a)= 2,448 : 1,02

   = 2,4

b)=3,06 : 0,75

  =4,08

c) =53,9 :4 +22,8*2

    =13,475 + 22,8*2

    =13,475+ 45,6

 d) =21,56 : 9,8- 0,354 : 2

     = 2,2 - 0,177

     =2,023

e) =332-116-4

   =216-4

   =212

f) =16*400:200-(37+138):35

   =16*400:200-175:35

   =6400:200-175:35

   =32-5

   =27

g)=184:(96-4)+2*3561

   =184:92+2*3561

   =2+7122

   =7124

h)=146-(16+284):15-2*25

   =146-300:15-2*25

   =146-20-50

   =126-50

   =76

Nhớ k cho mình nha!🤗😘😘😘

\(A=\frac{1}{30}+\frac{1}{42}+....+\frac{1}{110}+\frac{1}{132}\)

\(A=\frac{1}{5.6}+\frac{1}{6.7}+....+\frac{1}{10.11}+\frac{1}{11.12}\)

\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+....+\frac{1}{11}-\frac{1}{12}\)

\(A=\frac{1}{5}-\frac{1}{12}=\frac{7}{60}\)

Hình như bn ghi sai đề mk sửa cho

Ta có:\(A=\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{100}+\frac{1}{132}\)

\(\Leftrightarrow A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}+\frac{1}{11.12}\)

\(\Leftrightarrow A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+....+\frac{1}{11}-\frac{1}{12}\)

\(\Leftrightarrow A=\frac{1}{5}-\frac{1}{12}\)

\(\Leftrightarrow A=\frac{7}{60}\)