tim x biet:
3^( x + 2 ) - 3^x = 24!
Tim so nguyen x biet : x+(x+1)+(x+2)+(x+3)+........+23+24=0
Tao không biết và tao cũng chẳng quan tâm
tim x,y thuoc Z biet -3/6=x/-2=-18/y=3/24
ta có : \(\dfrac{-3}{6}=\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{3}{24}\)
\(\Rightarrow\dfrac{-3}{6}=\dfrac{3}{24}\) (vô lí)
\(\Rightarrow\) đề sai
tim x biet 1- (5/3/8 + x - 7/5/24 ) / 16/2/3 =0
Tim so nguyen x, biet :
a/ -24 + (x + 4)^4 = 10^3
b/ 2.(x + 7) - 3.(6 - x) = -24
c/ 3x - 6x^2 = 0
a/
\(-24+\left(x+4\right)^4=10^3\)3
\(\Leftrightarrow-24+x^4+16x^3+96x^2+256x+256=10^3\)
<=>\(x^4+16x^3+96x^2+256x-768=0\)
Giải trên tập số phức ta được
\(x=-\sqrt{32}-4\)
\(x=\sqrt{32}-4\)
\(x=-\sqrt{32}i-4\)
\(x=\sqrt{32}1-4\)=> Phần a kog có giá trị nguyên nào của x thỏa mãn phương trình
b/
2(x+7)-3(6-x)=-24
<=> 2x+14-18+3x=-24
<=>5x=-20
<=>x=-4
Vậy x=-4
c/
\(3x-6x^2=0\)
\(\Leftrightarrow3x\left(1-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x=0\\1-2x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{2}\end{cases}}\)(x = 1/2 kog thỏa mãn yêu cầu)
Vậy x=0
a/\(\left(x+4\right)^4=1000+24\)
\(\Rightarrow x^4+8x^2+4^4-1024=0\)
\(\Rightarrow x^4+8x^2-768\)
\(\Rightarrow x^4-24x+32x-768=0\)
\(\Rightarrow x.\left(x-24\right)+32.\left(x-24\right)\)
\(\Rightarrow\left(x+32\right).\left(x-24\right)\Rightarrow\orbr{\begin{cases}x=-32\\x=24\end{cases}}\)
b/2x+14-18+3x=-24
5x=-24-14+18
x=-20/5=-4
c/3x-6x\(^2\) =0
\(3x.\left(1-2x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x=0\rightarrow x=0\\1-2x=0\rightarrow x=\frac{1}{2}\end{cases}}\)
KL bAN tu lam nhe
ban HA sai hang đang thưc rôi \(\left[\left(x+4\right)^2\right]^2\) khai triên ra nhu binh thuong
tim x,y thuoc z biet
-24/-6 = x/3 = 4/y^2 = z^3/-2
tim x,biet: 435 + 24 : x = 500 - 65 + 24 : 3
435+24:x = 500 - 65 + 24:3
435+24:x = 435+24:3
=> 24:x= 24:3 (vì chung số hạng 435)
=> x = 3
Theo đề bài ta thấy:
435+24:x=500-65+24:3
Mà 435=500-65 nên chỉ còn 24:x=24:3
\(\Rightarrow\)X=3
tim x biet: x + x/3=24
x+x/3 =24
x/1+x/3=24
3x+x/3=24
4x/3=24
4x=24.3
4x=72
x=72/4
x=18
\(+\frac{x}{3}=24\)
\(=>x+x.\frac{1}{3}\)\(=24\)
\(=>x.1+x.\frac{1}{3}=24\)
\(=>x.\left(1+\frac{1}{3}\right)=24\)
\(=>x.\frac{4}{3}\)\(=24\)
\(=>x=24:\frac{4}{3}\)
\(=>x=24.\frac{4}{3}\)
\(=>x=18\)
tim so nguyen x biet:
1/2-(1/3+3/4)< x < 1/24-(1/8-1/3)
\(\frac{1}{2}-\left(\frac{1}{3}+\frac{3}{4}\right)\le x\le\frac{1}{24}-\left(\frac{1}{8}-\frac{1}{3}\right)\)
\(\Rightarrow\frac{1}{2}-\frac{1}{3}-\frac{3}{4}\le x\le\frac{1}{24}-\frac{1}{8}-\frac{1}{3}\)
\(\Rightarrow\frac{6-4-3}{12}\le x\le\frac{1-3-8}{24}\)
\(\Rightarrow\frac{-1}{12}\le x\le\frac{-10}{24}\)
\(\Rightarrow\frac{-2}{24}\le x\le\frac{-10}{24}\)
\(\Rightarrow-2\le x\le-10\)
\(\Rightarrow x\in\left\{-3;-4;-5;......;-10\right\}\)