\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-2^2.2^{27}.3^{20}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)

sao bạn ra thế khó hỉu nhỉ

Mk cũng chẳng hỉu

=\(\frac{5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}}{5\cdot2^9\cdot\left(2\cdot3\right)^{19}-7\cdot2^{29}\cdot3^{18}}\)=\(\frac{5\cdot2^{30}\cdot3^{18}-3^{20}\cdot2^{29}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)=\(\frac{2^{29}\cdot3^{18}\cdot\left(5\cdot2-3^2\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}\)=2

f

\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)

\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)

\(=\frac{2.\left(5.2-3^2\right)}{5.3-7.2}=\frac{2.\left(5.2-3^2\right)}{15-14}=2.\left(5.2-3^2\right)\)

5.415.99−4.320.895.29.619−7.229.276 

=5.(22)15.(32)9−22.320.(23)95.29.(2.3)19−7.229.(33)6 

=5.230.318−229.3205.228.319−7.229.318 

=229.318.(5.2−32)228.318.(5.3−7.2) 

=2.(5.2−32)5.3−7.2 =2.(5.2−32)15−14 =2.(5.2−32)

= 2 nha bn

cho mik nha

thanks

Viết lại rõ ràng đi khó hiểu quá

nek cậu:

A=5.4¹⁵.9⁹-4.3²⁰.8⁹và B=5.2⁹.6¹⁹-7.2²⁹.27⁶

Tính A,B

Các bn giúp mk vs, mk cần gấp lắm

\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)

\(=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}\)

\(=\frac{2^{29}}{2^{28}}\)

\(=2^1=2\)

Vậy \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=2\)