chép nhầm đề. Làm lại:

\(C=\frac{\left(3.4.2^4\right)^2}{5.2^5.4^2-16^2}=\frac{3^2.2^4.2^8}{5.2^5.2^4-2^8}=\frac{9.2^{12}}{5.2^9-2^8}=\frac{9.2^{12}}{2^8.\left(5.2-1\right)}=\frac{9.2^4}{9}=\frac{2^4}{1}=2^4=16\)

Gấp lắm thì làm vậy

\(C=\frac{\left(3.4.2^2\right)^2}{5.2^5.4^2-16^2}=\frac{3^2.2^4.2^4}{5.2^5.2^4-2^8}=\frac{3^2.2^8}{5.2^9-2^8}=\frac{3^2.2^8}{2^8.\left(5.2-1\right)}=\frac{9}{9}=1\)

\(\frac{\left(3.4.2^4\right)^2}{5.2^5.4^2-16^2}\)

\(=\frac{\left(3.2^2.2^4\right)^2}{5.2^5\left(2^2\right)^2-\left(2^4\right)^2}\)

\(=\frac{\left(3.2^6\right)^2}{5.2^9-2^8}\)

\(=\frac{3^2.2^{12}}{2^8\left(5.2-1\right)}\)

\(=\frac{9.2^4}{9}\)

\(=16\)

\(=\frac{3^2.2^4.2^8}{5.2^5.2^4-2^8}\)

\(=\frac{3^22^{12}}{2^8\left(5.2-1\right)}\)\(=2^4\)

\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}+7.2^{29}.3^{18}}\)

\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}+7.2^{29}.3^{18}}\)

\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3+7.2\right)}\)

\(=\frac{2}{29}\)

ta có: 4^7.2^8 / 3.2^15.16^2 - 5.2^2.(2^10)^2

      = 2^14.2^8 / 3.2^15.2^8 - 5.2^2.2^20

      = 2^22 / 6.2^22 - 5.2^22

      = 2^22 / 2^22 ( 6 - 5 )

      = 1

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ai nhanh nhất mà trả lời dúng mik tặng 3 k