ko biết

M+N=(3/2x6-7x+4x^5+2,5x^2)+(-3x^6+1/2^5-13/2x^2+4x)

M+N=3/2x6-7x+4x^5+2,5x^2+-3x^6+1/2^5-13/2x^2+4x

= (3/2x^6-3x^6)+(7x+4x)+(4x^5+1/2^5)+(2,5x^2-13/2x^2)

=-1,5x^6+11x+4,5x^5-4x^2

M-N=(3/2^6-7x+4x^5+2,5x^2)-(-3x^6+1/2^5-13/2x^2+4x)

=3/2^6-7x+4x^5+2,5x^2+3x^6-1/2^5+13/2x^2-4x

= (3/2x^6+3x^6)+(-7x-4x)+(4x^5-1/2^5)+(2,5x^2+13/2x^2)

= 4,5x^6-11x+3,5x^5+9x^2

N-M=(-3x^6+1/2^5-13/2x^2+4x)-(3/2^6-7x+4x^5+2,5x^2)

= -3x^6+1/2^5-13/2x^2+4x-3/2^6-7x-4x^5-2,5x^2

= (-3x^6-3/2x^6)+(1/2x^5-4x^5)+(-13/2x^2-2,5x^2)+(4x-7x)

= -4,5x^6-3,5x^5-9x^2-3x

vậy câu hỏi là gì?

x^3+3x^2+6x+4

b \(\Leftrightarrow x^3\left(x-2\right)+10x\left(x-2\right)=0\)

\(\Leftrightarrow x\left(x-2\right)=0\)

hay \(x\in\left\{0;2\right\}\)

c: \(\Leftrightarrow\left(2x-3-x-5\right)\left(2x-3+x+5\right)=0\)

=>(x-8)(3x+2)=0

=>x=8 hoặc x=-2/3

d: \(\Leftrightarrow x^2\left(x-1\right)-4\left(x-1\right)^2=0\)

\(\Leftrightarrow\left(x-1\right)\left(x^2-4x+4\right)=0\)

=>x=2 hoặc x=1

e: \(\Leftrightarrow x\left(x^2-11x+30\right)=0\)

=>x(x-5)(x-6)=0

hay \(x\in\left\{0;5;6\right\}\)

b: \(\Leftrightarrow x\left(x^3-2x^2+10x-20\right)=0\)

\(\Leftrightarrow x\left(x-2\right)=0\)

hay \(x\in\left\{0;2\right\}\)

c: \(\Leftrightarrow\left(2x-3-x-5\right)\left(2x-3+x+5\right)=0\)

=>(x-8)(3x+2)=0

hay \(x\in\left\{8;-\dfrac{2}{3}\right\}\)

d: \(\Leftrightarrow x^2\left(x-1\right)-4\left(x-1\right)^2=0\)

\(\Leftrightarrow\left(x-1\right)\left(x^2-4x+4\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x-2\right)^2=0\)

=>x=1 hoặc x=2

bấm máy tính là ra đó :VV

b, x mũ 2 + 4x + 3 = ( x+ 1 ) ( x + 3 )

a) = x² + 3x + x + 3 = x( x + 3 ) + ( x + 3 ) = ( x + 3 )( x + 1 )

b) = x² - 3x - 5x + 15 = x( x - 3 ) - 5( x - 3 ) = ( x - 3 )( x - 5 )

c) = x² - 2x + 4x - 8 = x( x - 2 ) + 4( x - 2 ) = ( x - 2 )( x + 4 )

d) = x² - 4x + 3x - 12 = x( x - 4 ) + 3( x - 4 ) = ( x - 4 )( x + 3 )

e) = 4x² - 2x + 6x - 3 = 2x( 2x - 1 ) + 3( 2x - 1 ) = ( 2x - 1 )( 2x + 3 )

ko có biết