\(\left|x-\frac{1}{3}+\frac{4}{5}\right|=\left|-3,2+\frac{2}{5}\right|\)

\(\Rightarrow x-\frac{1}{3}+\frac{4}{5}=-3,2+\frac{2}{5}\)

\(\Rightarrow x-\frac{1}{3}+\frac{4}{5}=-\frac{14}{5}\)

\(\Rightarrow x-\frac{1}{3}=-\frac{14}{5}-\frac{4}{5}\)

\(\Rightarrow x-\frac{1}{3}=-\frac{18}{5}\)

\(\Rightarrow x=\frac{-49}{15}\)

Lời giải:

$|x-\frac{1}{3}|=|2-3x|$

$\Leftrightarrow x-\frac{1}{3}=2-3x$ hoặc $x-\frac{1}{3}=3x-2$

$\Leftrightarrow x=\frac{7}{12}$ hoặc $x=\frac{5}{6}$