\(2.3^x=162\)

\(3^x=162:2\)

\(3^x=81\)

\(\Rightarrow x=4\)

Vậy x = 4

theo đề bài ta có : 

2.3^x = 162 

3^x = 162 :2 

3^x    = 81

3^x    = 3⁴

x = 4

\(2.3^x=162\)

\(3^x=162:2\)

\(3^x=81\)

\(3^x=3^4\)

Vậy x=4

2.3^x=162

=>3^x=84

   3x =3⁴

=>x=4

=> 3^x = 81 = 2⁴

x = 4

2.3^x =162

3^x=162:2

3^x=81

=>81=3^3

X=3

a, 3^x=162:2

     3^x=81

     3^x=3⁴

      =>x=4

b, 2^x=17+15

    2^x=32

    2^x=2⁵

=> x=5

a, 2.3^x=162

<=>3^x=81

<=>3^x=3^4

=>x=4

b, 2^x-15=17

<=>2^x=32

<=>2^x=2^5

=>x=5

a. =>3^x= 81

 => 3^x= 3^4 => x=4

b. => 2^x= 2

=> 2^x= 2^1 => x= 1

Ko có x Làm sao mà tìm x đc

2.3^x=162

3^x=162:2

3^x=81

3^x=3⁴

=>x=4

2^x-15=17

2^x=17+15

2^x=32

2^x=2⁵

=>x=5

(7x-11)³=2⁵.5²+200

(7x-11)³=1000

(7x-11)³=10³

7x-11=10

7x=10+11

7x=21

x=21:7

x=3

\(a)2.3^x=162\)

\(3^x=81\)

\(3^x=3^4\)

\(\Rightarrow x=4\)

lam ho to cac cau o duoi voi thanks ban nhieu 

\(x^{20}=x\)

\(\Rightarrow x^{20}-x=0\)

\(x\left(x^{19}-1\right)=0\)

\(\Rightarrow\hept{\begin{cases}x=0\\x^{19}-1=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=0\\x^{19}=1\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=0\\x=1\end{cases}}\)

a, 3^x=162:2

3^x=81

Vì 81=3x3x3x3

=> x=4

b, 2^x-15=17

2^x=17+15

2^x=32

32=2x2x2x2x2

=> x=5

c, x^2=100 Mà 100=10x10

=> x=10

d, x^3=64

Vì 64=4x4x4

=> x=4