\(2222^{5555}=2^{5555}.1111^{5555}=\left(2^5\right)^{1111}.1111^{5555}=32^{1111}.1111^{5555}\)

\(5555^{2222}=5^{2222}.1111^{2222}=\left(5^2\right)^{1111}.1111^{2222}=25^{1111}.1111^{2222}\)

\(32^{1111}.1111^{5555}>25^{1111}.1111^{2222}\Rightarrow2222^{5555}>5555^{2222}\)

vậy \(2222^{5555}>5555^{2222}\)

Trang Đỗ sai  ruj

\(2222^{5555}=2222^{5.11}=\left(2222^5\right)^{1111}\)

\(5555^{2222}=5555^{2.1111}=\left(5555^2\right)^{1111}\)

Để 

So sánh : 2222^5555 và 5555^2222 ta cần so sánh 2222^5 và 5555^2

\(2222^5=2^5.1111^5=32.1111^5\)

\(5555^2=5^2.1111^2=25.1111^2\)

Vì \(32>25;1111^5>1111^2\Rightarrow32.1111^5>25.1111^2\Rightarrow2222^5>5555^2\Rightarrow2222^{5555}>5555^{2222}\)

chtt

http://olm.vn/hoi-dap/question/24563.html

\(2^{5555}=\left(2^5\right)^{1111}=32^{1111}\)

\(5^{2222}=\left(5^2\right)^{1111}=25^{1111}\)

vì \(32^{1111}>25^{1111}\) nên \(2^{5555}>5^{2222}\)

Ta có:\(2^{5555}=\left(2^5\right)^{1111}=32^{1111}\)

\(5^{2222}=\left(5^2\right)^{1111}=25^{1111}\)

Vì 25<32 nên 25¹¹¹¹<32¹¹¹¹

Vậy 5²²²²<2⁵⁵⁵⁵

2⁵⁵⁵⁵và 5²²²²

(2⁵)¹¹¹¹=32¹¹¹¹

(5²)¹¹¹¹=25¹¹¹¹

Vậy 2⁵⁵⁵⁵>5²²²²

vì \(2^5>5^2\) nên \(2^{5555}>5^{2222}\)

tk mình nha

a)

\(5^{2222}=\left(5^2\right)^{1111}=25^{1111}\)

\(2^{5555}=\left(2^5\right)^{1111}=32^{1111}\)

=> tự kết luận

b)

ĐỀ ?????

a)  \(5^{2222}=5^{2.1111}=25^{1111}\)

      \(2^{5555}=2^{5.1111}=32^{1111}\)

Do  \(25^{1111}< 32^{1111}\)nên    \(5^{2222}< 2^{5555}\)

b)  \(4a=3b\)=>   \(\frac{a}{3}=\frac{b}{4}\)

Áp dụng t.c dãy tỉ số bằng nhau ta có:

\(\frac{a}{3}=\frac{b}{4}=\frac{a+b}{3+4}=\frac{21}{7}=3\)

suy ra:  \(\frac{a}{3}=3\)=>  \(a=9\)

             \(\frac{b}{4}=3\)=>   \(b=21\)

Vậy....

Đề của câu b là tìm a và b nha bonking

Ta có :

5²²²² = (5²)¹¹¹¹ = 25¹¹¹¹

2⁵⁵⁵⁵ = (2⁵)¹¹¹¹ = 32¹¹¹¹

Vì 32¹¹¹¹ > 25¹¹¹¹ nên 2⁵⁵⁵⁵ > 5²²²²

8¹⁵ và 64¹⁰

64¹⁰=(8²)¹⁰=8²⁰

vì 8¹⁵<8²⁰nên 8¹⁵<64¹⁰

2222⁵⁵⁵và 5555²²²

2222⁵⁵⁵=(2.1111)⁵⁵⁵=2⁵⁵⁵.1111⁵⁵⁵⁵=(2⁵)¹¹¹.(1111⁵)¹¹¹=32¹¹¹.(1111⁵)¹¹¹

5555²²²=(5.1111)²²²=5²²².1111²²²=(5²)¹¹¹.(1111²)¹¹¹=25¹¹¹.(1111²)¹¹¹

vì 32¹¹¹> 25¹¹¹ và (1111⁵)¹¹¹ > (1111²)¹¹¹ => 32¹¹¹.(1111⁵)¹¹¹ > 25¹¹¹.(1111²)¹¹¹

nên 2222⁵⁵⁵ > 5555²²²

2222⁵⁵⁵ và 5555²²²

2222⁵⁵⁵ = (2.1111)⁵⁵⁵ = 2⁵⁵⁵.1111⁵⁵⁵⁵ = (2⁵)¹¹¹. (1111⁵)¹¹¹ = 32¹¹¹. (1111⁵)¹¹¹

5555²²² = (5.1111)²²² =5²²².1111²²² = (5²)¹¹¹. (1111²)¹¹¹ = 25¹¹¹. (1111²)¹¹¹

Ta có Vì 32¹¹¹> 25¹¹¹ và (1111⁵)¹¹¹ > (1111²)¹¹¹ => 32¹¹¹.(1111⁵)¹¹¹ > 25¹¹¹.(1111²)¹¹¹

Nên => 2222⁵⁵⁵ > 5555²²²

Ta có 

33⁴⁴=(3.11)⁴⁴=3⁴⁴.11⁴⁴=(3⁴)¹¹.11⁴⁴=81¹¹.11⁴⁴

44³³=(4.11)³³=4³³.11³³=(4³)¹¹.11³³=64¹¹.11³³

=> 33⁴⁴>44³³

KL:

b) 5²²²²=(5²)¹¹¹¹=25¹¹¹¹

2⁵⁵⁵⁵=(2⁵)¹¹¹¹=32¹¹¹¹

=> 5²²²²<2⁵⁵⁵⁵

KL