240-[23+(13+24.3-x)]=132

240-[23+(13+168-x)]=132

240-[23+(181-x)]=132

|

x-8:4-(46-23.2+6.3)=0

\(x-8:4-\left(46-23.2+6.3\right)=0\)

\(x-2-\left(46-46+18\right)=0\)

\(x-2-18=0\)

\(x-2=0+18\)

\(x-2=18\)

\(x=18+2\)

\(x=20\)

\(240-\left[23+\left(13+24.3-x\right)\right]=132\)

\(240\left[23+\left(13+82-x\right)\right]=132\)

\(23+\left(95-x\right)=132:240\)

\(23+\left(95-x\right)=\frac{132}{240}=\frac{11}{30}\)

\(23+\left(95-x\right)=\frac{11}{30}\)

\(95-x=\frac{11}{30}-23\)

\(95-x=\frac{11}{30}-\frac{690}{30}\)

\(95-x=-\frac{679}{30}\)

\(x=95+\frac{679}{30}\)

\(x=\frac{2850}{30}+\frac{679}{30}\)

\(x=\frac{3529}{30}=\)tự rút gọn ( nếu có thể )

240 - [ 23 + ( 13 + 24 . 3 - x ) ] = 132

240 - [ 23 + 13 + 72 - x ] = 132

240 - 23 - 13 - 72 + x = 132

132 + x = 132

x = 132 - 132

x = 0

Vậy x = 0

=))

\(240-\left[23+\left(13+24.3-x\right)\right]=132\)

\(23+\left(13+24.3-x\right)=240-132\)

\(23+\left(13+24.3-x\right)=108\)

\(13+24.3-x=108-23\)

\(13+24.3-x=85\)

\(24.3-x=85-13\)

\(24.3-x=72\)

\(72-x=72\)

\(x=72-72\)

\(x=0\)

Đáp án cần chọn là: C

\(\dfrac{-19}{23}\cdot\dfrac{13}{14}+\dfrac{13}{14}\cdot\dfrac{-15}{23}-\dfrac{13}{14}\cdot\dfrac{1}{23}\\ =\dfrac{13}{14}\cdot\left(\dfrac{-19}{23}+\dfrac{-15}{23}-\dfrac{1}{23}\right)\\ =\dfrac{13}{14}\cdot\dfrac{-35}{23}=\dfrac{-65}{46}\)

18 * 23 +3 +45 * 6 +9 * 32 *2 =1263

425 *7*4 - 170 *60=1700 

132 *9 +132 =1320

( 56* 27 +56 +35 ):62=\(\frac{1603}{62}\) 

39 * ( 250 +87) +61 * ( 240 +97)=33700

Hk tốt!!! k cho mình nha!!@@

bạn có chép sai đề câu 1 không z

132 x 9 + 132 = 132x(9+1) = 132 x 10 = 1320