Toán tiếng anh: If the length of a leg of a right angle is 11 and the lengths of the other two side are both positive integers, then the perimeter of a triangle is.............
Những câu hỏi liên quan
1.Find the greatest negative integer value for n so that:
n4 - 25n2 - 70n - 49
2.Toán tiếng anh: If the length of a leg of a right angle is 11 and the lengths of the other two side are both positive integers, then the perimeter of a triangle is.............
The lengths in cm of three sides of a triangle are three consecutive odd numbers. Knowing that the perimeter of the triangle is 39cm, find the length of the longest side of the triangle. Show your work.
The lengths of three sides of a triangle are all primes, and the perimeter of the triangle is 17. Find the sum of all possible value(s) of the second longest side.
The lengths in cm of three sides of a triangle are three consecutive odd numbers.
Knowing that the perimeter of the triangle is 40.5 dm, find the length of the longest side of the
triangle.
A.137cm
B.135cm
C.143cm
D.145cm
40.5dm = 405cm
The length of each side averages to : 405 / 3 = 135 ( cm )
The length of the longest side of the triangle is : 135 + 2 = 137 ( cm )
The answer is A.137cm.
Câu hỏi tiếng ANH :
If the sum of all the digits in each of two consecutive positive integers are both exactlt multiple of 5. Then what is the least sum of these two integers ?
A. 99 B. 999 C. 9999 D. 99999
Bản dịch này bn, còn giải thì bn tự tính nha!
"Nếu tổng của tất cả các chữ số trong mỗi hai số nguyên dương liên tiếp là cả hai chính xác nhiều của 5. Sau đó, tổng hợp ít nhất của hai số nguyên là gì?"
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The lengths of three sides of a triangle are all primes, and the perimeter of the triangle is 4343. Find the sum of all possible value(s) of the longest side.
Given a square with the length of one side is 8 cm and a isosceles triangle with the length of its base is 12 cm. If the area of the square is equal to the area of the isosceles triangle then what is the length of the height of the isosceles triangle, in cm?
Let ABC be a triangle having the ratios of the length of the two side sharing the common vertex A as 2:3 . Let AM be the media and Ak be the angle bisector of the triangle. Find the ratio of the areas of the triangle AKM and the triangle AKB.
( Giải bằng tiếng anh )
On the supposition that AB<AC
AK be the angle bisector of the triangle
\(\Rightarrow\) \(\frac{KB}{KC}=\frac{AB}{AC}=\frac{2}{3}\)
\(\Rightarrow\frac{MB-MK}{MC+MK}=\frac{MC-MK}{MC+MK}=\frac{2}{3}\)
\(\Rightarrow3MC-3MK=2MC+2MK\)
\(\Rightarrow MC=5MK\)
\(\Rightarrow BK=MC-MK=5MK-MK=4MK\)
Let AH be the height of the triangle
\(\Rightarrow\frac{S_{AKM}}{S_{ABK}}=\frac{\frac{AH.KM}{2}}{\frac{BK.AH}{2}}=\frac{KM}{4KM}=\frac{1}{4}\)
If AB > AC then
\(\Rightarrow CM=5MK\)
\(\Rightarrow Bk=CM+MK=5MK+MK=6MK\)
\(\Rightarrow\frac{S_{AKM}}{S_{AKB}}=\frac{\frac{AH.MK}{2}}{\frac{AH.BK}{2}}=\frac{MK}{6MK}=\frac{1}{6}\)
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Given a square with the length of one side is 8cm and an isosceles triangle with the length of its base is 12 cm . If the area of the square equal of the area of the isosceles triangle then is the length of height of the isosceles triangle ?
M.n ơi kb vs mk nha ! Mk là thành viên ms nên chưa có bn !
Girl 2k5 -FA